HELP!!!!!!!! For #19-20, solve for x. simplify all radicals.

Answer:

t(0,3) reflected on your axis is t(-0,3)

5.4 out of the 12 adult Australian sheep dogs in the sample weigh 65 pounds or more, on average.

We can start by calculating the likelihood that a single adult Australian sheep dog weighs 65 pounds or more using the provided estimate of 45%. If p represents the percentage of adult dogs weighing 65 pounds or more, the following is the result:

p = 0.45

Next, we may calculate the median number of dogs weighing 65 pounds or more using the sample size of 12. If X represents the proportion of dogs in the sample that weigh 65 pounds or more, X will follow a binomial distribution with n = 12 and p = 0.45 as its parameters.

The formula for X's mean or expected value is:

E(X) = np

When we change the values of n and p, we obtain:

E(X) = 12(0.45) = 5.4

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The equation representing the cost of each teacup is given as follows:

4c + 18 = 42.

Hence the cost is of: $6.

The slope-intercept representation of a linear function is given by the equation presented as follows:

y = mx + b

The coefficients of the function and their meaning are described as follows:

The meaning of the slope and of the intercept for this problem are given as follows:

Hence the function is given as follows:

C = xc + 18.

(as the cost of the pot is of $18).

4 teacups push the price up to $42, hence the equation is given as follows:

4c + 18 = 42

4c = 24

c = 6.

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The probability of Kim getting a 2 and a head is 1/12.

A subfield of mathematics known as probability studies random occurrences and the possibility that they will occur. It is a technique of putting a number on the degree of ambiguity surrounding a situation or result. A number between 0 and 1, where 0 denotes an improbable event and 1 denotes a certain event, is used to express probability. The probability of an occurrence is determined by dividing the number of possible outcomes by the number of ways the event may occur. Several disciplines, including science, engineering, economics, and statistics, employ probability.

For a fair dice, the probability of getting a 2 on the dice is 1/6.

The probability of getting a head on the coin is 1/2.

Thus,

P(getting a 2 and a head) = P(getting a 2) × P(getting a head)

= (1/6) × (1/2)

= 1/12

Hence, the probability of Kim getting a 2 and a head is 1/12.

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Answer:

100%

Step-by-step explanation:

If 35 specials were served and 35 of them were salmon, then salmon was 100% of the special served.

Answer:

Step-by-step explanation:

You didnt attatch anything

Answer: (-4,11)(-2,7)(0,3)(2,-1)

Step-by-step explanation:

Put the function into desmos and create a table.

Quinn is currently 38 years old.

Let's start by using variables to represent their ages.

Let Q be Quinn's current age and B be Banu's current age.

We know that Quinn is 7 years older than Banu, so we can write:

Q = B + 7

In 3 years, their ages will increase by 3, so we can write:

(Q + 3) + (B + 3) = 75

Now we can substitute Q = B + 7 into the second equation:

(B + 7 + 3) + (B + 3) = 75

Simplifying the left side:

2B + 13 = 75

Subtracting 13 from both sides:

2B = 62

Dividing both sides by 2:

B = 31

So Banu is currently 31 years old. Using Q = B + 7, we can find Quinn's age:

Q = 31 + 7 = 38

Therefore, Quinn is currently 38 years old.

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The decision rule is as follows: If Z < -1.96, reject the null hypothesis. If not, fail to reject the null hypothesis.

The decision rule in statistics is a statement that instructs on the null hypothesis’s rejection or acceptance. It is a predetermined criterion used to test a hypothesis. When the calculated test statistic falls outside the critical region, the null hypothesis is rejected. A chocolate chip producer wants to know if the 404.0 gramme setting on their bag-filling machine is correct.

It is suspected that the machine is underfilling the bags. The chocolate chip manufacturer uses a 41 bag sample with an average weight of 396.0 grams to determine whether the machine works correctly at 404.0 gram setting.

With a significance level of 0.05, the decision rule is as follows:

If Z < -1.96, reject the null hypothesis. If not, fail to reject the null hypothesis.

Z can be calculated as follows:

z = (x - μ) / (σ / √n)

where:

x = sample mean = 396.0

μ = population mean = 404.0

σ = standard deviation = 25.0

n = sample size = 41

Substitute the values in the equation:

z = (396.0 - 404.0) / (25.0 / √41)z = -2.67Z < -1.96

Thus, reject the null hypothesis that the machine is filling bags correctly at 404.0 gram setting.

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Let's assume that each van and each bus can carry "x" number of students.

Let's assume there are "x" students in each van and each bus. Therefore, the total number of students in High School A's senior class is 8x + 8x = 16x. We know that the total number of students in High School A's senior class is 240, so we can set up an equation:

16x = 240

Solving for x, we get:

x = 15

So, each van and each bus had 15 students in it for High School A's senior class.

Similarly, for High School B, the total number of students is 4x + 1x = 5x. We know that the total number of students in High School B's senior class is 54, so we can set up an equation:

5x = 54

Solving for x, we get:

x = 10.8

Since the number of students must be a whole number, we can round up to 11. Therefore, each van and each bus had 11 students in it for High School B's senior class.

Therefore, the total number of students in High School A's senior class is 1x + 6x = 7x. We know that the total number of students in High School A's senior class is 372, so we can set up an equation:

7x = 372

Solving for x, we get:

x = 53

Therefore, each van and each bus can carry 53 students for High School A's senior class.

Similarly, for High School B, the total number of students is 4x + 12x = 16x. We know that the total number of students in High School B's senior class is 780, so we can set up an equation:

16x = 780

Solving for x, we get:

x = 48.75

Since the number of students must be a whole number, we can round up to 49. Therefore, each van and each bus can carry 49 students for High School B's senior class.

Let's assume that the price of one senior citizen ticket is "s" and the price of one child ticket is "c". Therefore, we can set up two equations based on the given information:

[tex]3s + 9c = 75[/tex]

[tex]8s + 5c = 67[/tex]

We can solve these equations simultaneously to find the values of "s" and "c". One way to do this is to multiply the first equation by 8 and the second equation by 3, so that we can eliminate "c" and solve for "s":

[tex]24s + 72c = 600[/tex]

[tex]24s + 15c = 201[/tex]

Subtracting the second equation from the first, we get:

57c = 399

Solving for "c", we get:

c = 7

Substituting this value into one of the original equations, we can solve for "s":

[tex]3s + 9(7) = 75[/tex]

[tex]3s + 63 = 75[/tex]

[tex]3s = 12[/tex]

[tex]s = 4[/tex]

Therefore, one senior citizen ticket costs $4 and one child ticket costs $7.

Let's assume that the speed of the boat in still water is "b" and the speed of the current is "c".

Therefore, we can set up two equations based on the given information:

[tex]336 = (b + c) * 12[/tex]

[tex]336 = (b - c) * 14[/tex]

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Answer:

For the original triangle:

A is at (-3, 6), B is at (1, 2), C is at (-5, 1).

For the new triangle:

A' will be at (-3 - 3, -(6 + 2)) = (-6, -8)

B' will be at (1 - 3, -(2 + 2)) = (-2, -4)

C' will be at (-5 - 3, -(1 + 2)) = (-8, -3)

The answer to this question is 289 miles. The sum of 89 + 73 + 127 is 289, so Julie will have driven a total of 289 miles.

Sum is the total of two or more numbers added together. It is a mathematical operation used to find the aggregate of two or more numbers or amounts. Sum is calculated by adding the numbers together to get the total.

This is because Julie will be driving a total of 89 miles from York to Derby, then 73 miles from Derby to Corby, for a total of 162 miles. She will then have to drive 127 miles from Derby back to York, giving a total of 289 miles.

Once these distances are determined, the total number of miles is simply the sum of the three distances. The sum of 89 + 73 + 127 is 289, so Julie will have driven a total of 289 miles.

To further illustrate this answer, it can be thought of as a triangle, where each location is a vertex and the lines connecting them are the distances between the locations.

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The first step in conducting exploratory research is to conduct a literature search. (Option 3)

Exploratory research is a type of research design used when the researcher has little or no knowledge about the research problem. The purpose of exploratory research is to gain a better understanding of the problem, identify potential research questions, and develop a hypothesis or research design.

The first step in exploratory research is to conduct a literature search, which involves reviewing existing research and publications related to the research problem. This helps the researcher to identify key concepts and theories related to the problem, as well as to identify any gaps or limitations in the existing research.

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Complete Question:

in general, the first step in conducting exploratory research is to___.

group of answer choices

To find the mean, we add up all the numbers in the list and divide by the total number of numbers:Mean = (35 + 16 + 28 + 4 + 62 + 15 + 48 + 22 + 16 + 28) / 10 = 27.4To find the median, we first need to put the numbers in order:4, 15, 16, 16, 22, 28, 28, 35, 48, 62The median is the middle number. In this case, there are 10 numbers, so the middle two are 22 and 28. The median is the average of these two numbers:Median = (22 + 28) / 2 = 25To find the mode, we look for the number that appears most often. In this case, both 16 and 28 appear twice, while all the other numbers appear only once. So the mode is 16 and 28.Mode = 16, 28To find the range, we subtract the smallest number from the largest number:Range = 62 - 4 = 58Therefore, the mean is 27.4, the median is 25, the mode is 16 and 28, and the range is 58.

Answer: the mean is 25.4, the median is 25, the mode is 16 and 28, and the range is 58.

Step-by-step explanation:

To find the mean, we add up all the values and divide by the total number of values:

Mean = (35 + 16 + 28 + 4 + 62 + 15 + 48 + 22 + 16 + 28) / 10

Mean = 254 / 10

Mean = 25.4

So the mean is 25.4.

To find the median, we need to first put the list in numerical order:

4, 15, 16, 16, 22, 28, 28, 35, 48, 62

The median is the middle number in the list, so in this case it is 25, which is between the 5th and 6th numbers in the list.

So the median is 25.

To find the mode, we need to find the number that appears most frequently in the list. In this case, the numbers 16 and 28 each appear twice, which is more than any other number, so both 16 and 28 are modes of the list.

So the mode is 16 and 28.

To find the range, we subtract the smallest value from the largest value:

Range = 62 - 4

Range = 58

So the range is 58.

Therefore, the mean is 25.4, the median is 25, the mode is 16 and 28, and the range is 58.

Answer:

546.7

Step-by-step explanation:

Answer:

a. The product of each pair of numbers is:

1 x 49 = 49

2 x 48 = 96

10 x 40 = 400

b. The pair of numbers that will produce the largest possible product is when the two numbers are equal to half of the sum, which is 25. So the pair of numbers is 25 and 25, and the product is 25 x 25 = 625.

c. We can determine the pair of numbers that have the largest product by using the following reasoning: For any two numbers whose sum is fixed, their product is maximized when the two numbers are as close together as possible. This is because the product of two numbers that are far apart is always smaller than the product of two numbers that are closer together and have the same sum. In this case, the sum is 50, so the two numbers that are closest together and add up to 50 are 25 and 25, which give the largest possible product.

After a time period of 9 years Mr. Lucas' investment will be 17940 x 10^5

What does investment mean in everyday language?

A purchase made with the intention of earning money or gaining notoriety is referred to as an investment. The acquisition of things that are not used right away but will be utilized to create wealth down the road is known as an investment in an economic perspective. There are numerous investment options available.

Rate in percentage (R) = 5.5%

Principal Amount (P) = 5 200

Total time period (t) = 9 years

Number of times interest is compounded per t (n) = 1

r = R/100

r = 5.5/100

r =  0.055 rate per year,

Then solve the equation for A

A = P(1 + r/n)^(nt)

A = 5200(1 + 0.055/1)⁽¹⁾⁽⁹⁾

A = 5200(1 + 0.055)⁹

A = 5200(1.055)⁹

A =  5200 * 3.45 x 10^5

   = 17940 x 10^5

Hence, after a time period of 9 years Mr. Lucas' investment will be 17940 x 10^5

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Answer:

area = 127[tex]units^{2}[/tex]

perimeter = 46 units

Step-by-step explanation:

count them

Answer:

In a right triangle, one of the angles measures 90 degrees, and the other two angles are acute angles that add up to 90 degrees. Let's call the measures of the two acute angles x and y.

We know that x and y differ by 22 degrees. So we can set up an equation:

x - y = 22

We also know that x + y = 90, since the two acute angles add up to 90 degrees.

Now we can solve this system of equations for x and y. One way to do this is to add the two equations together, which eliminates y:

x - y + x + y = 22 + 90

2x = 112

x = 56

Now we can substitute x = 56 into one of the equations to find y:

x + y = 90

56 + y = 90

y = 34

Therefore, the measures of the two acute angles of the right triangle are 56 degrees and 34 degrees.

According to combinations formula there are 495 possible committees that can be selected from a group of 12 people.

To calculate this, you can use the formula for combinations

nCr = n!/(r!(n-r)!)

where n is the total number of people (12) and r is the number of people on the committee.
Therefore, the possible number of committees that can be selected is;

= {12!}/{4!8!}
= 12*11*10*9/4*3*2*1

= 11880/24
= 495
Therefore, 495 possible committees can be selected from a group of 12 people if a committee of 4 is to be selected.

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The value of x is approximately 8.15.

To find the value of x, we need to use the formula for the volume of a cone, which is V = (1/3)πr^2h, where r is the

radius of the base and h is the height of the cone. We know that the volume of the cone below is 392π, so we can set

up the equation:

[tex]392π = (1/3)πx^2h[/tex]

Simplifying, we can divide both sides by π and multiply by 3 to get:

[tex]1176 = x^2h[/tex]

Using the Pythagorean theorem, we can relate the height, radius, and slant height of the cone:

[tex]h^2 + r^2 = x^2[/tex]

Since the cone is a right cone, we know that the radius is half of the diameter, which is equal to x/2. Substituting this in,

we get:

[tex]h^2 + (x/2)^2 = x^2[/tex]

Simplifying:

[tex]h^2 = x^2 - (x/2)^2

h^2 = 3x^2/4[/tex]

Now we can substitute this expression for [tex]h^2[/tex] into our equation for the volume:

[tex]1176 = x^2(3x^2/4)[/tex]

Simplifying again:

[tex]1176 = 3x^4/4[/tex]

[tex]1568 = 3x^4[/tex]

[tex]x^4 = 1568/3[/tex]

Taking the fourth root of both sides:

[tex]x = (1568/3)^(1/4)[/tex]

x ≈ 8.15

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Answer: 14

Step-by-step explanation:

As per the combination method, Cameron can wear a different outfit for 6 days.

If we want to find the number of different combinations of shirts that Cameron can wear with a pair of shorts, we need to calculate the value of 3C1 (which means choosing 1 shirt out of 3). Using the formula above, we get:

³C₁ = 3! / (1! x (3-1)!) = 3

So there are 3 possible combinations of shirts that Cameron can wear with a pair of shorts.

Since Cameron has 2 pairs of shorts, he can wear each combination twice (once with each pair of shorts). Therefore, the total number of different outfits he can wear is:

3 (number of shirt combinations) x 2 (number of pairs of shorts) = 6

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Answer:

4cm

Step-by-step explanation:

Area of a triangle=[tex]\frac{1}{2}[/tex]×b×h

[tex]\frac{1}{2}[/tex]×3cm×h=[tex]24cm^{2}[/tex]

L.C.M=2

6cmh=[tex]24cm^{2}[/tex]

h=[tex]24cm^{2}[/tex]÷6cm

h=4cm

Answer:

Step-by-step explanation:

area = [tex]\frac{1}{2} base[/tex]×height

  24 = [tex]\frac{1}{2}[/tex](3)×height

  24 = 1.5×height

  [tex]\frac{24}{1.5}[/tex] = [tex]\frac{1,5}{1,5}[/tex]height

  16 = height

Latrell would need to pay 105 to replace the felt on his pool table.

Latrell has a pool table that is 3 feet wide and 7 feet long.

The pool table's felt needs to be replaced, and the cost of the felt per square foot is $5.00.

Let's find out how much it would cost Latrell to replace the pool table's felt.

What is the surface area of the pool table.

To determine the surface area of the pool table,

we need to multiply the length by the width, as shown below:

Surface area = length × width

Surface area = 7 ft × 3 ft

Surface area = 21 square feet

Now that we know the surface area of the pool table, we can determine the cost of the felt.

Latrell will need 21 square feet of felt, and it costs $5.00 per square foot.

We can use the following formula to determine the total cost of the felt:

Total cost of felt = cost per square foot × surface area.

Total cost of felt = $5.00 × 21 square feet.

Total cost of felt = $105

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In other words, we can expect that 95% of the time, the number of applicants who meet the 80-point requirement for the Peace Corps in a randomly selected group of 300 will fall within a range of 67 and 93.

Based on the information provided, it is likely that 0.6% of applicants will meet the 80-point requirement for the Peace Corps. Using the Empirical Rule, we can estimate that 95% of measurements will fall within two standard deviations of the mean. For the random variable x, which is the number of applicants out of 300 who meet the 80-point requirement, this would be approximately[tex]80 +/- 2(6.47),[/tex] or between 67.06 and 92.94.

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Answer: I like "Hot Dogs"?

Step-by-step explanation:

The procedure of comparing different instrumental variables estimates of the same parameter is an example of testing over identifying restrictions

Testing the over identifying restrictions is the procedure of comparing different instrumental variables estimates of the same parameter. It is a method used to assess the validity of a set of instruments in a two-stage least squares (2SLS) regression model. In this method, the same parameter is estimated in two different ways using different sets of instruments. The difference between these two estimates is then tested to see if they are statistically different. If they are statistically different, then this indicates that the instruments are not valid and need to be revised.

The over identifying restrictions test is typically used in cases where there is a large number of instruments and the researcher wants to be sure that the instruments are appropriate for the regression model.

This test is also useful for assessing homogeneity, which is when the independent variable is correlated with the error term in the regression model. Heteroscedasticity is another potential issue in regression models, where the variance of the error term is not constant across all observations. The over identifying restrictions test can be used to detect this issue as well.

In summary, the procedure of comparing different instrumental variables estimates of the same parameter is an example of testing over identifying restrictions. It is a method used to assess the validity of a set of instruments in a 2SLS regression model, and can also be used to detect issues such as homogeneity and heteroscedasticity.

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To enlarge Shape A by a scale factor of 1.5 with the center of enlargement (0, 0), we have to multiply every length by 1.5.

Enlargement of Shape A

Enlargement of a shape is when it is either stretched or shrunk in one or both directions. The original shape is called the pre-image, while the new shape is called the image. What is the centre of enlargement?

The center of an enlargement is the point about which all of the points of the pre-image are scaled to obtain the image. When the scale factor is greater than 1, the image of the pre-image is an enlargement. When the scale factor is between 0 and 1, the image of the pre-image is a reduction.In an enlargement, each point on the pre-image is mapped onto a corresponding point on the image along a straight line which goes through the centre of enlargement.

The new shape has a larger size than the original shape. To expand shape A by a scale factor of 1.5, you need to multiply each length by 1.5. You have to create new points. It's easy to use a scale ruler to make sure each length is multiplied by 1.5.

A Centre of enlargement is a point in the coordinate plane that enlarges or shrinks a figure by some scale factor. In the problem, the center of enlargement is (0, 0).

Thus, we have to extend every length of Shape A by 1.5, and our scale factor is 1.5. We get Shape B by doing so. Now, we can conclude that to enlarge Shape A by a scale factor of 1.5 with the center of enlargement (0, 0), we have to multiply every length by 1.5.

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Answer:

Step-by-step explanation:

Given a^2 + b^3 + c^4 = 55, we need to find the greatest value for a * b * c.

To solve this problem, we can use the AM-GM inequality, which states that the arithmetic mean of a set of non-negative numbers is always greater than or equal to their geometric mean.

Using this inequality, we have:

(a^2 + b^3 + c^4) / 3 >= (a*b*c)^(2/3)

55/3 >= (a*b*c)^(2/3)

(55/3)^(3/2) >= a*b*c

The maximum value of a, b, and c occurs when they are as close together as possible. We can use the fact that a, b, and c are distinct positive integers to determine that the closest they can be is 1, 2, and 3.

So the greatest value for a * b * c is (1*2*3) = 6, and we have:

(55/3)^(3/2) >= 6

Approximately: 23.1 >= 6

Therefore, the greatest value for a * b * c is 6.

The greatest value for abc is 3,240.

We want to find the greatest value of the product abc, given that a, b, and c are different positive integers and a + b + c = 55.

To maximize the value of abc, we want to maximize each individual factor, a, b, and c. We can do this by setting a to be as small as possible and c to be as large as possible, while ensuring that a, b, and c are still different positive integers.

Since a, b, and c are different positive integers, the smallest value for a is 1.

To maximize c, we set b = a + 1 and c = 55 - a - b.

Substituting b and c in terms of a, we get:

c = 55 - a - (a + 1) = 54 - 2a

Now we can express the product abc in terms of a:

abc = a x b x c = a (a + 1)(54 - 2a)

Expanding this expression, we get:

abc = -2a³ + 53a²+ 54a

To find the maximum value of abc, we can take the derivative of this expression with respect to a and set it equal to zero:

d(abc)/da = -6a² + 106a + 54 = 0

Solving for a, we get:

a = 8.93 (rounded to two decimal places)

Since a must be a positive integer, we round up to a = 9.

Using this value of a, we can find the corresponding values of b and c:

b = a + 1 = 10

c = 55 - a - b = 55 - 9 - 10 = 36

Therefore, the greatest value of abc is:

abc = 9 x 10 x 36 = 3,240

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The complete question is below:

If a, b, and c are different positive integers and a₂+ b₃ + c₄ = 55, Then what is the greatest value for abc= ?