conduct electricity in solution__________.

do not conduct electricity in solution__________

examples include c 6 h 12 o 6 and c c l 4 __________

examples include n a o h and k b r_________

Electrolytes dissociate in solution, meaning that they break down into charged particles called** ions**. This allows them to conduct electricity in solution because the charged ions can move freely and carry electrical current.

Examples of **electrolytes** include NaOH and KBr. On the other hand, non-electrolytes do not dissociate in solution, meaning they do not break down into ions and cannot conduct **electricity**. Examples of non-electrolytes include C6H12O6 (glucose) and CCl4 (carbon tetrachloride).

In summary, electrolytes answer "conduct electricity in solution" and "dissociate in solution" while non-electrolytes answer "do not conduct electricity in solution" and "do not dissociate in solution".

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write the electron arrangement of beryllium. write the number of electrons in each level in ascending level order, separated by a comma. provide your answer below:

The electron arrangement of** beryllium **(Be) is 1s² 2s².

Beryllium is a silvery-white metal. It is relatively soft and has a low density. Uses. Beryllium is used in alloys with copper or nickel to make gyroscopes, springs, electrical contacts, spot-welding electrodes and non-sparking tools.

This means that beryllium has two electrons in the 1s orbital and two electrons in the 2s orbital. In **ascending** level order, the number of **electrons** in each level would be 2, 2.

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Which characteristic best serves to distinguish science from other disciplines? -tentative, reproducible, explanatory, testable, predictive

Science is a unique discipline that sets it apart from other fields of study. One of the key characteristics that distinguish science from other disciplines is its emphasis on** reproducibility**.

In other words, scientific findings and results should be consistent and repeatable under similar conditions. This helps to ensure that the data and conclusions drawn from it are valid and reliable. The **scientific method** requires that experiments and observations are conducted in a systematic and controlled manner, and that the results are subject to peer review and scrutiny. By emphasizing reproducibility, **science **helps to establish a firm foundation of knowledge that can be built upon and refined over time. This allows researchers to develop theories and explanations that are supported by **empirical evidence** and can be used to make accurate predictions about the natural world. In summary, reproducibility is a critical characteristic of science that helps to ensure the validity and reliability of its findings and conclusions.

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provide the chemical structure for 9-chlorobicyclo 3.3.1 nonane

The **chemical** structure for 9-chlorobicyclo 3.3.1 **nonane **can be represented as follows: [tex]CH_3 - CH_2 - CH_2 - CH_2 - CH_2 - CH_2 - CH_2 - CH(Cl) - CH_2[/tex]

This structure indicates that the **compound** consists of a chain of seven carbon atoms, each of which is bonded to two other carbon atoms and one hydrogen atom. Additionally, one of the carbon atoms is bonded to a chlorine atom, which is represented by (Cl) in the structure. **Nonane** refers to a nine-carbon straight-chain hydrocarbon, which is the backbone of the compound. The term "bicyclo 3.3.1" indicates that there are three rings in the structure, with two of them fused together. The numbers in the name describe the size of each ring and the **position** of the fusion points.

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the temperature of a cup of coffee obeys newton's law of cooling. the initial temperature of the coffee is 150f and one minute later, it is 135f. the ambient temperature of the room is 70f. if t(t) represents the temperature of the coffee at time t, the correct differential equation for the temperature with side conditions is select the correct answer

The correct **differential equation** for the temperature of the coffee with side conditions is dT/dt = ln(2/3)(T - 70)

with the initial condition that T(0) = 150.

The correct differential equation for the temperature of the coffee with side conditions can be found using** Newton's law of cooling**, which states that the rate of change of the temperature of an object is proportional to the difference between the object's temperature and the ambient temperature. In this case, we can represent the temperature of the coffee at time t as T(t) and the **ambient temperature** as Ta. Therefore, the differential equation for the temperature of the coffee can be written as:

dT/dt = k(T - Ta)

where k is a **constant of proportionality**.

To find k, we can use the given information that the temperature of the coffee drops from 150F to 135F in one minute. We can set up an equation using this information:

(135 - 70) = (150 - 70) * e^(-k*1)

Simplifying this equation, we get:

k = ln(2/3)

Therefore, the correct differential equation for the temperature of the coffee with side conditions is:

dT/dt = ln(2/3)(T - 70)

with the initial condition that T(0) = 150.

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does the equilibrium ratio of product to reactant depend on the percent of the molecules that reacted in the forward and reverse reactions? if yes, describe the relationship.

Yes, the **equilibrium** ratio of product to reactant does depend on the percent of molecules that reacted in the forward and reverse reactions.

This is because the equilibrium constant is calculated based on the ratio of products to **reactants** at equilibrium, which is determined by the rate of the forward and reverse reactions. If there is a higher percentage of molecules reacting in the forward direction, then the equilibrium will favor the products and the equilibrium constant will be higher. Conversely, if there is a higher percentage of molecules reacting in the reverse direction, then the equilibrium will favor the reactants and the equilibrium constant will be lower. At equilibrium, the forward and reverse reaction rates are equal. This balance is determined by the reaction's equilibrium constant (K), which is the ratio of product concentrations to reactant concentrations raised to their respective **stoichiometric** coefficients. As the reaction progresses and the percentage of molecules reacting in the forward and reverse directions change, the concentrations of products and reactants adjust accordingly, maintaining the equilibrium constant. The relationship between the equilibrium ratio and reaction percentages reflects the system's stability and its tendency to reach equilibrium.

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What is the most common geometry found in four-coordinate complexes?

A) square planar

B) octahedral

C) tetrahedral

D) icosahedral

E) trigonal bipyramidal

The most common **geometry **found in four-coordinate complexes is tetrahedral. In a tetrahedral geometry, the central atom is surrounded by four other atoms or groups of atoms, which are located at the corners of a tetrahedron. Therefore, the correct answer to this question is C) tetrahedral.

This geometry is commonly found in **compounds **with sp3 hybridization, where the central atom has four electron pairs in its valence shell. The other options listed in the question, such as octahedral and trigonal bipyramidal, are more commonly found in compounds with six or more coordination sites. Square planar and icosahedral geometries are less common, but can still be observed in certain **complex **compounds. Therefore, the correct answer to this question is C) tetrahedral.

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Entex PSE is a decongestant drug. An analysis shows that it is composed of 60.58% C, 7.13% H, and 32.29% What is its empirical formula?

The **empirical formula** of Entex PSE, given its composition of 60.58% carbon (C), 7.13% hydrogen (H), and 32.29% oxygen (O), can be determined by converting the percentages into moles and finding the simplest whole-number ratio. The empirical formula is **C_{9}H_{13}NO**.

To determine the **empirical formula**, we need to convert the percentages of each element into moles. Assuming we have 100 grams of the compound, we can calculate the moles of each element.

For carbon (C):

Percentage of C = 60.58%

Molar mass of C = 12.01 g/mol

Moles of C =\frac{ (60.58 g / 100 g) }{ (12.01 g/mol) }≈ 0.504 mol

For hydrogen (H):

Percentage of H = 7.13%

**Molar mass** of H = 1.01 g/mol

Moles of H =\frac{ (7.13 g / 100 g) }{ (1.01 g/mol) }≈ 0.07 mol

For oxygen (O):

Percentage of O = 32.29%

Molar mass of O = 16.00 g/mol

Moles of O = \frac{(32.29 g / 100 g) }{ (16.00 g/mol) }≈ 0.202 mol

Next, we need to find the simplest whole-number ratio of these moles. By dividing each **mole** value by the smallest mole value (0.07 mol), we get approximately 7.2 moles of C, 1 mole of H, and 2.9 moles of O.

Rounding these values to the nearest whole number, we find the empirical formula of Entex PSE to be **C_{9}H_{13}NO**.

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Calibration and collection of equilibrium data are different experiment. Why could you use the calibration curve for getting equilibrium data?

**Calibration** and collection of equilibrium data are indeed two different experiments. Calibration is the process of determining the relationship between the input and output of a measuring instrument. On the other hand, equilibrium data refers to the data obtained from experiments involving the establishment of a state of balance between two or more phases.

However, it is possible to use the calibration curve for getting **equilibrium data** because the calibration curve provides a way to relate the signal obtained from a measuring instrument to the concentration of the analyte. Equilibrium data can be obtained by measuring the concentration of the analyte in the sample before and after the establishment of equilibrium. By plotting the **concentration** of the analyte against the signal obtained from the measuring instrument, a calibration curve can be obtained. This calibration curve can then be used to determine the concentration of the analyte in the sample at equilibrium.

In summary, although calibration and equilibrium data are different experiments, the calibration curve obtained from the calibration experiment can be used to determine the concentration of the analyte in equilibrium experiments. This is because the calibration curve provides a way to relate the signal obtained from a measuring instrument to the concentration of the analyte.

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The pH of a solution of Ca(OH)2 is 8.57. Find the [Ca(OH)2]. Be careful, the fact that this base produces 2 OH- is important!

The concentration of** Ca(OH)2** in the solution is approximately 1.33 x 10^(-6) M.

To find the concentration of Ca(OH)2 in a solution with a pH of 8.57, we need to use the concept of pOH, which is the negative logarithm of the **hydroxide **ion concentration ([OH-]). The **pOH **can be calculated by subtracting the pH from 14, which gives us 14 - 8.57 = 5.43.

Since Ca(OH)2 produces two OH- ions for every molecule of Ca(OH)2 that dissolves, the concentration of OH- **ions **will be twice the concentration of Ca(OH)2. Thus, we have [OH-] = 2x, where x represents the concentration of Ca(OH)2.

Taking the antilogarithm of the pOH, we find that [OH-] = 10^(-pOH) = 10^(-5.43).

Since [**OH**-] = 2x, we can write 2x = 10^(-5.43) and solve for x.

x = (10^(-5.43))/2 ≈ 1.33 x 10^(-6) M

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The following instruction sequence describes arguments being pushed into the stack before jumping to subroutine CalcEq. How many arguments are passed to the subroutine CalcEq? Assume CalcEg returns a value. di sp. 5p. 4 Sto, (sp) ada spp4 $t1, (p) addi SSD, Ssp. -4 Jal Calca 3 0 1 04 02

The instruction sequence provided appears to have typos and formatting issues, making it difficult to accurately assess the number of arguments passed to the **subroutine** CalcEq.

The instruction sequence provided appears to have typos and formatting issues, making it difficult to accurately assess the number of **arguments** passed to the subroutine CalcEq. However, I can still provide some general information about subroutines and how they work with arguments.

A subroutine (also known as a function or procedure) is a sequence of instructions that perform a specific task within a program. It is called from the main program or another subroutine, and it typically receives input data (arguments) and returns a value upon completion.

Arguments are passed to a subroutine by placing them onto the stack, a data structure used to store temporary information during a program's execution. The number of arguments passed to a subroutine can be determined by **analyzing** the instruction sequence before the subroutine call and identifying the operations that push the arguments onto the stack.

However, without a properly formatted and error-free instruction sequence, it is not possible to determine the exact number of arguments passed to the CalcEq subroutine in this case. If you could provide a corrected version of the instruction sequence, I would be happy to help further.

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.Calculate the energy released in joules/mol when one mole of polonium-214 decays according to the equation

21484 Po --> 21082 Pb + 42 He

Atomic masses: Pb-210 = 209.98284 amu,

Po-214 = 213.99519 amu, He-4 = 4.00260 amu.]

Question 8 options:

8.78 x 1014 J/mol

7.2 x 1014 J/mol

8.78 x 1011 J/mol

–9.75 x 10–3 J/mol

1.46 x 10–9 J/mol

To calculate the energy released in joules/mol when one mole of** polonium-214 decays**, first determine the mass difference between reactants and products: So the energy released when one mole of polonium-214 decays is 8.78 x 10¹⁴ J/mol.

To calculate the energy released in joules/mol when one mole of polonium-214 decays according to the given equation, we need to first determine the atomic mass difference between the **reactants **and products.

The atomic mass of 214Po is 213.99519 amu, while the combined** atomic masses** of 210Pb and 4He are 209.98284 amu + 4.00260 amu = 213.98544 amu.

Thus, the atomic mass difference is 213.99519 amu - 213.98544 amu = 0.00975 amu.

Using the relationship E=mc^2, we can calculate the energy released by the decay of one mole of 214Po as:

E = (0.00975 amu/mol) * (1.66054 x 10^-27 kg/amu) * (2.99792 x 10^8 m/s)^2 = 8.78 x 10^14 J/mol.

Therefore, the correct answer is 8.78 x 10^14 J/mol.

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Select the atoms in histrionicotoxin 283A that are sp 3

-hybridized. * How many π bonds are in the molecule? Select the atoms in histrionicotoxin 283 A that are sp 2

-hybridized. *).

**Histrionicotoxin **283A contains three sp3-hybridized atoms and one π bond. The **sp3-hybridized **atoms are located at specific positions within the molecule.

Histrionicotoxin 283A is a complex molecule with multiple atoms and functional groups. To identify the sp3-hybridized atoms, we need to understand the concept of **hybridization**. In sp3 hybridization, one s orbital and three p orbitals combine to form four sp3 hybrid orbitals, which are then used to form **sigma bonds **with other atoms.

Within the histrionicotoxin 283A molecule, there are three atoms that exhibit sp3 hybridization: carbon (C) atoms. These sp3-hybridized carbon atoms are typically **bonded **to four other atoms, including hydrogen (H) atoms and other carbon atoms.

As for the number of π bonds in the molecule, one π bond is present. A π bond forms when parallel p orbitals overlap sideways, allowing for the sharing of **electrons**. In histrionicotoxin 283A, this π bond is usually found between two carbon (C) atoms.

In summary, histrionicotoxin 283A contains three sp3-hybridized carbon atoms and one π bond formed between two carbon atoms. The sp3 hybridization provides stability and determines the geometry around these carbon atoms, while the presence of a π bond contributes to the overall electronic structure of the molecule.

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a sample of sand has a mass of 51.1 g and a volume of 29.7 cm3 . calculate its density in grams per cubic centimeter ( g/cm3 ).

The **density **οf the sand sample is apprοximately 1.72 g/cm³.

Tο calculate the density οf the **sand sample**, we divide the mass οf the sample by its **vοlume**.

Given:

**Mass **οf the sand sample = 51.1 g

Vοlume οf the sand sample = 29.7 cm³

Density is defined as the mass per unit vοlume. Therefοre, we can calculate the density using the fοrmula:

Density = Mass / Vοlume

Density = 51.1 g / 29.7 cm³

**Density **≈ 1.72 g/cm³

Therefοre, the density οf the sand sample is apprοximately about 1.72 g/cm³.

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what is the molecular formula for a compound that is 82.6% carbon and 17.4% hydrogen, by mass, and has a molar mass of 58.0 g/mol?

The molecular formula for the **compound **with 82.6% carbon and 17.4% hydrogen, by mass, and a **molar **mass of 58.0 g/mol is C₃H₆.

To determine the molecular formula, we first need to find the empirical formula. The **empirical formula** gives the simplest whole number ratio of atoms in a compound. To find the empirical formula, we assume 100 g of the compound, which corresponds to 82.6 g of carbon and 17.4 g of hydrogen.

Next, we convert the masses of carbon and hydrogen to moles using their respective molar masses. The molar **mass **of carbon is 12.01 g/mol, and the molar mass of hydrogen is 1.01 g/mol.

Moles of carbon = 82.6 g / 12.01 g/mol ≈ 6.88 mol

Moles of hydrogen = 17.4 g / 1.01 g/mol ≈ 17.2 mol

To find the simplest whole number ratio, we divide the number of moles by the smallest number of moles, which is approximately 6.88 mol.

Moles of carbon in empirical formula = 6.88 mol / 6.88 mol ≈ 1 mol

Moles of **hydrogen **in empirical formula = 17.2 mol / 6.88 mol ≈ 2.5 mol

Since we need whole numbers, we multiply both the carbon and hydrogen ratios by 2, giving us the empirical formula C₂H₅.

Finally, we compare the molar mass of the empirical formula to the given molar mass of 58.0 g/mol. The molar mass of C₂H₅ is approximately 29 g/mol, which is half of the given molar mass. To obtain the **molecular **formula, we multiply the empirical formula by 2, resulting in C₄H₁₀.

However, the given percentages of carbon and hydrogen indicate that there is an **unsaturation **present in the compound, suggesting a double bond between two carbon atoms. Therefore, the molecular formula is C₃H₆.

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S- A simple machine which has mechanical advantange 4 and velocity ratio 5 calculate the of the efficiency simple machine.

A **simple** **machine** which has mechanical advantange 4 and velocity ratio 5, the **efficiency** is 80%.

The effectiveness with which a **machine** transforms input energy into usable output energy is known as **efficiency**.

It is a proportion of the machine's useful work or energy output to its overall work or energy input. A **percentage** is a common way to describe effectiveness.

The **efficiency** of a simple machine, we can apply the formula:

Efficiency = (Mechanical Advantage / Velocity Ratio) × 100%

Given that

**Mechanical** **advantage** = 4 and

Velocity ratio = 5

We can substitute these values into the formula to find the asked **efficiency**.

Efficiency = (4 / 5) × 100%

Efficiency = 0.8 × 100%

Efficiency = 80%

Therefore, the **efficiency **of the simple machine is 80%.

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What kind of splitting pattern would you expect in the 1H NMR spectrum of the following compound? (Cl2CH)3CH A) A triplet downfield and a singlet upfield B) A doublet downfield and a quartet upfield C) A doublet upfield and a quartet downfield D) A singlet downfield and a triplet upfield

The correct answer is C) A **doublet upfield **and a quartet downfield.

In the given **compound** (Cl2CH)3CH, the central carbon atom, marked in parentheses, is connected to three identical methyl groups. Since the three methyl groups are chemically equivalent, they will contribute to the same NMR signal, resulting in a singlet upfield.

The neighboring chlorine atoms (Cl2CH) will cause splitting of the signal. Each chlorine atom has two adjacent protons, **resulting **in a doublet pattern. Therefore, the signal from the protons adjacent to the chlorine atoms will appear as a doublet upfield.

Overall, the NMR spectrum of the compound will show a doublet upfield (from the protons adjacent to the chlorine atoms) and a quartet downfield (from the three methyl groups).

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1A. Assume that there is half as much sodium hydroxide as acetic acid in a solution. Write the equation for this reaction.

1B. Compare the products from the equation for part A with the products the the equation. (1. 0)HF+(0. 5)NaOH -> (0. 5)HF+(0. 5)F-+(0. 5)Na+(0. 5)H2O. Is this solution a buffet? Why or why not

1A. The equation for the reaction **sodium hydroxide** as acetic acid in a solution is CH₃COOH + NaOH → CH₃COONa + H₂O

1B. If the products from the equation for part A compare with the products the equation HF + NaOH → NaF + H₂O, this solution is buffer because HF is a week acid, and F⁻ is its conjugate base.

1A. In the given question, it is assumed that there is half as much sodium hydroxide as **acetic acid** in a solution. It means that the mole ratio of sodium hydroxide to acetic acid is 1:2.

1B. The equation given below is not related to the first equation of part A.HF + NaOH → NaF + H2O

The given equation is the **neutralization** reaction between hydrofluoric acid and sodium hydroxide. The products of this reaction are sodium fluoride (NaF) and water (H₂O).

The solution given in the question is a buffer. A **buffer** is a solution that resists a change in pH when a small amount of acid or base is added to it. A buffer solution is prepared by mixing a weak acid and its conjugate base or a weak base and its conjugate acid. In the given solution, HF is a weak acid, and F⁻ is its conjugate base. Sodium fluoride (NaF) is a salt of this weak acid. Hence, it is a buffer solution.

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For the following electron-transfer reaction:

Cu(s) + 2Ag+(aq) Cu2+(aq) + 2Ag(s)

The oxidation half-reaction is:

The reduction half-reaction is:

What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Cl2 pressure is 1.30 atm, the Cl- concentration is 4.31×10-3M, and the Ag+ concentration is 8.41×10-4M ?

Cl2(g) + 2Ag(s)2.00Cl-(aq) + 2Ag+(aq)

The calculated value of the** cell potential** at 298K for an **electrochemical **cell with the given reaction, when the Cl2 pressure is 1.30 atm, the Cl- concentration is 4.31×10-3M, and the Ag+ concentration is 8.41×10-4M is 1.65 V.

Given:

Cu(s) + 2Ag+(aq) Cu2+(aq) + 2Ag(s)

Oxidation half-reaction: Cu(s) → Cu2+(aq) + 2e-

Reduction half-reaction: 2Ag+(aq) + 2e- → 2Ag(s)

The cell potential can be calculated using the** Nernst equation **given by:Ecell = E°cell – (RT / nF)

ln Q where E°cell is the standard cell potential,R is the gas constant

T is the temperature n is the number of electrons transferred

F is the Faraday constantQ is the reaction quotient

Q = [Cu2+ ] / [Ag+]2E°cell for the given reaction can be calculated by:E°cell = E°cathode – E°anode = E°red, cathode – E°red, anodeE°red,

cathode for the reduction half-reaction is the **standard reduction potential** of Ag+ which is 0.80 V and E°red,

anode for the oxidation half-reaction is the standard reduction potential of Cu2+ which is 0.34

V.E°cell = 0.80 - 0.34 = 0.46 VNow, to use the Nernst equation,

we need to calculate Q using the given **concentration **and pressure.Q = [Cl- ]2 [Ag+]2 / P(Cl2)Q = (4.31 × 10-3)2 (8.41 × 10-4)2 / 1.30Q = 9.364 × 10-16

Substitute all the given values in the Nernst equation

:Ecell = E°cell – (RT / nF)

ln Q= 0.46 – (0.0257 / 2) ln (9.364 × 10-16)

Ecell = 0.46 V – (-1.19)

Ecell = 1.65 V

Therefore, the calculated value of the cell potential at 298K for an electrochemical cell with the given reaction, when the Cl2 pressure is 1.30 atm, the Cl- concentration is 4.31×10-3M, and the Ag+ concentration is 8.41×10-4M is 1.65 V.

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Please answer the 3 questions with an explanation provided

This Subject is Chemistry Stoichiometry Exit ticket moles & mass

The **moles **of [tex]H_2[/tex] required to produce 4.00 moles of [tex]NH_3[/tex] is 6.00 moles.The **mass **of [tex]H_2O[/tex] that can be produced by reacting 0.26 moles of [tex]CH_4[/tex] is 9.37 gramsThe **mass **of [tex]O_2[/tex] that can be created if 9.6 grams of [tex]H_2O[/tex] is produced is 8.64 grams.Stoichiometric problem

(1) From the **balanced equation**, 2 moles of [tex]NH_3[/tex] require 3 moles of [tex]H_2[/tex]. Following this ratio, 4 moles of [tex]NH_3[/tex] will require 6 moles of [tex]H_2[/tex].

(2) The **mole ratio** of [tex]CH_4[/tex] and water is 1:2. Thus, 0.26 moles of [tex]CH_4[/tex] will produce:

0.26 x 2 = 0.52 moles of [tex]H_2O[/tex]

**Mass **of 0.52 moles [tex]H_2O[/tex] = 18.02 x 0.52

= 9.37 grams

(3) The **mole ratio** of [tex]H_2O[/tex] and [tex]O_2[/tex] is 2:1.

9.6 grams of [tex]H_2O[/tex] = 9.6/18.02 = 0.53 moles

Equivalent mole of [tex]O_2[/tex] = 0.53/2 = 0.27 moles

**Mass **of 0.27 moles [tex]O_2[/tex] = 0.27 x 32 = 8.64 grams.

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what+is+the+composition,+in+weight+percent,+of+an+alloy+that+consists+of+5+at%+cu+and+95+at%+pt?

The **composition **in weight percent of the alloy is **approximately **2.15% Cu and 97.85% Pt.

To determine the **composition **in weight percent of an **alloy **consisting of 5 at% Cu and 95 at% Pt, we need to convert the atomic percentages to weight percentages. The **atomic percentages **can be directly converted to **weight percentages **because the atomic masses of Cu and Pt are known. The atomic mass of Cu is 63.55 g/mol, and the atomic mass of Pt is 195.08 g/mol.

The weight percentage of Cu in the alloy can be calculated as:

Weight percentage of Cu = (Atomic percentage of Cu × Atomic mass of Cu) / (Total atomic mass of the alloy)

Weight percentage of Cu = (5 at% Cu × 63.55 g/mol) / [(5 at% Cu × 63.55 g/mol) + (95 at% Pt × 195.08 g/mol)]

Similarly, the weight percentage of Pt can be calculated as:

Weight percentage of Pt = (95 at% Pt × 195.08 g/mol) / [(5 at% Cu × 63.55 g/mol) + (95 at% Pt × 195.08 g/mol)]

Calculating these values:

Weight percentage of Cu ≈ 2.15%

Weight percentage of Pt ≈ 97.85%

Therefore, the composition in weight percent of the alloy is approximately 2.15% Cu and 97.85% Pt.

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which of the following statement is incorrect?group of answer choices a) in coarse-grained multithreading switching between threads only happens after significant events such as last-level cache fine-grained. b) multithreading switching between threads happens after every instruction. c) simultaneous multithreading (smt) uses threads to improve resource utilization of statically scheduled. d) multithreading and multicore rely on parallelism to get more efficiency from a chip.

The incorrect statement among the given options is option B. **Multithreading** switching between threads does not happen after every instruction.

The incorrect statement among the given options is option B. Multithreading switching between **threads** does not happen after every instruction. In fact, in fine-grained multithreading, switching between threads occurs after every cycle. Coarse-grained multithreading involves switching between threads after significant events such as cache misses or branch mispredictions, while fine-grained multithreading involves switching between threads after every cycle. Simultaneous multithreading (SMT) is a technique that uses threads to improve resource utilization of dynamically scheduled processors. Multithreading and multicore both rely on parallelism to get more efficiency from a chip. Parallelism refers to the ability of a system to execute multiple tasks simultaneously. Multithreading and multicore both achieve **parallelism** in different ways, with multithreading using multiple threads within a single core, while multicore uses multiple cores to achieve parallelism. In summary, option B is incorrect as multithreading switching between threads does not happen after every instruction.

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When constructing a galvanic cell using a standard hydrogen electrode, the SHE always operates as which of the following? Select the correct answer below: A. the cathode B. the anode C. an active electrode D. depends on the nature of the reactants or the nature of the other electrode

The correct answer is ( A) the** cathode**. When constructing a galvanic cell, the standard hydrogen electrode (SHE) always operates as the cathode.

In a **galvanic **cell, the standard hydrogen electrode (SHE) is always used as the reference electrode, and it is conventionally assigned as the cathode. The SHE consists of a platinum** electrode** immersed in a solution of 1 M H+ ions with a partial pressure of hydrogen gas (1 atm).

The SHE serves as a standard reference for measuring the reduction potentials of other half-reactions in the cell. By convention, the reduction potential of the SHE is defined as zero **volts**. Therefore, in comparison to the SHE, other half-reactions will have positive or negative reduction potentials.

When constructing a galvanic cell, the standard hydrogen electrode (SHE) always operates as the cathode. It serves as a reference electrode with a defined reduction potential of zero volts.

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if you burn 100 grams of methane and produce 10 grams of carbon monoxide, what is the total mass of products

The total **mass** of products, including 10 grams of CO and 90 grams of H2O, is 100 grams.

The total mass of products from burning 100 grams of methane and producing 10 grams of carbon **monoxide** is 110 grams. To answer question, we'll use the law of conservation of mass, which states that the total mass of reactants equals the total mass of products in a chemical **reaction**. In this case, 100 grams of methane (CH4) are burned, producing 10 grams of carbon monoxide (CO). We must find the mass of the other product, which is water (H2O). Since we know that 10 grams of CO are produced, the mass of H2O can be calculated as follows: 100 grams (initial mass of CH4) - 10 grams (mass of CO produced) = 90 grams of H2O. Therefore, the total mass of products, including 10 grams of CO and 90 grams of H2O, is 100 grams.

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A) Write a balanced equation depicting the formation of one mole of NO2(g) from its elements in their standard states. Express your answer as a chemical equation. Identify all of the phases in your answer.

B) Write a balanced equation depicting the formation of one mole of SO3(g) from its elements in their standard states. Express your answer as a chemical equation. Identify all of the phases in your answer.

C) Write a balanced equation depicting the formation of one mole of NaBr(s) from its elements in their standard states. Express your answer as a chemical equation. Identify all of the phases in your answer.

D) Write a balanced equation depicting the formation of one mole of Pb(NO3)2(s) from its elements in their standard states.

The **balanced** equations with one **mole** are: A) [tex]N_2(g) + O_2(g) - > 2NO_2(g)[/tex], B) [tex]S(s) + O_2(g) - > SO_3(g)[/tex], C) [tex]Na(s) + 1/2Br_2(l) - > NaBr(s)[/tex] and D)[tex]Pb(s) + 2HNO_3(aq) - > Pb(NO_3)_2(s) + H_2(g)[/tex]

A) The balanced equation depicting the formation of one mole of NO2(g) from its **elements** in their standard states is:

[tex]N_2(g) + O_2(g) - > 2NO_2(g)[/tex]

B) The balanced equation depicting the formation of one mole of SO3(g) from its elements in their **standard states** is:

[tex]S(s) + O_2(g) - > SO_3(g)[/tex]

C) The balanced equation depicting the formation of one mole of NaBr(s) from its elements in their standard states is:

[tex]Na(s) + 1/2Br_2(l) - > NaBr(s)[/tex]

D) The balanced equation depicting the formation of one **mole** of Pb(NO3)2(s) from its elements in their standard states is:

[tex]Pb(s) + 2HNO_3(aq) - > Pb(NO_3)_2(s) + H_2(g)[/tex]

The **phases** of the elements and compounds are indicated in parentheses, where (g) represents gas, (s) represents solid, (l) represents liquid, and (aq) represents aqueous solution.

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write the oxidation state for the underlined element in the box following each compound.

a) NaH

b) KNO3

c) Na2PtCI6

d) Ca3(PO3)2

e) NA(NCS)

The oxidation state of **Na **in NaH is +1, N in [tex]KNO_3[/tex] is +5, Pt in [tex]Na_2PtCl_6[/tex] is approximately +2/3, P in [tex]Ca_3(PO_3)_2[/tex] is -3 and **N **in Na(NCS) is -2.

A) NaH: The **oxidation state **of hydrogen (H) is typically -1 in compounds, so the oxidation state of Na in NaH is +1.

b) [tex]KNO_3[/tex] : The oxidation state of **potassium **(K) is +1 in compounds, the oxidation state of nitrogen (N) in[tex]NO_3[/tex] is +5, and the oxidation state of oxygen (O) is -2 in compounds. Therefore, the oxidation state of N in [tex]KNO_3[/tex]is +5.

c) [tex]Na_2PtCl_6[/tex] : The oxidation state of sodium (Na) is +1 in compounds, the oxidation state of **chlorine **(Cl) is typically -1 in compounds, and the sum of oxidation states in a neutral compound is zero. Since the overall compound is neutral, the oxidation state of platinum (Pt) can be calculated as follows:

2(+1) + 6(x) + 6(-1) = 0

2 + 6x – 6 = 0

6x – 4 = 0

6x = 4

X ≈ +2/3

So, the oxidation state of Pt in[tex]Na_2PtCl_6[/tex] s approximately +2/3.

d) [tex]Ca_3(PO_3)_2[/tex] : The oxidation state of **calcium **(Ca) is +2 in compounds, and the oxidation state of oxygen (O) is typically -2 in compounds. The phosphate ion (PO3) has an overall charge of -3. Therefore, the oxidation state of phosphorus (P) in [tex]Ca_3(PO_3)_2[/tex] can be calculated as follows:

3(+2) + 2(x) = 0

6 + 2x = 0

2x = -6

X = -3

So, the oxidation state of P in [tex]Ca_3(PO_3)_2[/tex] is -3.

e) Na(NCS): The oxidation state of sodium (Na) is +1 in compounds, and the oxidation state of sulfur (S) in thiocyanate (NCS) is typically -2. Therefore, the oxidation state of N in Na(NCS) is -2.

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Write the equation showing the formation of a monosubstituted product when 2,3-dimethylbutane reacts with chlorine. Use molecular formulas for the organic compounds (C before H, halogen last) and the smallest possible integer coefficients.

The equation showing the formation of a monosubstituted product when 2,**3-dimethylbutane **reacts with chlorine can be **represented** as follows:

C6H14 + Cl2 -> C6H13Cl + HCl

In this equation, 2,3-dimethylbutane (C6H14) reacts with chlorine (Cl2) to produce a monosubstituted product, which is 2-chloro-3,3-dimethylbutane (C6H13Cl) and **hydrogen chloride** (HCl) as a byproduct.

Please note that the structural arrangement of the substituents on the carbon backbone may vary, but the overall** chemical equation **represents the general substitution reaction between 2,3-dimethylbutane and chlorine.

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what is the total number of moles of o2 g that must react completely with 8 moles of al in order to form al2o3

6 **moles** of O2 gas are required to react completely with 8 moles of Al to form Al2O3.

The balanced **chemical equation** for the reaction between aluminum and oxygen to form aluminum oxide is 4Al + 3O2 → 2Al2O3. From this equation, we can see that 3 moles of O2 are required for every 4 moles of Al that react. Therefore, to completely react with 8 moles of Al, we would need (3/4) x 8 = 6 moles of O2. So, the total number of moles of O2 that must react completely with 8 moles of Al in order to form Al2O3 is 6 moles.

To determine the total number of moles of O2 gas needed to react completely with 8 moles of Al to form Al2O3, we must first consider the balanced chemical equation:

4Al + 3O2 → 2Al2O3

From the equation, we can see that 4 moles of Al react with 3 moles of O2. To find the amount of O2 needed for 8 moles of Al, we can set up a proportion:

(3 moles O2 / 4 moles Al) = (x moles O2 / 8 moles Al)

By solving for x, we find that:

x = (3 moles O2 / 4 moles Al) × 8 moles Al = 6 moles O2

Thus, 6 moles of O2 **gas** are required to react completely with 8 moles of Al to form Al2O3.

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Consider the reactions below. Which of the following correctly identifies the coordinate complex? Select the correct answer below: O SO3 in 02- + SO3 + S02 02- in 02- + S03 +502 BH3 in (CH3), S +BH3 → H3BS(CH3), O Becl in BeCl2 +201 Beci - NA MODE INSTRUCT

Out of the given reactions, the correct identification of the **coordinate complex** is BH3 in (CH3)2S + BH3 → H3BS(CH3)2. In this reaction, BH3 acts as a Lewis acid and coordinates with the lone pair of electrons present on the S atom in (CH3)2S to form a coordinate complex.

The BH3 molecule is a **Lewis acid** as it has an incomplete octet and can accept a pair of electrons from a Lewis base. In the other two reactions, there are no coordination complexes formed.

BeCl2 is not involved in the formation of a coordination complex in the given reactions. It is a molecule that exists as a linear shape due to its sp hybridization. The two Cl **atoms** are directly bonded to the central Be atom through a single bond. BeCl2 is not a Lewis acid as it does not have an incomplete octet and cannot accept a pair of **electrons** from a Lewis base to form a coordination complex.

In conclusion, the correct identification of the coordinate complex is BH3 in (CH3)2S + BH3 → H3BS(CH3)2, and BeCl2 is not involved in the formation of a coordination complex in the given reactions.

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**Answer:**

BeCl2−4 in BeCl2 + 2Cl → BeCl2−4

**Explanation:**

In a Lewis acid-base reaction, the coordinate complex is the compound that is generated by the formation of coordinate covalent bond(s) between the Lewis acid and the Lewis base.

How many rings does an alkane have if its formula is C11H18?

An alkane with the formula C11H18 would have two rings. An **alkane **is a type of **hydrocarbon** that only contains single bonds between its **carbon atoms**.

It is a saturated hydrocarbon and has the general formula CnH2n+2. To determine how many rings an alkane has based on its formula, we need to first find out the value of n in the formula. In the given formula, C11H18, we can see that n is equal to 11. Therefore, the general formula for this **alkane **would be C11H2(11)+2, which simplifies to C11H24. Since this is an alkane, we know that all of the **carbon-carbon bonds** are single bonds, which means there are no rings present in the **molecule**. Therefore, an alkane with the formula C11H18 does not have any rings in its structure. Its carbon atoms are connected in a straight chain, with each carbon atom being bonded to two other carbon atoms and two hydrogen atoms.

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At 37 degree Celsius, the dissociation constant, Kw of water is 2.5 x 10-14 (pKw= 13.6). What is the pH of a 1.0 x 10-5 M NaOH solution at 37 degree celcius? (a) 4.6 (b) 5.0 (c) 8.6 (d) 9.0 (e) 13.6

The pH of a 1.0 x 10-5 M NaOH solution at 37 degrees Celsius is approximately 9.0. The **pH **of a solution can be determined using the **pOH value**, which is related to the concentration of **hydroxide ions** (OH-) in the solution.

The pOH is calculated using the following equation pOH = pKw - log[OH-]

We can calculate the** pOH:**

pOH = 13.6 - log(1.0 x 10^-5)

= 13.6 + 5

= 18.6

Since pH + pOH = 14 (at 25 °C), we can calculate the** pH:**

pH = 14 - pOH

= 14 - 18.6

= -4.6

Since pH values are typically positive, we can adjust it to a **positive value**:

pH = 14 + (-4.6)

= 9.4

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A region, in the first quadrant, is enclosed by. y = - 2? + 8 Find the volume of the solid obtained by rotating the region about the line = 7.
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