gi is a g protein that inhibits adenylate cyclase in response to ligand activation. a toxic bacterial enzyme enters cells and covalently alters the a subunit of gi so that it cannot release bound gdp in response to receptor activation by ligand. which of the following will happen in the cell (consult the g protein cycle slide in your powerpoint for help)(select one)? group of answer choices a) the g protein remains bound to the ligand-activated receptor. b) the receptor cannot communicate with the adenylate cyclase enzyme c) cellular levels of camp are elevated. d) all the above e) a and b

Answers

Answer 1

The correct option is: e) a and b. a) the g protein remains bound to the ligand-activated receptor. b) the receptor cannot communicate with the adenylate cyclase enzyme

In the G protein cycle, the G protein is activated when the ligand (receptor activator) binds to the receptor.

Upon activation, the G protein exchanges its bound GDP (guanosine diphosphate) for GTP (guanosine triphosphate), leading to the dissociation of the G protein into its subunits (Gα and Gβγ).

The subunit, now bound to GTP, can then interact with downstream effectors, such as adenylate cyclase.

In this scenario, the toxic bacterial enzyme covalently alters the α subunit of Gi (an inhibitory G protein), preventing it from releasing bound GDP. As a result, the G protein cycle is disrupted. Here's what happens:

The G protein remains bound to the ligand-activated receptor:

Since the α subunit of Gi cannot release bound GDP, it remains associated with the receptor, even after ligand activation.

This disrupts the normal cycle where the G protein dissociates from the receptor after activation.

The receptor cannot communicate with the adenylate cyclase enzyme:

In the normal G protein cycle, the activated Gα subunit, bound to GTP, interacts with adenylate cyclase to inhibit its activity.

However, in this case, as the α subunit of Gi is unable to release bound GDP, it cannot interact with adenylate cyclase to inhibit its function.

Therefore, the receptor cannot effectively communicate with the adenylate cyclase enzyme.

Cellular levels of cAMP are elevated:

Adenylate cyclase is responsible for producing cyclic adenosine monophosphate (cAMP) from ATP.

In the absence of inhibition by the Gα subunit, the activity of adenylate cyclase is not regulated properly, leading to increased production of cAMP.

Therefore, cellular levels of cAMP are elevated.

In conclusion, when the α subunit of Gi is covalently altered and unable to release bound GDP, both the G protein remaining bound to the ligand-activated receptor and the impaired communication between the receptor and adenylate cyclase enzyme occur. This disruption ultimately leads to elevated cellular levels of cAMP.

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Related Questions

What important discovery was made by Columbia University researchers concerning carbon dioxide levels using data from Biosphere 2?
A. The world's ocean can serve as a endless sink of atmospheric carbon dioxide with little effect on biological organisms.
B. Carbon dioxide levels will decrease naturally in both air and water in a contained system such as Biosphere 2.
C. Carbon dioxide in the atmosphere is absorbing atmospheric oxygen.
D. Carbon dioxide in the atmosphere is absorbed into water causing ocean acidification.

Answers

Your answer: D. Carbon dioxide in the atmosphere is absorbed into water causing ocean acidification.

The atmosphere is the layer of gases that surrounds a planet and is held in place by gravity. Earth's atmosphere consists mainly of nitrogen (78%) and oxygen (21%), along with trace amounts of other gases such as carbon dioxide, water vapor, and noble gases. The atmosphere serves several vital functions, including providing oxygen for respiration, protecting the planet from harmful solar radiation, regulating temperature through the greenhouse effect, and enabling weather and climate patterns. It acts as a buffer between outer space and the Earth's surface, supporting life and facilitating various atmospheric phenomena, such as cloud formation, precipitation, and air circulation. The atmosphere is divided into distinct layers, each with its own characteristics and roles in Earth's overall system.

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Which of the following is true of both mitochondria and chloroplasts?
A. They are only found in eukaryotic autotrophs
B. They are only found in eukaryotic heterotrophs
C. They are only found in prokaryotes
D. They are found in both eukaryotic autotrophs and heterotrophs

Answers

The true option for mitochondria and chloroplast is D. They are found in both eukaryotic autotrophs and heterotrophs.

Mitochondria and chloroplasts are organelles found in eukaryotic cells. Mitochondria are responsible for cellular respiration and produce ATP, while chloroplasts are responsible for photosynthesis and produce glucose. Both of these organelles have their own DNA and are believed to have evolved from free-living prokaryotes through endosymbiosis. Therefore, they are found in both eukaryotic autotrophs (organisms that produce their own food) and heterotrophs (organisms that consume other organisms for food).

Mitochondria and chloroplasts are important organelles found in eukaryotic cells and are responsible for crucial cellular processes. They are found in both eukaryotic autotrophs and heterotrophs, indicating their significance in the evolution and survival of diverse organisms.

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what structures monitor the level of oxygen in arterial blood

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The structures that monitor the level of oxygen in arterial blood are called chemoreceptors.

There are two types of chemoreceptors involved in oxygen monitoring: peripheral chemoreceptors and central chemoreceptors. Peripheral chemoreceptors are located in the carotid arteries and the aortic arch, and they respond to changes in oxygen levels by sending signals to the brainstem to adjust breathing rate and depth.

                            Central chemoreceptors are located in the brainstem and they respond to changes in carbon dioxide levels, which indirectly reflect changes in oxygen levels. Both types of chemoreceptors play a critical role in maintaining oxygen homeostasis in the body.
                                 The structures that monitor the level of oxygen in arterial blood are called chemoreceptors. Specifically, there are two main types of chemoreceptors involved in monitoring arterial oxygen levels: peripheral chemoreceptors and central chemoreceptors.

                                         Peripheral chemoreceptors are located in the carotid bodies and aortic bodies, while central chemoreceptors are located in the medulla oblongata of the brainstem. These structures detect changes in oxygen levels and send signals to the respiratory center in the brain, which then adjusts the breathing rate and depth to maintain appropriate oxygen levels.

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Pyruvate dehydrogenase (PDH) catalyzes acetyl-CoA from pyruvate, CoA, and NAD+. Which of the following statements are correct?
a) PDH is inhibited by high levels of ATP and NADH.
b) PDH is stimulated by high levels of ADP and NAD+.
c) PDH is found only in the mitochondria.
d) PDH is involved in the citric acid cycle.

Answers

The correct statements are a) Pyruvate dehydrogenase (PDH) is inhibited by high levels of ATP and NADH, b) PDH is stimulated by high levels of ADP and NAD+, and c) PDH is found only in the mitochondria.

a) PDH is inhibited by high levels of ATP and NADH because they signify that there is sufficient energy available in the cell, thus slowing down the conversion of pyruvate to acetyl-CoA to conserve resources.

b) PDH is stimulated by high levels of ADP and NAD+ because they indicate that the cell needs more energy. This triggers the activation of PDH, leading to the production of acetyl-CoA, which is used in the citric acid cycle to generate more ATP.

c) PDH is found only in the mitochondria, as it is the location where the citric acid cycle occurs and where acetyl-CoA is required as a substrate.

d) While PDH is indirectly related to the citric acid cycle through the production of acetyl-CoA, it is not directly involved in the cycle itself, making this statement incorrect.

Statements a, b, and c are correct regarding the function and location of pyruvate dehydrogenase (PDH).

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FILL THE BLANK. The male secretory structures that produce a fluid necessary for adequate sperm motility after ejaculation are called the ______.

Answers

Answer:

seminal vesicles and prostate gland

Explanation:

The male secretory structures that produce a fluid necessary for adequate sperm motility after ejaculation are called the seminal vesicles and prostate gland.

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The male secretory structures that produce a fluid necessary for adequate sperm motility after ejaculation are called the seminal vesicles.

The seminal vesicles are a pair of male reproductive organs located behind the bladder and connected to the vas deferens. They are responsible for producing and storing a significant portion of the seminal fluid, which is released during ejaculation. The fluid produced by the seminal vesicles contains various substances, including fructose, prostaglandins, and enzymes. These components provide nourishment and energy for sperm, aid in their motility, and help create a suitable environment for fertilization.

The seminal vesicles contribute to the overall volume and composition of semen, which is the fluid that carries and nourishes sperm during ejaculation. Their secretions combine with sperm from the testes and fluids from other accessory glands, such as the prostate gland and bulbourethral glands, to form semen. The proper functioning of the seminal vesicles is crucial for the fertility and reproductive capacity of males.

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If P represents the allele for purple flowers and p represents the allele for white flowers, then which represents a heterozygous genotype?
A. PP
B. pp
C. Pp
D. PPP

Answers

If P represents the allele for purple flowers and p represents the allele for white flowers, then heterozygous genotype would be represented by C) Pp. Hence option C) is the correct answer.

The heterozygous genotype for purple and white flowers would be represented by the genotype Pp. This genotype indicates that the individual has one copy of the P allele and one copy of the p allele. It is important to note that a heterozygous genotype can also be written as P/p or p/P. It is only homozygous genotypes that are written with two of the same letters (e.g. PP or pp).

A heterozygous genotype contains two different alleles for a particular gene. In this case, P represents the allele for purple flowers and p represents the allele for white flowers. Therefore, a heterozygous genotype would be represented by Pp.

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Intravenous solutions (IV) must be prepared so that they are isotonic to red blood cells. A 0.9% salt solution is isotonic to red blood cells.
a.Explain what will happen to a red blood cell placed in a solution of 99.3% water and 0.7% salt.
b.What will happen to a red blood cell placed in a solution of 90% water and 10% salt?

Answers

A. Red blood cells must be isotonic with intravenous solutions (IV) before administration. b. If a red blood cell is submerged in a 90/10 solution of water and salt, water will leak out of the cell.  

Red blood cells submerged in a fluid containing 99.3% water and 0.7% salt will experience water infiltration. The test tube's salt solution would cause the red blood cell to shrink as it lost water. Anything higher than 0.9% NaCl would be hypertonic if 0.9% was isotonic to a cell. NaCl 0.9% is equivalent to this. In isotonic NaCl, the volume of the red blood cell is normal. NaCl 0.9% results in an opaque suspension because erythrocytes are not destroyed.

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Adapoids and Omomyoids divided food type resources as a way to avoid competion, driving species development further away from each other. This is seen as what?
a. An example of a selective pressure that may have favored the strepsirhine and haplorhine split
b. A precursor to bipedalism
c. A response to the geologic transition to open Savannahs
d. Early use of tools to hunt and eat meat

Answers

Adapoids and Omomyoids divided food type resources as a way to avoid competion, driving species development further away from each other. a. An example of a selective pressure that may have favored the strepsirhine and haplorhine split.

Adapoids and Omomyoids dividing food type resources as a way to avoid competition and driving species development further away from each other is an example of niche differentiation or resource partitioning.

Niche differentiation refers to the process in which species with similar resource requirements partition or divide the available resources in their environment to minimize competition and maximize their own fitness. Adapoids and Omomyoids were two groups of primates that coexisted during the Eocene epoch. They exhibited distinct differences in their dentition and jaw morphology, suggesting specialization in different types of food resources.

Adapoids were adapted to a diet primarily consisting of leaves, fruits, and other plant materials, while Omomyoids had dental and jaw adaptations suited for consuming insects and other small prey. By utilizing different food resources, they were able to reduce competition for limited food sources and coexist in the same habitat without directly competing with each other.

This niche differentiation likely drove further evolutionary divergence between the two groups, as they occupied different ecological niches and faced different selective pressures related to their respective diets. Over time, this differentiation may have led to the development of more specialized adaptations within each group, further separating them from one another.

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Letter to Government regarding Solutions to Fl ecologiral issues. Help me please I need to submit it before 12

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To the government, a formal letter describing suggested solutions to ecological issues should be addressed.

Environmental and ecological issues are issues that affect the environment and its ecosystems. These problems frequently concern the interplay of human activities with the environment. It has negative impacts on the balance and efficiency of ecosystems. Environmental laws can be passed to resolve them.

A formal letter is a kind of written communication that follows a precise format and tone. It is typically used for official or professional purposes, such as in business, academia, government, or legal settings.

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Look at the graph. It shows how light intensity affects the rate of photosynthesis. The lines show different carbon dioxide concentrations and temperatures. Rate of photosynthesis 2.4 30°C, 0.2%CO,. 30°C, 0.1%CO₂ 20 °C, 0.1%CO₂ -B- Light Intensity Explain what is limiting the rate of photosynthesis at the three points A, B and C on the graph. Use evidence from the graph in your answer. (3)​

Answers

At factor B, the parameters are 30°C temperature and 0.11% CO2 attention, and the rate of photosynthesis is roughly 0.2 gadgets.

To determine what is limiting the fee of photosynthesis at factors A, B, and C on the graph, we want to investigate the evidence furnished by the graph. Let's have a look at each factor:

A: At point A, the fee of photosynthesis is two.4 units, and the situations are 30°C temperature and zero.2% carbon dioxide (CO₂) concentration.

Looking at the graph, we can see that the charge of photosynthesis at point A is not restricted by using light depth.

The line for factor A is particularly flat, indicating that as light depth increases, the price of photosynthesis stays constant. Therefore, mild depth isn't the limiting factor at factor A.

Thus, at factor B, the price of photosynthesis is approximately 0.2 gadgets, and the conditions are 30°C temperature and zero.1% CO₂ attention.

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Your question seems incomplete, the probable complete question is:

Look at the graph. It shows how light intensity affects the rate of photosynthesis. The lines show different carbon dioxide concentrations and temperatures. Rate of photosynthesis 2.4 30°C, 0.2%CO,. 30°C, 0.1%CO₂ 20 °C, 0.1%CO₂ -B- Light Intensity Explain what is limiting the rate of photosynthesis at the three points A, B and C on the graph. Use evidence from the graph in your answer. (3)​

Which antibiotic resistance mechanism is exemplified by beta-lactamase?
a. modify the target so that it no longer binds the antibiotic
b. pump the antibiotic out of the cell
c. destroy the antibiotic before it gets into the cell
d. add modifying groups that inactivate the antibiotic

Answers

The antibiotic resistance mechanism exemplified by beta-lactamase is option (d): add modifying groups that inactivate the antibiotic.

Beta-lactamase is an enzyme produced by certain bacteria that confers resistance to beta-lactam antibiotics, such as penicillins and cephalosporins. This enzyme hydrolyzes the beta-lactam ring structure present in these antibiotics, rendering them inactive. By adding modifying groups, beta-lactamase disrupts the structure of the antibiotic, preventing it from effectively targeting and inhibiting the growth of bacteria.

The action of beta-lactamase can be understood through its interaction with beta-lactam antibiotics, which contain a beta-lactam ring. The beta-lactamase enzyme recognizes and binds to the antibiotic molecule. It then catalyzes a hydrolytic reaction, breaking the beta-lactam ring and rendering the antibiotic inactive. This modification prevents the antibiotic from effectively inhibiting the synthesis of bacterial cell walls, which is its primary mechanism of action. Consequently, bacteria that produce beta-lactamase are able to survive and multiply in the presence of beta-lactam antibiotics, leading to antibiotic resistance.

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This principle describes how someone who knows how to perform a back squat will more easily learn an overhead squat because the basic framework for the movement has already been learned and it only needs to be adapted to the new skill.
a. Motor program theory
b. Generalized motor program
c. Homunculus
d. Movement pattern
e. Short-term retention

Answers

The Generalized Motor Program theory suggests that motor skills are represented in the central nervous system as a generalized pattern or blueprint for movement. The correct option is B.

This blueprint contains the fundamental features and structure of a specific motor skill. When learning a new skill that shares similarities with a previously learned skill, the existing GMP can be modified or adapted to perform the new movement.

The principle that describes how someone who knows how to perform a back squat will more easily learn an overhead squat because the basic framework for the movement has already been learned and only needs to be adapted to the new skill is referred to as the Generalized Motor Program (GMP).  

In this case, the GMP for the back squat provides the foundational framework for understanding the basic mechanics and movement patterns involved in squatting.

This knowledge can be transferred and applied to the overhead squat, with adjustments made to accommodate the specific demands of the new skill.

Short-term retention, on the other hand, refers to the temporary storage and recall of recently acquired information or skills. It is not directly related to the principle described in the scenario. Therefore, the correct option is B.

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quizelet the ------glands are a source of sex phermon; a- cerumenou b- mammary merocrine c- merocrine d- sebaceous d- apocrine

Answers

The apocrine glands are a source of sex pheromones.

Pheromones are chemical substances secreted by organisms to communicate with others of the same species. In humans, apocrine glands are one of the types of sweat glands found in areas such as the armpits, groin, and areolae of the breasts. These glands produce a thick, odorless secretion that contains various chemicals, including sex pheromones. The release of these pheromones can play a role in attracting potential mates and signaling sexual readiness. Other options listed in the question, such as ceruminous glands (found in the ear canal), mammary glands (produce breast milk), merocrine glands (release sweat), and sebaceous glands (secrete sebum), are not specifically associated with the production of sex pheromones.

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development and growth of structures follows the direction of head to tail, referred to as cephalocaudal development and from inside out, called

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Development and growth of structures in organisms follow two main patterns: cephalocaudal development, which proceeds from head to tail, and proximodistal development, which occurs from the inside out.

Cephalocaudal development refers to the process in which growth and development occur in a sequential manner from the head (cephalic region) to the tail (caudal region) of an organism. This pattern is observed in various aspects of development, such as the formation of the brain and nervous system, facial features, and the spinal cord. For example, during embryonic development, the head region develops before the lower body regions.

Proximodistal development, on the other hand, describes the growth and development of structures from the inside (proximal) to the outside (distal) of an organism. This pattern can be observed in the development of limbs, where the internal skeletal structure forms first, followed by the development of muscles, and finally the growth of skin and other external features.

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What is the relationship between cell division, cell differentiation, and gene regulation? - Cell division alone is sufficient for embryonic development--each division provides an opportunity to generate unique cells with different patterns of gene expression. - Cell division is the process of regulating transcription and translation and is necessary throughout development: gene regulation is only necessary during fertilization. - Cell division alone would result in a big ball of undifferentiated cells. Cell differentiation occurs as a result of regulation of the expression of certain genes, leading to specialized structure and function of cells - Cell division only occurs during cleavage after the blastula is formed cell differentiation via cene regulation is used to form tissue layers

Answers

The relationship between cell division and gene regulation is Cell differentiation, which leads to specialized structure and function of cells, occurs through the regulation of gene expression. Option C is correct.

C. Cell division alone would result in a big ball of undifferentiated cells. Cell differentiation occurs as a result of the regulation of the expression of certain genes, leading to specialized structure and function of cells. During development, cells undergo a process called cell differentiation, where they become specialized and acquire specific functions. This process is tightly regulated by gene expression, which determines which genes are turned on or off in a cell, leading to the development of specific cell types.

Cell division is responsible for increasing the number of cells during development, but it alone does not determine cell specialization. Instead, gene regulation plays a critical role in guiding cells to differentiate into specific cell types with distinct characteristics. Gene regulation involves mechanisms such as transcription factors, epigenetic modifications, and signaling pathways that control the expression of genes at different stages of development. Through gene apoptosis regulation, cells acquire the necessary instructions to differentiate into various cell types, forming tissues, organs, and ultimately the whole organism.

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The complete question is

What is the relationship between cell division, cell differentiation, and gene regulation? -

A. Cell division alone is sufficient for embryonic development--each division provides an opportunity to generate unique cells with different patterns of gene expression. -

B. Cell division is the process of regulating transcription and translation and is necessary throughout development: gene regulation is only necessary during fertilization. -

C. Cell division alone would result in a big ball of undifferentiated cells. Cell differentiation occurs as a result of regulation of the expression of certain genes, leading to specialized structure and function of cells -

D. Cell division only occurs during cleavage after the blastula is formed cell differentiation via cene regulation is used to form tissue layers

the most versatile method for sterilizing heat-sensitive liquids is

Answers

Answer:

Filtration

Explanation:

The most versatile method for sterilizing heat-sensitive liquids is Filtration.

Hope this helps!

commercial refrigeration equipment for eggs produce and dairy uses

Answers

When it comes to commercial refrigeration equipment for eggs, produce, and dairy, there are a few options to consider. Egg Coolers,Reach-in Refrigerators,Walk-in Coolers,Milk Coolers,Dairy Display Cases

Here are some commonly used types of refrigeration equipment for each category:

Eggs:

Egg Coolers: These specialized refrigeration units are designed specifically for storing eggs at the optimal temperature and humidity levels. They typically feature adjustable shelves or trays to accommodate different egg sizes.

Produce:

Reach-in Refrigerators: These refrigerators are ideal for storing fruits and vegetables. They come in various sizes and configurations, with adjustable shelves and humidity controls to maintain the freshness of produce.

Walk-in Coolers: These larger refrigeration units provide ample space for storing a large quantity of produce. They offer better organization and accessibility, making it easier to manage inventory.

Dairy:

Milk Coolers: These refrigeration units are designed to store large quantities of milk at a consistent temperature. They often have adjustable shelves and glass doors for easy visibility.

Dairy Display Cases: These cases are specifically designed to showcase dairy products, such as yogurt, cheese, and butter, while keeping them chilled. They feature glass doors and adjustable temperature settings.

In addition to the specific equipment mentioned above, it's important to consider factors such as energy efficiency, temperature control, and durability when selecting commercial refrigeration equipment for eggs, produce, and dairy. It's recommended to consult with a reputable commercial refrigeration supplier or expert who can provide guidance based on your specific requirements and budget.

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TRUE / FALSE. microbes can utilize only carbohydrates for energy production

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False. Microbes can utilize a variety of substrates for energy production, including not only carbohydrates but also proteins, fats, and other organic compounds.

In fact, many microbes are known to have the ability to break down and metabolize complex molecules that are difficult to digest by other organisms. This metabolic diversity allows microbes to thrive in a wide range of environments and play important roles in various biogeochemical cycles. For example, some bacteria can use sulfur compounds or iron as their energy source, while some archaea can generate energy by converting methane or hydrogen gas. Furthermore, some microbes are capable of utilizing inorganic compounds such as ammonia, nitrate, or carbon dioxide, through a process called chemolithotrophy. Therefore, while carbohydrates may be a common substrate for microbial energy production, they are certainly not the only one.

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If X has an exponential (1) PDF, what is the PDF of W = X2? 5.9.1 Random variables X and Y have joint PDF fx,y(, y) = ce -(x/8)(42/18) What is the constant c? Are X and Y in- dependent? 6.4.1 Random variables X and Y have joint PDF fxy(x, y) = 6xy 0 Points: 0 of 1 Save Find the linear and quadratic functions that best fit the data points (0,6.7). (1,6.5), (2,6.0), (3,5,8), and (4,5.9). Which of the two functions best fits the data? ank The linear (a) calculate their final angular velocity, given each had an initial speed of 1.60 m/s relative to the ice. each has a mass of 70.0 kg, and their centers of mass are 0.690 m from their locked hands. you may approximate their moments of inertia to be that of point masses at this radius. Find the area of the following regular hexagon.10Round your answer to the nearest tenth. 1. A nurse is reinforcing discharge teaching with the family of a client who has a new diagnosis of a seizure disorder. The nurse should instruct the client's family to take which of the following actions first during the event of a seizure?A. Reorient the client.B. Protect the client's head.C. Loosen constrictive clothing.D. Turn the client on his side.2. A nurse is reinforcing teaching with a group of client's about transient ischemic attacks (TIAs). Which of the following information should the nurse include in the teaching?A. A TIA can cause irreversible hemiparesis.B. A TIA can be the result of cerebral bleeding.C. A TIA can cause cerebral edema.D. A TIA can precede an ischemic stroke.3. A nurse is collecting data from a client following a recent head injury. Which of the following findings should the nurse recognize as a manifestation of increased intracranial pressure?A. Widened pulse pressureB. TachycardiaC. Periorbital edemaD. Decrease in urine output4. A nurse is reviewing the medical history of a client who is scheduled for a magnetic resonance imaging (MRI) examination of the cervical vertebra. The nurse should alert the provider to which of the following information in the client's history is a contraindication to the procedure?A. The client has a new tattoo.B. The client is unable to sit upright.C. The client has a history of peripheral vascular disease.D. The client has a pacemaker A gas has a pressure of 2.70 atm at 50.0 C. What is the pressure at standard temperature (0C)? In cell B5, enter a VLOOKUP function that will retrieve the skill level from the Student Data named range for the Studenti entered in cell B2 Incorporate an IFERROR function to return a blank value (**) if there is no Studentin value in cell B2 Hint: The skill level value to return is in column 8 of the Student_Data named range. Also be sure to use a False - Exact Match for the the range_lookup argument A security analyst is performing a quantitative risk analysis. The risk analysis should show thepotential monetary loss each time a threat or event occurs.Given this requirement, which of the following concepts would assist the analyst in determining this value? (Select two.)A. ALEB. AVC. AROD. EFE. ROI An isolated system has two phases, denoted by A and B, each of which consists of the same two substances, denoted by 1 and 2. The phases are separated by a freely moving thin wall permeable only by substance 2. Determine the necessary conditions for equilibrium A 10 m ladder leans against the side of a building. If the top of the ladder begins to slide down the building at a rate of 3 m/sec, how fast is the bottom of the ladder sliding away from the building when the top of the ladder is 6 m off the ground? Water is flowing into and out of two vats, Vat A and Vat B. The amount of water, in gallons, in Vat A at time t hours is given by a function Aft) and the amount in Vat B is given by B(t). The two vats contain the same amount of water at t=0. You have a formula for the rate of flow for Vat A and the amount in Vat B: Vat A rate of flow: A'(t)=-312+24t-21 Vat B amount: B(t)=-272 +16t+40 (a) Find all times at which the graph of A(t) has a horizontal tangent and determine whether each gives a local maximum or a local minimum of A(t). smaller t= 1 gives a local minimum larger t= 7 gives a local maximum (b) Let D(t)=B(t)-A(t). Determine all times at which D(t) has a horizontal tangent and determine whether each gives a local maximum or a local minimum. (Round your times to two digits after the decimal.) smaller t= 1.59 gives a local maximum larger t= 7.74 gives a local minimum (c) Use the fact that the vats contain the same amount of water at t=0 to find the formula for Aft), the amount in Vat A at time t. 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