a pyramid and a cone are both 10 centimeters tall and have the same volume what statement

The quadratic equation that has the roots 3 + i and 3 - i is x² - 6x + 10 = 0.

The general form of a quadratic equation is ax² + bx + c = 0, where a, b, and c are constants.

The roots of the quadratic equation are the values of x that make the equation equal to zero.

Therefore, if a quadratic equation has the roots 3 + i and 3 - i, it can be written in the factored form as (x - (3 + i))(x - (3 - i)) = 0. Expanding this product yields x² - (3 + i + 3 - i)x + (3 + i)(3 - i) = 0.

Simplifying this expression further results in the quadratic equation x² - 6x + 10 = 0.

The quadratic equation that has the roots 3 + i and 3 - i is x² - 6x + 10 = 0.

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The complete sentence is shown below:

Reason: Given

Reason: Angles forming a linear pair sum to 180° (Given)

Reason: Substitution from Statement 1.

To complete the proof that HJ GI, we can use the given statements and reasons:

Statement 1: <HKI = <GKH

Reason: Given

Statement 2: m<GKH + m<HKI = 180°

Reason: Angles forming a linear pair sum to 180° (Given)

Statement 3: m,GKH + m<GKH = 180°

Reason: Substitution from Statement 1

Statement 4: m<GKH = 90°

Reason: From Statement 2 and Statement 3, we can subtract m<GKH from both sides, which results in m<GKH = 180° - m<GKH.

Since the angles forming a linear pair sum to 180°, m<GKH + m<GKH = 180° implies that m<GKH = 90°.

Therefore, based on the given statements and reasons, we can conclude that HJ and GI are congruent (m<GKH = 90°)

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area of equilateral triangle =

[tex]( \sqrt{3 } \div 4) \times a {}^{2} [/tex]

(C) area = 84.9 in²

The area of the kite is 38 mm squared.

A kite is a quadrilateral with two pairs of adjacent sides equal. The diagonals of a kite are perpendicular. The vertex angle are bisected by the diagonals.

It has two pairs of consecutive equal sides and perpendicular diagonals.

Therefore,

area of a kite = ab / 2

where

Therefore,

a = 9.5 mm

b = 4 mm

Therefore,

area of a kite = 9.5 × 4 / 2

area of a kite = 38 / 2

area of a kite = 19 mm²

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Answer:

The area of the kite would be 19 mm².

Step-by-step explanation:

A kite is a quadrilateral with two pairs of equal-length adjacent sides. The diagonals of a kite are perpendicular to each other and intersect at a right angle, dividing the kite into four right triangles. The area of a kite can be calculated by finding the product of the lengths of its diagonals and dividing it by 2.

If we assume that the height and width you provided are the lengths of the diagonals, we can calculate the area using the following formula:

Area = (height * width) / 2

Substituting the given values:

Area = (9.5 mm * 4 mm) / 2

= 38 mm² / 2

= 19 mm²

Therefore, if the height and width represent the lengths of the diagonals, the area of the kite would be 19 square millimeters.

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Hello!

[tex]7p-13p+4-5p\\\\= 7p-13p-5p+4\\\\= -6p-5p+4\\\\\Large\boxed{= -11p + 4}[/tex]

The center of the circumscribed circle is (1, 5).

We calculate the midpoint and slope of the line segment AB:

Midpoint of AB = ((x₁ + x₂) / 2, (y₁ + y₂) / 2)

Midpoint of AB = ((2 + 0) / 2, (8 + 8) / 2)

Midpoint of AB = (1, 8)

Slope of AB = (y₂ - y₁) / (x₂ - x₁)

= (8 - 8) / (0 - 2)

Slope= 0

We can notice that the equation of the perpendicular bisector of AB is x = 1.

We also find midpoint and slope of the line segment  BC

Midpoint of BC = ((x₁ + x₂) / 2, (y₁ + y₂) / 2)

= ((0 + 2) / 2, (8 + 2) / 2)

= (1, 5)

Slope of BC = (y₂ - y₁) / (x₂ - x₁)

= (2 - 8) / (2 - 0)

= -3

y - 5 = -3(x - 1)

y - 5 = -3x + 3

3x + y = 8

we have the equations of two perpendicular bisectors which are

x = 1 and 3x + y = 8.

We Substitute x = 1 into 3x + y = 8:

3(1) + y = 8

3 + y = 8

y = 5

In conclusion, center of the circumscribed circle is (1, 5).

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2.63 is the value or quotient of 616/265 using long division.

We have to find the value of 616/265

In the given division the numerator is a dividend and the number in the denominator is a divisor.

616 is the dividend and 265 is the divisor.

When we perform long division the quotient will be 2.63 which is the require value.

       2.63  

____________

265 | 616

-530

______

860

-795

______

650

-530

______

120

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Sin 40° = x/16

0.6428 = x/16

x = 0.643 × 16

x = 10.2848

x = 10.28

So, the value of x is 10.28 (C)

That's it :)

In the year 2000, it was estimate that the population of the world was 6, 082, 966, 429 people.

Based on data provided by the table give, the global population in the year 2000 was estimated to be around 6, 082, 966, 429 individuals. This remarkable figure, serving as a testament to the expansive tapestry of humanity, reflects the vastness and intricacy of our interconnected world during that period.

Within the context of demographic analysis, the United Nations diligently compiled and analyzed extensive data to derive this population estimate for statistical reasons.

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The full question is:

In the year 2000 the world population was

Step-by-step explanation:

1 qt = 2 pts     multiply both sides by two

2 qt = 4 pints

The area of the required shaded portion is 123 ft²

Given is figure having some shaded portion we need to find the area of the same,

So, the shaded portion is two right isosceles triangles with equal side measuring 14 ft and 7 ft,

So, to find the same, we will calculate the area of the triangles and add them,

Area of a triangle = 1/2 x base x height

Area of the shaded portion = 1/2 x 7 x 7 + 1/2 x 14 x 14

= 122.5 ft²

≈ 123 ft²

Hence the area of the required shaded portion is 123 ft²

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In order to expand the properties of logarithms log981x:

log981x = log98 + log1x

One must know that loga + logb = log(ab), and loga + logb = log(ab) may also be represented as loga(b) or logab.

Using this property, we can simplify the expression further:

log981x = log98 + log1x = log9 + log8 + log1 + logx

We know that log9 = 2 and log1 = 0, so we can simplify even further:

log981x = log9 + log8 + log1 + logx = 2 + log8 + 0 + logx = 2 + log8x.

Therefore, the expanded value would be log981x to 2 + log8x.

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The nearest Whole number, the missing dimension (height) of the cylinder is approximately 39 inches.

The missing dimension of the cylinder, we can use the formula for the volume of a cylinder:

Volume = π * r^2 * h

Given that the volume is 10,000π in³ and the diameter of the base is 32 inches, we can determine the radius (r) of the cylinder.

The diameter is twice the radius, so the radius is half of the diameter:

r = 32 inches / 2 = 16 inches

Substituting the known values into the volume formula, we have:

10,000π in³ = π * (16 in)^2 * h

Cancelling out the common factor of π, we get:

10,000 = 16^2 * h

Simplifying further:

10,000 = 256 * h

To isolate h, we divide both sides of the equation by 256:

h = 10,000 / 256

Calculating the value of h:

h ≈ 39.06

Rounded to the nearest whole number, the missing dimension (height) of the cylinder is approximately 39 inches.

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The angle ABC in the circle is 70 degrees.

The intercepted arc is the arc that is inside the inscribed angle and whose

endpoints are on the angle. The arc angle is half the the inscribed angle.

The intercepted arc that is formed is equal to the inscribed angle,

multiplied by two (intercepted arc measure = inscribed angle × 2).

Therefore, let's find the arc angle ABC as follows:

∠ ABC = 1  /2 (360 - 120 - 100)

∠ ABC = 1  /2 (360 - 220)

∠ ABC = 1  /2 (140)

Therefore,

∠ ABC = 70 degrees

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Answer:

There are 20 blue fish in the aquarium.

Step-by-step explanation:

If 60% of the fish are red than 40% are blue. That means that 20% fish is 10 fish. 20% = 10 fish. 40% = 20 fish.

The measure of angle C is 13°.

To find the measure of angle C in the given circle, we need to use the properties of angles subtended by arcs in a circle.

Given information:

m∠J = 88° (angle J)

mArc DF = 62° (arc DF)

mArc BD = 136° (arc BD)

We can start by using the fact that the measure of an angle formed by a chord and an arc is equal to half the measure of the intercepted arc.

Since mArc DF = 62°, the measure of angle DJF (angle formed by chord DF and arc DF) is 62°/2 = 31°.

Next, we can use the fact that angles subtended by the same arc are equal.

Since mArc BD = 136°, angle BJD (angle formed by chord BD and arc BD) is also 136°.

Now, let's find angle BCD (angle formed by chord BD and chord CD). The sum of angles in a triangle is 180°, so angle BCD = 180° - angle DJF - angle BJD.

Angle BCD = 180° - 31° - 136°

Angle BCD = 180° - 167°

Angle BCD = 13°

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Answer:

(2x + 3)(x - 5)

Step-by-step explanation:

2x² - 7x - 15

consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 × - 15 = - 30 and sum = - 7

the factors are - 10 and + 3

use these factors to split the x- term

2x² - 10x + 3x - 15 ( factor the first/second and third/fourth terms )

= 2x(x - 5) + 3(x - 5) ← factor out (x - 5) from each term

= (2x + 3)(x - 5) ← in factored form

Blank 1 is 3

Blank 2 is 5

Answer:

  (a)  0.75

Step-by-step explanation:

You want the 10th term of the geometric sequence with a1 = 384 and a7 = 6.

The equation for the n-th term can be written ...

  an = a1·b^(n-1)

Using a1 = 384, we can find b from ...

  a7 = 6 = 384·b^(7-1)

  (6/384)^(1/6) = b

Then the 10th term is ...

  a10 = 384·(6/384)^((10-1)/6) = 0.75

The 10th term of the sequence is 0.75.

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The value of x in arithmetic progression is 5/3 and the largest angle is 30.

The given sequence is: (2x-7), (x-1), 3x, x, (x+2), 30, 10.

In an arithmetic progression, the common difference (d) between consecutive terms remains constant.

The common difference between the terms = (x - 1) - (2x - 7) = x - 1 - 2x + 7 = 6 - x

6 - x = 3x - (x - 1)

6 - x = 3x - x + 1

6 - x = 2x + 1

-x - 2x = 1 - 6

-3x = -5

x = -5 / -3

x = 5/3

Therefore, the value of x is 5/3.

2x-7 = 2 ×5/3 -7 = -3.66

x-1 = 5/3-7 = -5.33

3x = 3 × 5/3 = 5

x + 2 = 5/3+2 =3.66

Thus, the largest angle is 30.

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Your question is incomplete, most probably the full answer is:

If (2x-7), (x-1), 3x, x, (x+2), 30 and 10 are in AP, then

1. Find the value of x

2. Find the value of the largest angle

Answer:

A = 22.62°

B = 67.38°

c = 26

Step-by-step explanation:

[tex]a^2+b^2=c^2\\10^2+24^2=c^2\\100+576=c^2\\676=c^2\\26=c[/tex]

[tex]\sin A=\frac{\text{Opposite}}{\text{Hypotenuse}}=\frac{10}{26}\\\\A=\sin^{-1}(\frac{10}{26})\\\\A\approx22.62^\circ[/tex]<-- You can also use other trig ratios

[tex]B=180^\circ-(90^\circ+22.62^\circ)=180^\circ-112.62^\circ=67.38^\circ[/tex]

There's no specific order in how to solve for A and B, so there may be more than one way to approach these solutions.

The value of x that makes the rational expression undefined is x = -3.

The rational expression is undefined when the denominator is equal to zero, because division by zero is undefined.

In the given rational expression (x - 3) / (3 + x), we need to find the value of x that makes the denominator (3 + x) equal to zero.

To find this value, we set the denominator equal to zero and solve for x:

3 + x = 0

Subtracting 3 from both sides:

x = -3

Therefore, the value of x that makes the rational expression undefined is x = -3.

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Answer:

D = 90 FT

Step-by-step explanation:

40 / d = 20 / 45

cross multiply

45 × 40 = 20d

1800 = 20d

divide both sides by 20

1800 / 20 = 20d / 20

d = 90 ft

Let's solve the inequality to determine the number of outfits Tariq can purchase while staying within his budget.

Given:

Amount Tariq has to spend: $640

Cost of a new bicycle: $291.24

Cost of 4 bicycle reflectors: $19.56 each

Cost of bike gloves: $16.52

Cost of each biking outfit: $50.80

Let's assume the number of outfits Tariq can purchase is represented by x.

The total cost of the items he has already purchased is:

Cost of bicycle = $291.24

Cost of 4 bicycle reflectors = $19.56 * 4 = $78.24

Cost of bike gloves = $16.52

The remaining amount Tariq has to spend can be calculated as:

Remaining amount = Total amount - (Cost of bicycle + Cost of reflectors + Cost of gloves)

Remaining amount = $640 - ($291.24 + $78.24 + $16.52)

Now, we need to determine the maximum number of outfits Tariq can purchase with the remaining amount. Each outfit costs $50.80.

Inequality: x * $50.80 ≤ Remaining amount

Substituting the values:

x * $50.80 ≤ $640 - ($291.24 + $78.24 + $16.52)

Simplifying further:

x * $50.80 ≤ $640 - $385

x * $50.80 ≤ $255

To solve for x, we divide both sides of the inequality by $50.80:

x ≤ $255 / $50.80

x ≤ 5

Therefore, the maximum number of outfits Tariq can purchase while staying within his budget is 5.

[tex] \begin{aligned}3 ^{3k} &= \frac{1}{81} \\3^{3k} &= \frac{1}{3^{4} } \\ 3^{ \blue{3k}} &= 3^{ - \blue{4}} \\ 3k&= - 4 \\ k&= \frac{ - 4}{3} \\ k&= \bold{ - \frac{4}{3} } \end{aligned}[/tex]

[tex]\rm{The\:value\:of\:\mathit{k}\:is\:\bold{ - \frac{4}{3}}} \\ \\ \small{ \blue{ \mathfrak{That's\:it\: :)}}}[/tex]

Beth and Kelly were on vacation for 6 days.

Let's assume that Beth and Kelly were on vacation for "x" days.

For Beth:

The cost per day for dog sitting at Rover Sleepover is $24.50.

Beth also paid a fee of $90.50 for food and cleaning.

So the total cost for Beth's dog sitting can be expressed as:

Total cost for Beth = (Cost per day × Number of days) + Cleaning fee

Total cost for Beth = ($24.50 × x) + $90.50

For Kelly:

The cost per day for dog sitting at Pet Palace is $32.

Kelly also paid a fee of $45.50 for cleaning.

So the total cost for Kelly's dog sitting can be expressed as:

Total cost for Kelly = (Cost per day × Number of days) + Cleaning fee

Total cost for Kelly = ($32 × x) + $45.50

Since both Beth and Kelly spent the same total amount of money, we can set up an equation:

($24.50 × x) + $90.50 = ($32 × x) + $45.50

Simplifying the equation, we get:

$24.50x + $90.50 = $32x + $45.50

Moving the variables to one side and constants to the other side:

$32x - $24.50x = $45.50 - $90.50

Combining like terms, we have:

$7.50x = $45

Dividing both sides of the equation by $7.50:

x = $45 / $7.50

x = 6

Therefore, Beth and Kelly were on vacation for 6 days.

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Answer:

13cm

Step-by-step explanation:

The area of a trapezoid is given by the formula:

Area = ½*(b1+b2)*h

where:

In this problem, we are given that b1 = 6 cm, b2 = 15 cm, and Area = 136.5 square centimeters.

Plugging these values into the formula, we get:

136.5 = ½*(6 + 15)*h

Solving for h, we get:

136.5=10.5h

h = 136.5/10.5=13centimeters

Therefore, the height of the trapezoid is 13 centimeters.

The surface area of the figure is approximately 997.5π cm².

We have,

The figure has two shapes:

Cone and a semicircle

Now,

The surface area of a cone:

= πr (r + l)

where r is the radius of the base and l is the slant height.

Given that

r = 15 cm and l = 19 cm, we can substitute these values into the formula:

= π(15)(15 + 19) = 885π cm² (rounded to the nearest whole number)

The surface area of a semicircle:

= (πr²) / 2

Given that r = 15 cm, we can substitute this value into the formula:

= (π(15)²) / 2

= 112.5π cm² (rounded to one decimal place)

The surface area of the figure:

To find the total surface area of the figure, we add the surface area of the cone and the surface area of the semicircle:

Now,

Total surface area

= 885π + 112.5π

= 997.5π cm² (rounded to one decimal place)

Therefore,

The surface area of the figure is approximately 997.5π cm².

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The solution to the equation 1/3a = -15 is a = -45

from the question, we have the following parameters that can be used in our computation:

1/3a = -15

Multiply 3 to both sides of the equation

so, we have the following representation

3 * 1/3a = -15 * 3

When the products are evalated, we have

a = -45

Hence, the solution to the equation is a = -45

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