determine the volume of the following spheres with the given dimensions. to break the code find the mean of all your answers. round your answers to the hundreth place. use 3.14 for an approximation for pi.

Answer:

Step-by-step explanation:

the of of 50 percent of people is married

The diameter of the hemisphere is 39.1918 feet.

The surface area of a hemisphere is given by the formula:

Surface Area = 2πr²

We have,

surface area of the hemisphere is 768π square feet,

So, 2πr² = 768π

Dividing both sides of the equation by 2π, we get:

r² = 384

To find the diameter, we need to double the radius.

Taking the square root of both sides of the equation, we get:

r = √384

r ≈ 19.5959

Now, Diameter ≈ 2 x 19.5959 ≈ 39.1918

Therefore, the diameter of the hemisphere is 39.1918 feet.

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The complete table for the function are

x  -2  -1  1  3

y  2   3  5  7

The graph is added as an attachment

From the question, we have the following parameters that can be used in our computation:

The function equation and the incomplete table of values

This is given as

y = x + 4

From the table, the missing values are at

x = -2, x = -1, 1 and x = 3

So, we have

y = -2 + 4 = 2

y = -1 + 4 = 3

y = 1 + 4 = 5

y = 3 + 4 = 7

The graph is added as an attachment

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Answer:

The maximum value of the profit function occurs at the corner point with the highest value, which is P2 = 25.

Therefore, the maximum profit is $25.

Step-by-step explanation:

You can determine the median of a triangle by looking out for the point that is 2/3 of the distance tht connects from the vertices, to midpoint and oposite sides.

The perpendicular bisector is determined by measuring the point that is equidistant from the segment.

The altitude of a triangle can be found by measiring the height of the triangle's extension that could be inside or outside the triangle. In obtsue triangles, this altitude is commonly found outside the triangle.

Also, the angle bisector of a triangle is the point that is equidistant from the angles sides. These descriptions can help in analyzing a trinagle.

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Answer:

 [(5 ± √(29)) ÷ 2]

Step-by-step explanation:

x = [(-b ± √(b² - 4ac)) ÷ 2a]

=  [(-(-5) ± √((-5)² - 4(1)(-1))) ÷ 2(1)]

=  [(5 ± √(25 + 4)) ÷ 2]

=  [(5 ± √(29)) ÷ 2]

The area of triangle ABC is 19 square units.

To find the area of a triangle, we can use different formulas depending on the information available. Since we have the coordinates of the vertices A(-9, -8), B(-2, -9), and C(-8, -5), we can use the Shoelace Formula (also known as the Gauss's area formula) to calculate the area of the triangle.

The Shoelace Formula states that if the coordinates of the vertices of a triangle are (x1, y1), (x2, y2), and (x3, y3), then the area (A) of the triangle can be calculated as:

Area = 0.5 * |(x1 * (y2 - y3) + x2 * (y3 - y1) + x3 * (y1 - y2))|

Using the coordinates of the vertices A(-9, -8), B(-2, -9), and C(-8, -5), we can substitute these values into the formula to calculate the area.

Let's calculate step by step:

x1 = -9

y1 = -8

x2 = -2

y2 = -9

x3 = -8

y3 = -5

Area = 0.5 * |(-9 * (-9 - (-5)) + (-2) * (-5 - (-8)) + (-8) * ((-8) - (-9)))|

Area = 0.5 * |(-9 * (-4) + (-2) * (3) + (-8) * (-1))|

Area = 0.5 * |(36 + (-6) + 8)|

Area = 0.5 * |(38)|

Area = 0.5 * 38

Area = 19

Therefore, the area of triangle ABC is 19 square units.

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The Horizontal distance from the base of the skyscraper to the ship is approximately 403.81 feet.

We can use trigonometry and the concept of angles of depression. We can consider the height of the observation deck as the opposite side and the horizontal distance to the ship as the adjacent side of a right triangle.

Given that the angle of depression is 67 degrees and the height of the observation deck is 955 feet, we want to find the horizontal distance (adjacent side).

Using the trigonometric function tangent, we can set up the following equation:

tan(67°) = opposite/adjacent

tan(67°) = 955/adjacent

To find the value of the adjacent side (horizontal distance), we can rearrange the equation:

adjacent = 955/tan(67°)

Using a calculator, we can evaluate the tangent of 67 degrees:

tan(67°) ≈ 2.3693

Now we can substitute this value into the equation:

adjacent = 955/2.3693

adjacent ≈ 403.81

Therefore, the horizontal distance from the base of the skyscraper to the ship is approximately 403.81 feet.

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Step-by-step explanation:

Cylinder LATERAL  S.A. = circ   X   Height = 132 cm  X  30 cm  = 3960 cm^2

   PLUS the two ends  =  two  X  pi r^2

  the circumference = pi * d = 132 cm

                   then  diameter = 132 / pi   then radius =  1/2  132 / pi = 66/ pi

     so end areas :  two *    pi (66/ pi)^2   = 2773.1

TOTAL = 3960  +  2773.1 =  6733.1 cm^2

The graph of the system of inequalities:

y  ≤ (1/4)*x - 2

y  ≥ −(5/4)x +2

Is in the image at the end.

Here we have the system of inequalities:

y  ≤ (1/4)*x - 2

y  ≥ −(5/4)x +2

To graph this, we just need to graph both of the linear equations, and we need to shade the region below the first line (the one with positive slope) and the region above the second line, the one with negative slope.

Then the graph of the system of inequalities is the graph you can see in the image at the end of the answer.

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The distance across the stream is 198 m.

We have,

ΔABC and ΔEBD are similar.

This means,

Corresponding sides ratios are the same.

Now,

AC/ED = AB/BE

Substituting the values.

x/360 = 220/400

x = 220/400 x 360

x = 22/40 x 360

x = 22 x 9

x = 198

Thus,

The distance across the stream is 198 m.

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The pair of figures are similar because:

• Both figures are parallelograms

• All sides are congruent.

• Scale factor 1: 2.5

A scale factor is defined as the ratio between the scale of a given original object and a new object, which is its representation but of a different size (bigger or smaller).

The pair of figures are similar because:

• Both figures are parallelograms

• All sides are congruent

• Angles W and Y are congruent with angles P and R

• Angles X and Z are congruent with angles S and Q

• Scale factor 1 : 2.5

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Approximately 273 cubes with a side length of 1/2 inch will be needed to fill the prism.

To determine the number of cubes with a side length of 1/2 inch needed to fill the prism, we need to calculate the volume of the prism and divide it by the volume of a single cube.

The given dimensions of the pencil box are:

Length: 6 1/2 inches

Width: 3 1/2 inches

Height: 1 1/2 inches

To find the volume of the prism, we multiply the length, width, and height:

Volume of the prism = Length [tex]\times[/tex] Width [tex]\times[/tex] Height

[tex]= (6 1/2) \times (3 1/2) \times (1 1/2)[/tex]

First, we convert the mixed numbers to improper fractions:

[tex]6 1/2 = (2 \times 6 + 1) / 2 = 13/2[/tex]

[tex]3 1/2 = (2 \times 3 + 1) / 2 = 7/2[/tex]

[tex]1 1/2 = (2 \times 1 + 1) / 2 = 3/2[/tex]

Now we substitute the values into the formula:

Volume of the prism [tex]= (13/2) \times (7/2) \times (3/2)[/tex]

[tex]= (13 \times 7 \times 3) / (2 \times 2 \times 2)[/tex]

= 273 / 8

≈ 34.125 cubic inches.

Next, we calculate the volume of a single cube with a side length of 1/2 inch:

Volume of a cube = Side length [tex]\times[/tex] Side length [tex]\times[/tex] Side length

[tex]= (1/2) \times (1/2) \times (1/2)[/tex]

= 1/8

To find the number of cubes needed to fill the prism, we divide the volume of the prism by the volume of a single cube:

Number of cubes = Volume of the prism / Volume of a single cube

= (273 / 8) / (1/8)

= 273

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The values from figure is,

x = 2

NS = 3.5

We have to given that,

In the figure below, S is the center of the circle.

And, Suppose that JK = 16, MP = 8, LP = 2x + 4, and SP = 3.5.

Now, We know that,

By figure,

MP = LP

Substitute the given values,

8 = 2x + 4

8 - 4 = 2x

4 = 2x

x = 4/2

x = 2

Hence, We get;

LM = MP + LP

LM = 8 + (2x + 4)

LM = 8 + 2 x 2 + 4

LM = 8 + 4 + 4

LM = 16

Since, We have JK = 16

Hence, We get;

NS = SP

This gives,

NS = 3.5

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The total number of possible outcomes is the number of rows in the table, which depends on the size of the table.

To determine the experimental probability of correctly guessing exactly one correct answer out of five choices, we can utilize the random number table provided, where 0's represent incorrect answers and 1's represent correct answers.

Since we have five choices for each answer, we will focus on a single row of the random number table, considering five consecutive values.

Let's assume we have randomly selected a row from the table, and the numbers in that row are as follows:

0 1 0 1 0

In this case, the second and fourth answers are correct (represented by 1's), while the remaining three choices are incorrect (represented by 0's).

To calculate the experimental probability of exactly one correct answer, we need to determine the number of favorable outcomes (i.e., rows with exactly one 1) and divide it by the total number of possible outcomes (which is equal to the number of rows in the table).

Looking at the table, we can see that there are several possible rows with exactly one 1, such as:

0 1 0 0 0

0 0 0 1 0

0 0 0 0 1

Let's assume there are 'n' favorable outcomes. In this case, 'n' is equal to 3.

The total number of possible outcomes is the number of rows in the table, which depends on the size of the table. Without the specific size of the table, we cannot provide an accurate value.

To calculate the experimental probability, we divide the number of favorable outcomes by the total number of possible outcomes:

Experimental probability = n / Total number of possible outcomes

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The required answer are :

6. The transformation from the graph of f to the graph of r in equation (6) involves compressing the graph horizontally by a factor of 5/2.

7. The transformation from the graph of f to the graph of r in equation (7) involves stretching the graph vertically by a factor of 6.

8.  The transformation from the graph of f to the graph of r in equation (8) involves shifting the graph horizontally to the right by 3 units.

9. The transformation from the graph of f to the graph of r in equation (9) involves compressing the graph horizontally by a factor of 4/3.

10.  The transformation from the graph of f to the graph of r in equation (10) involves shrinking the graph vertically by a factor of 1/2.

11.  The transformation from the graph of f to the graph of r in equation (11) involves shifting the graph vertically upward by 3 units.

In formula form: r(x) = f(2/5x)

This transformation causes the graph of r to become narrower compared to the graph of f, as it is compressed horizontally. The rate at which x-values change is increased, resulting in a steeper slope. The overall shape and direction of the graph remain the same, but it is narrower and more compact.

Therefore, the transformation from the graph of f to the graph of r in equation (6) involves compressing the graph horizontally by a factor of 5/2. This means that every x-coordinate in the graph of f is multiplied by 2/5 to obtain the corresponding x-coordinate in the graph of r. The vertical positioning of the graph remains unchanged.

In formula form: r(x) = 6f(x)

This transformation causes the graph of r to become taller compared to the graph of f, as it is stretched vertically. The rate at which y-values change is increased, resulting in a steeper slope. The overall shape and direction of the graph remain the same, but it is taller and more elongated.

Therefore, the transformation from the graph of f to the graph of r in equation (7) involves stretching the graph vertically by a factor of 6. This means that every y-coordinate in the graph of f is multiplied by 6 to obtain the corresponding y-coordinate in the graph of r. The horizontal positioning of the graph remains unchanged.

In formula form: g(x) = f(x - 3)

This transformation causes the entire graph of f to shift to the right by 3 units. Every point on the graph of f moves horizontally to the right, maintaining the same vertical position. The overall shape and slope of the graph remain the same, but it is shifted to the right.

Therefore, the transformation from the graph of f to the graph of r in equation (8) involves shifting the graph horizontally to the right by 3 units. This means that each x-coordinate in the graph of f is increased by 3 to obtain the corresponding x-coordinate in the graph of r. The vertical positioning of the graph remains unchanged.

In formula form: g(x) = f(4/3x)

This transformation causes the graph of r to become narrower compared to the graph of f, as it is compressed horizontally. The rate at which x-values change is increased, resulting in a steeper slope. The overall shape and direction of the graph remain the same, but it is narrower and more compact.

Therefore, the transformation from the graph of f to the graph of r in equation (9) involves compressing the graph horizontally by a factor of 4/3. This means that every x-coordinate in the graph of f is multiplied by 4/3 to obtain the corresponding x-coordinate in the graph of r. The vertical positioning of the graph remains unchanged.

In formula form: g(x) = 1/2 f(x)

This transformation causes the graph of r to become shorter compared to the graph of f, as it is vertically shrunk. The rate at which y-values change is decreased, resulting in a flatter slope. The overall shape and direction of the graph remain the same, but it is shorter and more compact.

The transformation from the graph of f to the graph of r in equation (10) involves shrinking the graph vertically by a factor of 1/2. This means that every y-coordinate in the graph of f is multiplied by 1/2 to obtain the corresponding y-coordinate in the graph of r. The horizontal positioning of the graph remains unchanged.

In formula form: g(x) = f(x) + 3

This transformation causes the entire graph of f to shift upward by 3 units. Every point on the graph of f moves vertically upward, maintaining the same horizontal position. The overall shape and slope of the graph remain the same, but it is shifted upward.

The transformation from the graph of f to the graph of r in equation (11) involves shifting the graph vertically upward by 3 units. This means that every y-coordinate in the graph of f is increased by 3 to obtain the corresponding y-coordinate in the graph of r. The horizontal positioning of the graph remains unchanged.

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Based on the data, we can infer that the park with the highest fee is Coaster City.

To find the value of each park we must take into account the different tables that show the value of each park. In this case we must find the unit value of each park as follows:

Park 1:

Park 2:

Park 3:

In accordance with the above, we can infer that the 2 Coaster City park is the one with the highest rate.

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Answer:

the volume of the square pyramid is 2430 cubic cm

Answer:

1296 cm³

Step-by-step explanation:

V = a² x [√s²- (a/2)²] / 3

a = 18 cm

s = 15 cm

V = 18² x [√15²-(18/2)²] / 3 = 18² x [√225-81] / 3

V = 324 x (√144/3) = 1296 cm³

The probability that she selects the route of three specific capitals is 3/43

From the question, we have the following parameters that can be used in our computation:

States = 43

Capitals = 3

The probability is then calculated as

P = Capitals/States

substitute the known values in the above equation, so, we have the following representation

P = 3/43

Hence, the probability is 3/43

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The value of the permutation P(5,0) is 1.

To find the value of the permutation P(5,0), we can use the formula:

P(n, r) = n! / (n - r)!

In this case, we have n = 5 and r = 0.

Substituting these values into the formula, we get:

P(5,0) = 5! / (5 - 0)!

Since any number factorial is equal to 1, we have:

P(5,0) = 5! / 5!

Simplifying further:

P(5,0) = 1

Therefore, the value of the permutation P(5,0) is 1.

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Answer:

Assuming the spinner has 6 equal sectors of different colors, and yellow is only one of those colors, we can say that the probability of the spinner not landing on yellow is 5/6 or approximately 0.8333.

To predict the number of times the spinner will not land on yellow out of 90 spins, we can multiply the probability by the total number of spins:

0.8333 x 90 = 74.997 or approximately 75

Therefore, the best prediction possible for the number of times the spinner will not land on yellow out of 90 spins is 75 times.

The quadratic equation shown in the graph is:

y = x² + 2x - 8

Here we want to find the graph of the given quadratic equation, where we only know the zeros of it.

Remember that if a quadratic equation has the zeros:

x = a

x = b

Then we can write it as:

y = (x - a)*(x - b)

Here the zeros are:

x = -4

x = 2

Then we can write:

y = (x + 4)*(x - 2)

Expanding that we will get the standard form:

y = x² + 4x - 2x - 8

y = x² + 2x - 8

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The height of the average fourth grader is 135 cm 21 mm

From the question, we have the following parameters that can be used in our computation:

Birth age = 45 cm 7 mm

Average fourth grader = three times as tall

using the above as a guide, we have the following:

Average fourth grader = 3 * Birth age

So, we have

Average fourth grader = 3 * 45 cm 7 mm

Evaluate

Average fourth grader = 135 cm 21 mm

Hence, the height of the average fourth grader is 135 cm 21 mm

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Answer: (4x-12) + ( 1/2x y -10) = 6

Step-by-step explanation:

First, input 4 for x and 6 for y into the equation so it looks like this:

(4(4)-12) + (1/2(4)(6)-10)

Now solve inside the parentheses starting with the first one. 4 * 4 = 16 so the inside of the first parentheses should look like (16 - 12) which equals 4.

For the second set of parentheses, 1/2 * 4 * 6 = 12, so the inside of that parentheses would look like (12 - 10), which equals 2.

At this point, the equation should look like this: (4) + (2). If you add those two together, your answer should be 6.

The product of (7x - 5)(6x - 4) is 42x^2 - 58x + 20.

First, distribute the first term of the first polynomial (7x) to each term in the second polynomial (6x - 4):

7x × 6x = 42x²

7x × (-4) = -28x

Next, distribute the second term of the first polynomial (-5) to each term in the second polynomial (6x - 4):

-5 × 6x = -30x

-5 × (-4) = 20

Now, combine the like terms:

42x² - 28x - 30x + 20

Simplify the expression:

42x² - 58x + 20

Therefore, the product of (7x - 5)(6x - 4) is 42x^2 - 58x + 20.

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Answer:

∠ DFG = 48°

Step-by-step explanation:

the central angle is equal to the measure of the arc that subtends it.

since EOG is the diameter of the circle with central angle of 180° , then

arc EG = 180°

the inscribed angle EGD is half the measure of the arc ED that subtends it, so

arc ED = 2 × ∠ EGD = 2 × 42° = 84° , then

ED + DG = EG , that is

84° + DG = 180° ( subtract 84° from both sides )

DG = 96°

Then

∠ DFG = [tex]\frac{1}{2}[/tex] × EG = [tex]\frac{1}{2}[/tex] × 96° = 48°

Answer:

2 * A^(3/2).

Step-by-step explanation:

Given that planet y is twice the mean distance from the sun as planet x, we can denote the mean distance of planet x as "A" and the mean distance of planet y as "2A".

The equation T^2 = A^3 represents the relationship between the orbital period (T) and the mean distance from the sun (A) for a planet.

Let's compare the orbital periods of planet x and planet y using the equation:

For planet x:

T_x^2 = A^3

For planet y:

T_y^2 = (2A)^3 = 8A^3

To find the factor by which the orbital period is increased from planet x to planet y, we can take the square root of both sides of the equation for planet y:

T_y = √(8A^3)

Simplifying the square root:

T_y = √(2^3 * A^3)

= √(2^3) * √(A^3)

= 2 * A^(3/2)

Now, we can express the ratio of the orbital periods as:

T_y / T_x = (2 * A^(3/2)) / T_x

As we can see, the orbital period of planet y is increased by a factor of 2 * A^(3/2) compared to the orbital period of planet x.

Therefore, the factor by which the orbital period is increased from planet x to planet y depends on the value of A (the mean distance from the sun of planet x), specifically, it is 2 * A^(3/2).

The charges will be equal when each car travels 2000 miles. To find the charge for that distance, we substitute x = 2000 into either equation.

To determine the number of miles at which the charges for the two car services, A and B, are equal, we can set up an equation based on the given information.

Let's represent the charge for car service A as y_A and the charge for car service B as y_B. We can set up the following equations:

For car service A: y_A = 0.60x + 300 (in cents)

For car service B: y_B = 0.75x (in cents)

To find the number of miles at which the charges are equal, we set y_A equal to y_B and solve for x:

0.60x + 300 = 0.75x

Subtracting 0.60x from both sides:

300 = 0.15x

Dividing both sides by 0.15:

x = 300 / 0.15

x = 2000

Therefore, the charges will be equal when each car travels 2000 miles. To find the charge for that distance, we substitute x = 2000 into either equation. Let's use the equation for car service A:

y_A = 0.60(2000) + 300

y_A = 1200 + 300

y_A = 1500 cents or $15.00

So, when each car travels 2000 miles, the charges will be equal at $15.00.

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