Calculate the mass percent by
volume of 281.1 g of glucose
(C6H12O6, MM = 180.2 g/mol) in
325 mL of solution.

Answers

Answer 1

Answer:

Given:

Mass of glucose (m) = 281.1 g

Molar mass of glucose (MM) = 180.2 g/mol

Volume of solution (V) = 325 mL

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

V = 325 mL = 325/1000 L = 0.325 L

Next, we can calculate the mass of glucose in the solution using its molar mass and the given mass:

moles of glucose (n) = m / MM

n = 281.1 g / 180.2 g/mol

Now, we need to calculate the mass percent by volume:

mass percent by volume = (mass of glucose / mass of solution) x 100

mass of solution = mass of glucose

mass percent by volume = (mass of glucose / mass of solution) x 100

= (n x MM / V) x 100

Substituting the values:

mass percent by volume = ((281.1 g / 180.2 g/mol) x 180.2 g/mol) / 0.325 L) x 100

Calculating this expression will give us the mass percent by volume of glucose in the solution.


Related Questions

Water arrived on earth in the form of

Answers

Answer:

the water arrives on the earth in the form of water rich objects(planetesimals)

CHEM FINAL TOMORROW!!! Need some help with concentration stuff. If someone could tell me how this works it would be incredibly helpful!!

Answers

The boiling point of a solution is influenced by the presence of solute particles, which can cause a change in the boiling point compared to the pure solvent. This phenomenon is known as boiling point elevation.

The magnitude of boiling point elevation depends on the concentration of the solute and the nature of the solute particles. In general, the greater the concentration of solute particles, the greater the boiling point elevation.

Comparing a 0.5m sodium chloride (NaCl) solution to a 0.3m aluminum sulfate ([tex]Al_2(SO_4)_3[/tex]) solution, we can determine the relative boiling point elevation.

Sodium chloride (NaCl) dissociates into two ions in solution (Na+ and Cl-), while aluminum sulfate ([tex]Al_2(SO_4)_3[/tex])dissociates into three ions (2[tex]Al_3[/tex]+ and 3[tex]SO_4[/tex]2-). This means that the aluminum sulfate solution will have a greater concentration of solute particles per mole than the sodium chloride solution.

Therefore, the boiling point of the 0.5m sodium chloride solution will be lower than the boiling point of the 0.3m aluminum sulfate solution.

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Identify reactions types and balancing equations???

Answers

The following chemical equations must be balanced:

1. N2 + 3 H2 → 2 NH3

Type: Synthesis reaction

2. 2 KClO3 → 2 KCl + 3 O2

Type: Single Replacement reaction

3. 2 NaF + ZnCl2 → ZnF2 + 2 NaCl

Type- Decomposition reaction

4. 2 AlBr3 + 3 Ca(OH)2 → Al2(OH)6 + 6 CaBr2

Type- Double Replacement reaction

5. 2 H2 + O2 → 2 H2O

Type: Combustion reaction

6. 2 AgNO3 + MgCl2 → 2 AgCl + Mg(NO3)2

Type: Synthesis reaction

7. 2 Al + 6 HCl → 2 AlCl3 + 3 H2

Type: Decomposition reaction

8. C3H8 + 5 O2 → 3 CO2 + 4 H2O

Type: Combustion reaction

9. 2 FeCl3 + 6 NaOH → Fe2O3 + 6 NaCl + 3 H2O

Type: Double Replacement reaction

10. 4 P + 5 O2 → 2 P2O5

Type: Synthesis reaction

11. 2 Na + 2 H2O → 2 NaOH + H2

Type: Single Replacement reaction

12. 2 Ag2O → 4 Ag + O2

Type: Decomposition reaction

13. C6H12O6 + 6 O2 → 6 CO2 + 6 H2O

Type: Combustion reaction

14. 2 KBr + MgCl2 → 2 KCl + MgBr2

Type: Double Replacement reaction

15. 2 HNO3 + Ba(OH)2 → Ba(NO3)2 + 2 H2O

Type: Double Replacement reaction

16. C5H12 + 8 O2 → 5 CO2 + 6 H2O

Type: Combustion reaction

17. 4 Al + 3 O2 → 2 Al2O3

Type: Synthesis reaction

18. Fe2O3 + 2 Al → 2 Fe + Al2O3

Type: Single Replacement reaction

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some1 please help me with this problem

for reference: it’s speaking about 3H2 + N2 -> 2NH3 (ammonia)



Answers

Theoretically, if 20 grams of hydrogen reacts then 112.5 grams of ammonia is produced.

The balanced chemical equation can be given as:

N₂+3H₂→ 2NH₃

From stoichiometry, 2 mol of NH₃is produced from 3 mol of H₂

5 mol of NH₃ will be produced from = 3/2×5 = 7.5 mol of H₂

∴mass of H₂=7.5×2= 15gm of H₂.

Excess reagents are those reactants in a chemical reaction that are not exhausted at the end of the reaction. A completely exhausted or reacted reagent is called a limiting reagent because its amount limits the number of products formed. In this reaction, the excess reagent is Nitrogen as 35 grams of nitrogen and 15 grams of hydrogen react to produce 34 grams of ammonia.

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The system at equilibrium below is heated.
How does the system adjust to reestablish
equilibrium?
2SO₂(g) + O₂(g) ⇒ 2SO3(g) + 198 kJ

Answers

When the system described above, which involves the reaction of sulfur dioxide (SO₂) and oxygen (O₂) to form sulfur trioxide (SO₃) with the release of 198 kJ of heat, is heated, it disrupts the equilibrium. In response to the increase in temperature, the system will adjust in order to reestablish equilibrium. Here's what happens:

According to Le Chatelier's principle, when a system at equilibrium is subjected to a stress, it will shift in a way that counteracts that stress. In this case, heating the system adds energy to it, which can be viewed as a stress. To counteract the increase in temperature, the system will shift in the endothermic direction, absorbing some of the added heat.

The forward reaction, in which SO₂ and O₂ combine to form SO₃, is an exothermic process since heat is released. By Le Chatelier's principle, increasing the temperature will shift the equilibrium to the left, favoring the reverse reaction (the endothermic direction). This means that some of the SO₃ molecules will decompose back into SO₂ and O₂.

As the system adjusts to reestablish equilibrium, the concentrations of SO₂, O₂, and SO₃ will change. The concentrations of SO₂ and O₂ will increase, while the concentration of SO₃ will decrease. This shift occurs in an attempt to consume some of the excess heat and reduce the temperature back towards the original equilibrium.

Overall, heating the system disrupts the equilibrium, causing a shift towards the reverse reaction. This shift helps absorb the added heat and restore the system to equilibrium by altering the concentrations of reactants and products.

Identify reactions types and balancing equations

Answers

The following chemical equations must be balanced:

1. N2 + 3 H2 → 2 NH3

Type: Synthesis

2. 2 KClO3 → 2 KCl + 3 O2

Type: Single Replacement

3. 2 NaF + ZnCl2 → ZnF2 + 2 NaCl

Type- Decomposition

4. 2 AlBr3 + 3 Ca(OH)2 → Al2(OH)6 + 6 CaBr2

Type- Double Replacement

5. 2 H2 + O2 → 2 H2O

Type: Combustion

6. 2 AgNO3 + MgCl2 → 2 AgCl + Mg(NO3)2

Type: Synthesis

7. 2 Al + 6 HCl → 2 AlCl3 + 3 H2

Type: Decomposition

8. C3H8 + 5 O2 → 3 CO2 + 4 H2O

Type: Combustion

9. 2 FeCl3 + 6 NaOH → Fe2O3 + 6 NaCl + 3 H2O

Type: Double Replacement

10. 4 P + 5 O2 → 2 P2O5

Type: Synthesis

11. 2 Na + 2 H2O → 2 NaOH + H2

Type: Single Replacement

12. 2 Ag2O → 4 Ag + O2

Type: Decomposition

13. C6H12O6 + 6 O2 → 6 CO2 + 6 H2O

Type: Combustion

14. 2 KBr + MgCl2 → 2 KCl + MgBr2

Type: Double Replacement

15. 2 HNO3 + Ba(OH)2 → Ba(NO3)2 + 2 H2O

Type: Double Replacement

16. C5H12 + 8 O2 → 5 CO2 + 6 H2O

Type: Combustion

17. 4 Al + 3 O2 → 2 Al2O3

Type: Synthesis

18. Fe2O3 + 2 Al → 2 Fe + Al2O3

Type: Single Replacement

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Describe two ways in which sodium chloride is different from sodium

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Answer:

Sodium (Na) is a highly reactive metal, while sodium chloride (NaCl) is a compound formed by the combination of sodium and chlorine (Cl). Sodium exists as a pure element, whereas sodium chloride is a stable, crystalline compound.

Sodium is a soft, silvery-white metal that is highly reactive and can easily react with water or air. In contrast, sodium chloride is a white crystalline solid that is highly stable and does not react readily with water or air. Sodium chloride is commonly known as table salt and is widely used as a seasoning and food preservative.

someone help ASAP!!

What are possible components of ionic compounds? Check all that apply.

1: a metal and a nonmetal

2: 2 metals

3: a metal and a polyatomic anion

4: a polyatomic cation and a metal




What happens to ions during bonding to form an ionic compound?

Cations accept electrons and anions give away electrons.

Anions and cations share electrons.

Cations give away electrons and anions accept those electrons.

Answers

Answer:

Question 1:

1: a metal and a nonmetal

3: a metal and a polyatomic anion

4: a polyatomic cation and a metal

Question 2:

Cations give away electrons and anions accept those electrons

For the 1st question :

1 is correct
2 is incorrect
3 is correct
4 is correct

For the 2nd question :

Cations give away electrons and anions meaning the elections accepts them


So the correct answer is "Cations give away electrons and anions accept those electrons."

Determine the type of reaction, predict the product and balance the equation for the following:
LiOH + HBr --->

Answers

The type of reaction is a double displacement reactionThe products of the reaction are LiBr and H₂OThe balanced equation is LiOH + HBr -> LiBr + H₂O

How do i know the type of reaction?

From the uncompleted equation, we have:

LiOH + HBr ->

LiOH is an ionic substance that can dissociate to produce Li⁺ and OH⁻ HBR is an ionic substance that can dissociate to produce H⁺ and Br⁻

Since we have two ionic substance reacting, we can conclude that the type of reaction is double displacement reaction as the reaction will involve exchange of ions between the reacting species.

How do i determine the products of the reaction?

The products of the reaction can be obtained by balancing the equation. This is shown below:

LiOH + HBr ->

By exchange of ion, we have

LiOH + HBr -> LiBr + H₂O

Now, observing the equation, we can see that the equation is balanced.

Thus, the products of the reaction are LiBr and H₂O

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Calculate the volume in L of Oxygen gas collected at STP if the sample has a mass of 2.67g?

Answers

Answer:

[tex]\huge\boxed{\sf 1.869\ L}[/tex]

Explanation:

Given that,

Mass = m = 2.67 g

Molar mass (O₂) = 16 × 2 = 32 g/mol

Finding no. of moles:

We know that,

No. of moles = mass in g / molar mass

No. of moles = 2.67 / 32

No. of moles = 0.08 moles

Also, we know that:

1 moles of O₂ at STP = 22.4 LMultiply both sides by 0.08

1 × 0.08 moles of O₂ at STP = 22.4 × 0.08 L

0.08 moles of O₂ at STP = 1.869 L

So, the volume of 0.08 moles of oxygen gas at STP will be 1.869 L.

[tex]\rule[225]{225}{2}[/tex]

What is the percent strength of a 1:25 (weight/volume) solution?

Answers

Answer:

First, let's consider the ratio: 1:25. This means that for every 1 gram of solute, we have 25 milliliters of solvent. Therefore, if we have 100 milliliters of the solution, we can set up a proportion to find the amount of solute in grams:

1 gram solute / 25 milliliters solvent = x grams solute / 100 milliliters solution

Cross-multiplying, we get:

25 * x = 1 * 100

25x = 100

x = 100 / 25

x = 4

So, in 100 milliliters of a 1:25 (weight/volume) solution, there are 4 grams of solute.

To calculate the percent strength, we divide the mass of the solute (4 grams) by the volume of the solution (100 milliliters) and multiply by 100:

Percent strength = (mass of solute / volume of solution) * 100

Percent strength = (4 g / 100 mL) * 100

Percent strength = 4%

Therefore, the percent strength of a 1:25 (weight/volume) solution is 4%.

How many atoms of carbon are there in 0.37 mol of procaine, C13H20N202. a "pain killer" used by dentists?​

Answers

There are approximately 2.8939 x[tex]10^2^4[/tex] carbon atoms in 0.37 mol of procaine.  The molecular formula of procaine (C₁₃H₂₀N₂₀₂), one can see that there are 13 carbon atoms (C13) in one molecule of procaine.

Avogadro's number (6.022 x [tex]10^2^3[/tex]) represents the number of particles (atoms, molecules, or formula units) in one mole of a substance

The number of molecules of procaine in 0.37 mol:

Number of molecules = 0.37 mol x (6.022 x[tex]10^2^3[/tex] molecules/mol)

Number of carbon atoms = Number of molecules x 13 carbon atoms/molecule

Number of molecules = 0.37 mol x (6.022 x [tex]10^2^3[/tex]molecules/mol)

= 2.22614 x [tex]10^2^3[/tex]molecules

Number of carbon atoms = 2.22614 x [tex]10^2^3[/tex] molecules x 13 carbon atoms/molecule

= 2.8939 x [tex]10^2^4[/tex]carbon atoms

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SECTION 1 Surface Water Movement (continued)
MAIN IDEA
DETAILS
Load/Stream magnesium compounds found in surface water, compare to the
Stream Explain how minerals, such as calcium carbonate and soluble
sugar in lemonade.

Answers

Answer:

Basically, they r different chemically and radically.

Explanation:

Here is how:


So,

Magnesium compounds found in surface water can vary depending on the specific water source and environmental factors. However, some common magnesium compounds that can be present in surface water include:

Magnesium Carbonate (MgCO3): This compound can form when magnesium ions (Mg2+) react with carbonate ions (CO32-) present in the water. It is often found in areas where there are limestone or dolomite formations.

Magnesium Hydroxide (Mg(OH)2): This compound can occur when magnesium ions react with hydroxide ions (OH-) in the water. It is more likely to be present in alkaline or basic water conditions.

Magnesium Sulfate (MgSO4): This compound can form when magnesium ions react with sulfate ions (SO42-) in the water. It can be found in areas where there are sulfates present, such as in some mining or industrial areas.

Now, let's compare these magnesium compounds to minerals like calcium carbonate and soluble sugar in lemonade:

Calcium Carbonate (CaCO3): Calcium carbonate is a common mineral found in many natural sources, including limestone, chalk, and shells of marine organisms. It is insoluble in water and tends to precipitate out of the solution, forming solid deposits or scale.

Soluble Sugar in Lemonade: Lemonade typically contains sucrose or other soluble sugars. These sugars are highly soluble in water, meaning they readily dissolve and form a homogeneous mixture with water.

In comparison to magnesium compounds found in surface water, calcium carbonate and soluble sugar in lemonade are chemically different. Calcium carbonate is insoluble in water and tends to separate from the solution, while soluble sugars dissolve completely.

convert 7.54 x 10^-8 m to nanometers

Answers

7.54 *[tex]10^8[/tex] meters is  75.4 nanometers.

To convert 7.54 *  [tex]10^8[/tex] meters to nanometers, you can multiply the value by [tex]10^9[/tex]

as,  [tex]10^9[/tex]nanometers = 1  meter.

7.54 * [tex]10^8[/tex] m * [tex]10^9[/tex] =  7.54 x [tex]10^1[/tex] nm

Therefore, 7.54 *[tex]10^8[/tex] meters is equal to 75.4 nanometers.

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Final answer:

To convert 7.54 x 10^-8 meters to nanometers, you multiply 7.54 x 10^-8 by 1 x 10^9 to get 75.4 nanometers.

Explanation:

To convert meters to nanometers, you need to know that 1 meter is equivalent to 1 x 109 nanometers. Therefore, if you were to convert 7.54 x 10-8 m to nanometers, you would multiply 7.54 x 10-8 by 1 x 109.

Here's how you'd do it: 7.54 x 10-8 m * 1 x 109 nm/m = 75.4 nm. So, 7.54 x 10-8 meters is equivalent to 75.4 nanometers.

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examples of chemical compounds that are formed by swapping the valencies

Answers

Some examples of chemical compounds that are formed by swapping the valencies are:

Sodium chloride (NaCl)Magnesium oxide (MgO)Carbon dioxide (CO2)Water (H2O)

What is valency?

In chemistry, one can analyze an element's combining capacity with other atoms through its valency, crucial for creating chemical compounds or molecules.

Recently, an article featured a comparable description detailing atomic valence as "the electrons utilized by the atom during bonding." There are also two distinct formulas available to determine the element's level of valence.

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For this question choose three answered which question should be asked before writing the name for H2SO4 (aq) HURRY

Answers

The name for H2SO4(aq) is Sulfuric acid.

Sulfuric acid (H2SO4) is a highly corrosive and strong acid. It is one of the most important industrial chemicals produced worldwide. Sulfuric acid is commonly used in various industries for a wide range of applications. It is used in the production of fertilizers, detergents, dyes, pharmaceuticals, and various chemical processes.

Sulfuric acid is also utilized in laboratories for its acidic properties and as a dehydrating agent due to its strong affinity for water. It is a dense, oily liquid that is colorless when pure but can appear yellowish or brownish due to impurities. When handling sulfuric acid, caution must be exercised as it can cause severe burns and is harmful if ingested or inhaled.

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What is the molal concentration of 30% ethanol solution C2H2OH

Answers

To determine the molal concentration of a solution, we need to know the amount of solute (ethanol) in moles and the mass of the solvent (usually water) in kilograms.

Given that the solution is 30% ethanol, it means that there are 30 grams of ethanol in 100 grams of the solution. Let's assume we have 100 grams of the solution.

To find the amount of ethanol in moles, we need to convert grams to moles using the molar mass of ethanol (C2H5OH).

The molar mass of C2H5OH:

2 * atomic mass of carbon (C) = 2 * 12.01 g/mol = 24.02 g/mol

6 * atomic mass of hydrogen (H) = 6 * 1.01 g/mol = 6.06 g/mol

1 * atomic mass of oxygen (O) = 1 * 16.00 g/mol = 16.00 g/mol

1 * atomic mass of hydrogen (H) = 1 * 1.01 g/mol = 1.01 g/mol

Total molar mass of C2H5OH = 24.02 + 6.06 + 16.00 + 1.01 = 47.09 g/mol

Now, let's calculate the amount of ethanol in moles:

30 grams ethanol * (1 mol / 47.09 g) = 0.637 moles ethanol

Next, we need to determine the mass of the solvent (water) in kilograms. Let's assume we have 100 grams of the solution, so the mass of water would be 100 - 30 = 70 grams.

Converting the mass of water to kilograms:

70 grams * (1 kg / 1000 grams) = 0.07 kg

Finally, we can calculate the molal concentration (m) using the formula:

molal concentration (m) = moles of solute/mass of solvent in kilograms

m = 0.637 moles / 0.07 kg ≈ 9.10 mol/kg

Therefore, the molal concentration of the 30% ethanol solution (C2H5OH) is approximately 9.10 mol/kg.

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Determine the limiting reactant:
2BF3 (1) + 3Li2SO4 (aq) --> B₂(SO4)3 (aq) + 6LiF (aq) (balanced)
300 grams of BF3 react with 800 grams of Li₂SO4.

Answers

Answer:

The limiting reactant is BF3 because there is less of it than Li2SO4.

Explanation:

B2 2- orbital picture​

Answers

The B2 2- orbital is a molecular orbital formed by the combination of two atomic orbitals from two boron atoms. It is derived from the overlap of two 2p atomic orbitals. The B2 2- orbital can be represented by a molecular orbital diagram, where the two 2p orbitals combine to form two molecular orbitals: a bonding orbital (lower in energy) and an antibonding orbital (higher in energy).

In the B2 2- orbital picture, the bonding orbital is lower in energy and has a lower electron density in the internuclear region. It contributes to the stability of the molecule. The antibonding orbital is higher in energy and has a node in the internuclear region. It does not contribute to the stability of the molecule and is less populated with electrons.

The B2 2- orbital diagram would show the relative energy levels of the atomic orbitals and the resulting molecular orbitals. The bonding orbital would be lower in energy and occupied by electrons, while the antibonding orbital would be higher in energy and unoccupied or less populated with electrons.

balanced equation for the decomposition of aluminium tetraoxosulphate​

Answers

The balanced equation for the decomposition of aluminium tetraoxosulphate (also known as aluminium sulfate) is:

2Al2(SO4)3(s) → 2Al2O3(s) + 3SO2(g) + 3O2(g)

This equation shows that when solid aluminium tetraoxosulphate is heated, it decomposes into solid aluminium oxide, and gases sulphur dioxide and oxygen. The coefficients in the balanced equation indicate that two molecules of aluminium tetraoxosulphate decompose to form two molecules of aluminium oxide, three molecules of sulphur dioxide, and three molecules of oxygen.

Look at the graph that shows the progress made in reducing fuel cell system costs. Graph of progress in reducing Fuel Cell System has an x axis labeled Years from 2002 to 2010, and a y axis labeled cost in dollars per kilowatt hour from 0 to 300. Data is: 2002, 248 dollars. 2003, 198 dollars. 2004, 149 dollars. 2005, 99 dollars. 2007, 82 dollars. 2008, 60 dollars. 2009, 51 dollars. 2010, 43 dollars. 2015 goal is 30 dollars per kilowatt hour. Which conclusion is supported by the information in the graph? The cost of producing a kilowatt of power with a fuel cell will be less than $30 in 2015. Fuel cell cars are unlikely to be affordable in the near future. The rate of emissions is decreasing because of inexpensive fuel cell technology. The environment is unlikely to improve as a result of cheap fuel cell technology.

Answers

The conclusion supported by the information in the graph is:

The cost of producing a kilowatt of power with a fuel cell will be less than $30 in 2015.

Based on the data provided in the graph, the cost of fuel cell systems has been decreasing over the years. In 2010, the cost was $43 per kilowatt hour, and the graph does not show any data beyond that year. However, it is mentioned that the goal for 2015 is to reach a cost of $30 per kilowatt hour. Given the decreasing trend in the cost of fuel cell systems, it is reasonable to conclude that the cost will be less than $30 in 2015, supporting the mentioned conclusion.

A gas occupies a volume of 139.3-mL at 135.5-kPa. What volume will the gas occupy at 138.7-kPa if the temperature remains the same?

Answers

The volume the gas will occupy at pressure of 138.7 KPa, given that the temperature remains the same is 136 mL

How do i determine the new volume of the gas?

The new volume of the gas, given that the new pressure is 138.7 KPa can be obtained as follow:

Initial volume of gas (V₁) = 139.3 mLInitial pressure of gas (P₁) = 135.5 KPaNew pressure of gas (P₂) = 138.7 KPaNew volume of gas (V₂) =?

P₁V₁ = P₂V₂

Inputting the given parameters, we have:

135.5 × 139.3 = 138.7 × V₂

18875.17 = 138.7 × V₂

Divide both side by 138.7

V₂ = 18875.17 / 138.7

V₂ = 136 mL

Thus, we can conclude that the volume of the gas will be 136 mL

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‼️‼️‼️need help asap‼️‼️‼️

Answers

24. To calculate the molarity of a solution, we must first find out how many moles of [tex]BaI_2[/tex] are in the solution.

Molar mass of BaI2 = (1 x atomic mass of Ba) + (2 x atomic mass of I)

= (1 x 137.33 g/mol) + (2 x 126.90 g/mol)

= 137.33 g/mol + 253.80 g/mol

= 391.13 g/mol

Number of moles of BaI2 = mass of BaI2 / molar mass of BaI2

= 413 g / 391.13 g/mol

= 1.056 mol

the molarity of the solution using the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

Volume of solution = 750 ml = 750 ml / 1000 ml/L = 0.750 L

Molarity = 1.056 mol / 0.750 L

= 1.408 M

Therefore, the molarity of the solution is 1.408 M.

25. a. [tex]P_20_7[/tex] - Ionic compound (Phosphorus(V) oxide)

b. [tex]SnBr_2[/tex] - Ionic compound (Tin(II) bromide)

c. [tex]Fe(OH)_2[/tex]-  Ionic compound (Iron(II) hydroxide)

d. [tex]Cl_30_8[/tex] - Not a valid chemical formula

26.

A. (NH4)2CO3 is soluble in water (NH4) in an ionic substance called 2CO3 containing the ions carbonate and ammonium.

B. Fe(OH)2 is insoluble in water. Iron(II) hydroxide is only sparingly soluble.

C. CaOH is not soluble in water. Only very little calcium hydroxide is soluble.

D. PbCl2 is insoluble in water. The chloride of lead(II) is sparingly soluble.

27. FeS + 2KCl = FeCl2 + K2S

FeS is an insoluble precipitate.

2KCl dissolves in aqueous solution.

ZnCl2 + SrSO4 = ZnSO4 + SrCl2

SrSO4 is an insoluble precipitate.

ZnCl2 dissolves in aqueous solution.

28. In salt water, the solute is the salt (sodium chloride, or NaCl), and the solvent is water. The element which dissolves in the solvent to form a solution is called solute.

29. Charles's law states that, if the pressure and volume of a gas remain constant, the volume of a gas falls as the temperature increases. As a result, the capacity of the balloon will decrease as it ascends to altitudes where the temperature is -15 °C.

30. The average kinetic energy of the particles of a substance increases with increase in its temperature. This is because temperature is a gauge for the specific kinetic energy of the constituent particles of a substance. On the other hand, the average kinetic energy falls as the temperature increases.

31. When the volume of a gas decreases, its pressure increases. Boyle's law, which states that at a given temperature, the pressure of a gas is inversely proportional to its volume, describes this relationship. On the other hand, pressure falls when volume increases.

32. The pressure of a gas increases along with its temperature. Gay–Lussac's law, which states that the pressure of a gas is directly proportional to its temperature, given the volume and volume of the gas is constant, describes this relationship.

33. The volume of a syringe is reduced as a marshmallow is pressed and the plunger is depressed. As a result the pressure inside the syringe increases. This is because Boyle's law states that the volume and pressure of a gas are inversely proportional. The decrease in volume causes the air inside the syringe to contract, exerting more pressure on the marshmallow, which is then crushed.

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If you placed 413g of Bal2 in a beaker and filled it with water to a total volume of 750ml, calculate the molarity of the solution

Answers

To calculate the molarity of a solution, we need to determine the number of moles of the solute (Bal2) and then divide it by the volume of the solution in liters.

Given:

Mass of Bal2 = 413 g

Volume of solution = 750 ml = 0.75 L

1. Calculate the number of moles of Bal2:

First, we need to convert the mass of Bal2 to moles using its molar mass. The molar mass of Bal2 can be calculated by summing the atomic masses of boron (B) and iodine (I):

Molar mass of Bal2 = (atomic mass of B × 1) + (atomic mass of I × 2)

Molar mass of Bal2 = (10.81 g/mol × 1) + (126.90 g/mol × 2)

Molar mass of Bal2 = 10.81 g/mol + 253.80 g/mol

Molar mass of Bal2 = 264.61 g/mol

Now we can calculate the number of moles of Bal2:

Moles of Bal2 = Mass of Bal2 / Molar mass of Bal2

Moles of Bal2 = 413 g / 264.61 g/mol

Moles of Bal2 ≈ 1.561 mol

2. Calculate the molarity of the solution:

Molarity (M) = Moles of solute / Volume of solution (in liters)

Molarity (M) = 1.561 mol / 0.75 L

Molarity (M) ≈ 2.081 M

Therefore, the molarity of the solution is approximately 2.081 M.

The molarity of the solution is approximately 1.408 M as to calculate the molarity of a solution, one must need to know the number of moles of the solute and the volume of the solution in liters.

The molar mass of BaI₂ is:

Ba (barium) atomic mass = 137.33 g/mol

I (iodine) atomic mass = 126.90 g/mol

Molar mass of  BaI₂ = (Ba atomic mass) + 2 × (I atomic mass)

= 137.33 + 2 × 126.90

= 137.33 + 253.80

= 391.13 g/mol

Given that the mass of BaI₂ is 413 g,

Number of moles = Mass / Molar mass

= 413 g / 391.13 g/mol

= 1.056 moles

Volume of solution = 750 ml = 750/1000 = 0.75 L

Finally, one can calculate the molarity of the solution using the formula:

Molarity = Number of moles / Volume of solution

= 1.056 moles / 0.75 L

= 1.408 M

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determine if the following are ionic or covalent compounds
a. P2O7
b. SnBr2
c.Fe(OH)2
d.Cl3O8

Answers

Answer:

a. P2O7 - This is a covalent compound. P and O have similar electronegativities and they form a covalent bond between them, rather than an ionic bond.

b. SnBr2 - This is a covalent compound. Sn and Br have different electronegativities, but they still form a covalent bond due to their relatively small difference in electronegativity.

c. Fe(OH)2 - This is an ionic compound. Fe has a higher electronegativity than O and H, so it tends to donate its electrons and become positively charged. This results in the formation of ionic bonds between Fe and OH.

d. Cl3O8 - This is a covalent compound. Cl and O have similar electronegativities, so they form covalent bonds rather than ionic bonds.

Which statement best explains why different gases effuse at different rates?

Answers

Different gases effuse at different rates due to the relationship between their molecular masses, average velocities, and kinetic energy.

Lighter gases have higher average velocities and effuse more rapidly, while heavier gases have lower average velocities and effuse at slower rates. Graham's law of effusion provides a quantitative explanation for this phenomenon.

Different gases effuse at different rates due to variations in their molecular masses and average velocities. Effusion is the process by which gas molecules escape through a small opening or porous barrier into a vacuum or a region of lower pressure.

According to Graham's law of effusion, the rate of effusion of a gas is inversely proportional to the square root of its molar mass. Mathematically, it can be expressed as:

Rate A / Rate B = √(Molar mass B / Molar mass A)

This means that lighter gas molecules, with lower molar masses, effuse faster compared to heavier gas molecules. The reason behind this can be understood by considering the kinetic theory of gases.

Gas molecules are in constant random motion, colliding with each other and the walls of the container. The average velocity of gas molecules is directly related to their kinetic energy, which depends on their mass and temperature. Lighter gas molecules have higher average velocities due to their lower mass and therefore higher kinetic energy.

During effusion, gas molecules near the opening of the container collide with the walls more frequently and possess higher velocities. Lighter gas molecules have a higher chance of having a velocity that exceeds the escape velocity threshold, allowing them to effuse more easily.

On the other hand, heavier gas molecules have lower average velocities and collide less frequently with the walls. They require more energy or higher velocities to overcome intermolecular forces and effuse through the opening.

In summary, different gases effuse at different rates due to the relationship between their molecular masses, average velocities, and kinetic energy. Lighter gases have higher average velocities and effuse more rapidly, while heavier gases have lower average velocities and effuse at slower rates. Graham's law of effusion provides a quantitative explanation for this phenomenon.

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I need help with question 5

Answers

I believe this answer is A, hope this helps!

Human activities are responsible for almost all of the increase in greenhouse gases in the atmosphere over the last 150 years. If we review the pie chart, we can determine the source greenhouse gas emissions by percentages. But ultimately, there is one huge cause of these emissions: it is involved with every piece of this pie chart. What is this human activity?

Answers

The underlying foundation of all these emissions can be traced back to the burning of fossil fuels, making it the dominant and pervasive cause of human-induced greenhouse gas emissions.

The human activity that is intricately connected to every piece of the pie chart representing greenhouse gas emissions is the burning of fossil fuels. Fossil fuel combustion, including coal, oil, and natural gas, is the primary contributor to the rise in greenhouse gas concentrations over the past 150 years. When these fuels are burned for energy generation, transportation, industrial processes, and residential use, carbon dioxide (CO2) is released into the atmosphere. CO2 is the most significant greenhouse gas, accounting for approximately 75% of total emissions. The other greenhouse gases, such as methane (CH4) and nitrous oxide (N2O), are also released as byproducts of certain human activities, such as agriculture, deforestation, and waste management.

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Plants need light from the sun in order to go through photosynthesis. Which type of air pollution would most likely decrease the amount of sunlight a plant can absorb?

Answers

Answer:

Particulate matter pollution decreases the amount of sunlight plants can absorb for photosynthesis.

Explanation:

Identify the conjugate acid-base pairs in the reaction between amonia and hydrofluoric acid in aqueous solution
NH3 (aq) + HF (aq) = NH4+ (aq) + F- (aq)

Answers

The conjugate acid-base pairs in the reaction between ammonia and hydrofluoric acid in aqueous solution are NH3/NH4+ and HF/F-.

In the reaction between ammonia (NH3) and hydrofluoric acid (HF) in aqueous solution, the following conjugate acid-base pairs can be identified:

NH3 (ammonia) and NH4+ (ammonium ion):

Ammonia (NH3) acts as a base by accepting a proton (H+) from hydrofluoric acid (HF) to form the ammonium ion (NH4+). In this reaction, ammonia acts as a Lewis base by donating an electron pair to the proton, resulting in the formation of the ammonium ion as the conjugate acid.

HF (hydrofluoric acid) and F- (fluoride ion):

Hydrofluoric acid (HF) acts as an acid by donating a proton (H+) to ammonia (NH3) to form the fluoride ion (F-).

In this reaction, hydrofluoric acid acts as a Lewis acid by accepting an electron pair from ammonia, resulting in the formation of the fluoride ion as the conjugate base.

To summarize, in the reaction NH3 (aq) + HF (aq) = NH4+ (aq) + F- (aq), the conjugate acid-base pairs are NH3/NH4+ and HF/F-. Ammonia (NH3) is the base that forms its conjugate acid, the ammonium ion (NH4+), while hydrofluoric acid (HF) is the acid that forms its conjugate base, the fluoride ion (F-).

It is important to note that in an aqueous solution, ammonia is present as NH3 molecules, and hydrofluoric acid dissociates into H+ and F- ions. The resulting ammonium ion (NH4+) and fluoride ion (F-) remain in the solution.

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