Answer:
the area ot the triangle is half the area of the rectangle, so the area of the triangle is what sqauare units
Answer: It's much easier to form a rectangle and multiply the width and the length and then divide it by 2
For what values of a are the following expressions true?
(PLease help ASAP)
|a +5| = −5−a
|a +5 |=a +5
The equation |a + 5| = −5 − a is not true for any value of a, while the equation |a + 5| = a + 5 is true for values of a greater than or equal to -5.
The absolute value of a number is defined as the distance of the number from zero on a number line. Thus, |a + 5| is equal to the distance of (a + 5) from zero on a number line. Since distance is always non-negative, |a + 5| is always non-negative.
On the other hand, the expression −5 − a is always negative, since the sum of a negative number (-5) and any number (a) is always negative.
Therefore, for the equation |a + 5| = −5 − a to be true, the absolute value of (a + 5) would have to be negative, which is impossible since absolute value is always non-negative.
For the equation |a + 5| = a + 5 to be true, a must be greater than or equal to -5, because when a is greater than or equal to -5, (a + 5) is already non-negative, so the absolute value of (a + 5) is equal to (a + 5).
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3) the line that passes through
(8,5) and (1,5)
Slope:
The table represents an exponential function. What is the multiplicative rate of change of the function?
The multiplicative rate οf change οf the given expοnential functiοn is 1/5.(1st οptiοn).
What is expοnential functiοn?An expοnential functiοn is a Mathematical functiοn which is οf the fοrm
f (x) = aˣ, where “x” is variable here and a real number and “a” is a cοnstant which is called the base οf the functiοn where a shοuld be greater than zerο.
The expοnential functiοn is given here in tabular fοrm.
Here frοm the table οf expοnential functiοn we get when x= 2 then
y= 2/5
again when x= 3 then y= 2/25
sο (2/5)×(1/5) = 2/25
again fοr x= 4 , y= 2/125
(2/25)×(1/5) = 2/125
sο every time the expοnential functiοn is multiplied by 1/5 and we get the next result.
Hence, The multiplicative rate οf change οf the given expοnential functiοn is 1/5.
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a trapezoid has a base length of 4 meters and 2.5 meters. if the height of the trapezoid is 4 meters, what is the area of the trapezoid?
The area of the trapezoid is 13 meters.
The area of a trapezoid is calculated by taking the sum of the two bases and multiplying that by the height, then dividing that by two. In this case, the sum of the two bases is 4 meters + 2.5 meters = 6.5 meters. Multiplying this by the height of 4 meters gives us a result of 26 meters. Finally, we divide that by two to get the final area of 13 meters.
To calculate the area of a trapezoid, you first need to calculate the sum of its two bases. The two bases are the bottom and the top lengths of the trapezoid, which in this case are 4 meters and 2.5 meters respectively. Once you have the sum of the two bases, you can then multiply that sum by the height of the trapezoid, which in this case is 4 meters. This will give you the total area of the trapezoid. Lastly, you divide this total area by two to get the final area.
In summary, to calculate the area of a trapezoid with a base length of 4 meters and 2.5 meters, and a height of 4 meters, you need to first calculate the sum of its two bases, which in this case is 6.5 meters. Multiply this by the height of 4 meters to get the total area of 26 meters. Finally, divide this by two to get the final area of the trapezoid, which is 13 meters.
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Ms Kowal invests £6000 in a simple interest account.
After 5 years her investment has earned £450 interest.
What rate of interest does the account pay?
Answer:
We can use the simple interest formula I = Prt to find the rate of interest that the account pays. Here, P is the principal amount (£6000), t is the time period (5 years), and I is the interest earned (£450). Substituting these values in the formula gives us: 450 = 6000 * r * 5. Solving for r, we get r = 0.015 or 1.5%. Therefore, the account pays a simple interest rate of 1.5%
If a₁ = 9, and an an-1 - 1 then find the value of a4.
A. 5
B. 6
C. 9
D. 4
Answer:
it’s b
Step-by-step explanation:
I just did it
Prove that the following statement is false. There exists an integer n such that 6n2 + 27 is prime. To prove the statement is false, prove the negation is true. Write the negation of the statement. For every integer n, 6n² + 27 is prime. For every integer n, 6n2 + 27 is not prime. There exists an integer n, such that 6n2 + 27 is not prime. There exists a composite number q = 6n2 + 27, such that n is an integer. There exists an integer n, such that 6n2 + 27 is prime. Now prove the negation. Suppose n is any integer. Express 6n2 + 27 as the following product: 6n2 + 2 Now is an integer because sums and products of integers are integers. Thus, 6n2 + 27 is not prime because it is a
The negation of the statement "There exists an integer n such that 6n2 + 27 is prime" is "For every integer n, 6n2 + 27 is not prime."
To prove the negation, we can use algebraic manipulation to show that 6n2 + 27 is always composite.
Suppose n is any integer. We can factor out 3 from 6n2 + 27 to get 3(2n2 + 9). Since 2n2 + 9 is always odd (2 times any integer is even, and adding 9 makes it odd), we can further factor it as (2n2 + 9) = (2n2 + 6n + 9 - 6n) = [(2n+3)(n+3)] - 6n.
Substituting this expression back into 3(2n2 + 9), we get 3[(2n+3)(n+3) - 6n]. Since (2n+3)(n+3) - 6n is an integer, 3[(2n+3)(n+3) - 6n] is composite for every integer n. Therefore, 6n2 + 27 is not prime for any integer n.
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WORTH 23 POINTS - While reading a news article, Bethany noticed that the word "senselessness" had a lot of repeating letters. Bethany wondered about the probabilities of randomly drawing certain letters if each letter in "senselessness" were written on an index card and put into a bag.
Answer:
To determine which letter has the greatest probability of being selected and its corresponding probability, we need to count the number of times each letter appears in the word "senselessness".
The word "senselessness" contains a total of 12 letters, with 4 distinct letters: "e", "s", "n", and "l". We can count the number of times each letter appears as follows:
"e" appears 4 times
"s" appears 4 times
"n" appears 2 times
"l" appears 2 times
Therefore, the letter "e" and "s" have the greatest probability of being selected, as they appear most frequently in the word. The probability of selecting the letter "e" would be 4/12, which simplifies to 1/3 or approximately 0.33. Similarly, the probability of selecting the letter "s" would also be 1/3 or approximately 0.33.
On the other hand, the letter with the least probability of being selected would be either "n" or "l", as they appear the least frequently. The probability of selecting either "n" or "l" would be 2/12, which simplifies to 1/6 or approximately 0.17.
I'm not sure if this answers your question, but i really hope it helps!
Please mark brainliest though, it really helps!
a spherical snowball is melting in such a manner that its radius is changing at a constant rate, decreasing from 20 cm to 10 cm in 30 minutes. at what rate, in cm3 per minute, is the volume of the snowball changing at the instant the radius is 9 cm?
The volume of the snowball is decreasing at a rate of approximately 108π cubic centimeters per minute when the radius is 9 cm.
The volume V of a sphere with radius r is given by the formula V = (4/3)πr^3. To find the rate at which the volume is changing with respect to time, we need to take the derivative of V with respect to time t. Using the chain rule, we get:
dV/dt = (dV/dr) * (dr/dt)
Since the radius is changing at a constant rate, we can calculate dr/dt by dividing the change in radius by the time interval:
dr/dt = (10 cm - 20 cm) / (30 minutes) = -1/3 cm/min
To find dV/dr, we can take the derivative of the volume formula with respect to r:
dV/dr = 4πr^2
Substituting the given radius of 9 cm, we get:
dV/dr = 4π(9)^2 = 324π cm^2
Finally, we can substitute these values into the formula for dV/dt:
dV/dt = (dV/dr) * (dr/dt) = 324π cm^2 * (-1/3 cm/min) = -108π cm^3/min
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Find the area of a circle that has a radius of 7/2 centimeters. Use 22/7 as an approximation for π.
Answer: The answer is 38.5 cm^2
Step-by-step explanation:
Given:
Radius(r) = 7/2
Pie (π) = 22/7
We know that:
The area of Circle is = πr^2 = π * r * r
So, ans is = (22/7) * 7/2 * 7/2 = 38.5 cm^2
Answer:
A≈ 38.5cm^2
Step-by-step explanation:
Given:
The approximation of pi is 22/7 or 3.141592
The radius is 7/2 or 3.5
Work:
A=πr(2)=π·3.5(2)≈38.48451
now let's round it to 38.5cm^2
in a trendline based on five observations, if the average of y is 100 and the slope of the line is 22 then the intercept is:
c = -880
The intercept for a trendline based on five observations with an average of y = 100 and slope of the line = 22 is -880. This can be calculated using the formula for the equation of a straight line: y = mx + c, where m is the slope and c is the intercept. We know that the slope (m) is 22 and the average of y (the y-intercept) is 100. Plugging in the given values, we get:
100 = 22x + c
c = -880
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a beer and wine store series 10 licensee is allowed to serve beer and wine samples on the premises if it holds sampling privileges. true or false? false true`
False. A Beer and Wine Store Series 10 Licensee is not allowed to serve beer and wine samples on the premises, even if they hold sampling privileges.
This is because beer and wine samples are not allowed to be sold under this type of license, according to the Texas Alcoholic Beverage Code. Under the TABC, beer and wine samples may only be sold in certain locations, such as restaurants and stores that have a TABC permit for the purpose of selling alcoholic beverages for on-premises consumption.
Beer and wine sampling privileges are reserved for other types of establishments, such as bars and taverns, that have a TABC permit for the purpose of selling alcoholic beverages for on-premises consumption. As such, a Beer and Wine Store Series 10 Licensee is not allowed to serve beer and wine samples on the premises, even if they hold sampling privileges.
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Help me Pleaaee it’s urgent
Graph the system below and write its solution
Answer:
the answer is one solution and to graph you'll need to make the second equation like this y=-2x+7
ELEPHANTS In the wild, an African elephant typically consumes 2.5 × 10² pounds of food a day. If there are approximately 4.15 × 10⁵ African elephants in the wild, how many pounds of food are consumed by African elephants in one day?
Answer:
Approximately 1.05 × 10⁹ pounds of food are consumed by African elephants in one day.
Step-by-step explanation:
Answer:
Step-by-step explanation:
its 7 or 6\
Two square pyramids are joined at their bases.
Each base is 28 cm long. The distance between the
vertices of the combined pyramids is 21 cm. What
is the volume of the solid formed?
The volume of the solid formed using square pyramids are joined at their bases is 5,487.3 unit ².
Using the formula for the volume of a square pyramid, find the volume and then multiply it by two since there are two square pyramids.
Let V be the volume of the solid formed.
⇒ volume of the solid formed - V = 2 ( [tex]\frac{1}{3} *B*h[/tex] )
Now substitute the values,
⇒V = 2 ( [tex]\frac{1}{3}[/tex] * [tex]28^{2}[/tex] * 10.5 )
⇒V = 2 ( [tex]\frac{1}{3}[/tex] * 784 * 10.5 )
⇒V = 2 ( 261.3 * 10.5 )
⇒V = 2 ( 2,743.65 )
⇒V = 5,487.3 unit ²
Therefore, the volume of the solid formed using square pyramids are joined at their bases is 5,487.3 unit ².
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A county recreation department cleared a mile long walking trail. If the trail will be marked every mile with a small sign, how many signs are needed?
Answer:
Step-by-step explanation:
If the trail is a mile long and is marked every mile with a sign, then there will be one sign at the end of the trail. In addition, there will be signs marking each mile along the trail, including the starting point. Since there are 1 mile markers between the starting point and the end of the trail, there will be a total of:
1 (at the end) + 1 (at the starting point) + 1 (for each mile marker) = 1 + 1 + 1 = 3
Therefore, three signs are needed to mark a mile-long walking trail.
Ezra started collecting lunch boxes when he was 5 years old. He had 26 superhero lunch boxes, 15 outer space lunch boxes, and 17 rock band lunch boxes. Then Ezra's cousin started her own lunch box collection. Ezra wanted to help her get started, so he gave his cousin 19 lunch boxes from his collection. How many lunch boxes does Ezra have left in his collection? lunch boxes
Answer:
he has 39 lunch boxes left
Step-by-step explanation:
26 + 15 + 17 gives you 58 and when you subtract 19 from 58 that leaves you with 39 left
when you take the scholastic assessment test (sat), your score is recorded as a percentile score. if you scored in the 92nd percentile, it means that you scored better than approximately 92% of those who took the test. (a) if lisa's score was 83 and that score was the 29th score from the top in a class of 240 scores, what is lisa's percentile rank? (round your answer to the nearest whole number.) (b) lee has received a percentile rank of 83% in a class of 40 students. what is lee's rank in the class? (round your answer to the nearest whole number.)
Using percentage, Lisa's percentile rank is 88 and Lee's class rank is 34
What is Lisa's percentile rank?(a) To find Lisa's percentile rank, we need to determine how many scores are below hers in the class, then divide by the total number of scores and multiply by 100 to get a percentage.
Since Lisa's score is the 29th from the top, there are 240 - 29 = 211 scores below hers.
Her percentile rank is (211/240) x 100 = 87.92, which rounded to the nearest whole number is 88.
Therefore, Lisa's percentile rank is 88.
(b) To find Lee's rank in the class, we need to determine how many students scored below him, then add 1 (for Lee's own score).
Since Lee's percentile rank is 83%, we know that 83% of the class scored lower than he did.
The number of students who scored lower is (83/100) x 40 = 33.2, which rounded to the nearest whole number is 33.
Therefore, Lee's rank in the class is 33 + 1 = 34.
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The work shows the first steps of writing a partial fraction decomposition.
3x+9/(x+1)(x-5)=A/x+1+B/x-5
3 x + 9 = A (x minus 5) + B (x + 1)
3 x + 9 = A x minus 5 A + B x + B
What is the partial fraction decomposition in terms of x?
it's C
The partial fraction decomposition of 3x+9/(x+1)(x-5) in terms of x is C = A/(x+1) + B/(x-5).
To find the values of A and B, we solve the system of equations formed by equating coefficients of x and the constant term in equation 3x + 9 = A(x-5) + B(x+1). Solving for A and B, we get A=-3/4 and B=3/4. Substituting these values back into the partial fraction decomposition, we get C = -3/4/(x+1) + 3/4/(x-5).
Therefore, the partial fraction decomposition of 3x+9/(x+1)(x-5) in terms of x is C = -3/4/(x+1) + 3/4/(x-5).
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Answer:
Answer is C
Step-by-step explanation:
Precalc Edge 2023
Each dot in the following dot plot represents the height of one toddler at Mrs. Orlando's daycare.
Find the interquartile range (IQR) of the data in the dot plot.
Answer: 1.5
Step-by-step explanation:
The interquartile range (IQR) is a measure of statistical dispersion and is calculated by subtracting the first quartile (Q1) from the third quartile (Q3). For the given dot plot data of the toddler's heights, the data would first be arranged in ascending order, then divided into two halves below and above the median to determine the first and third quartiles.
Explanation:To find the interquartile range (IQR) in the dot plot data of the toddler's heights at Mrs. Orlando's daycare, we first need to understand what the IQR represents. The Interquartile Range is a measure of where the bulk of the values lie in a data set. It's computed by subtracting the first quartile (Q1) from the third quartile (Q3).
As a first step, you would arrange the data points in ascending order. The median would give us the second quartile (Q2). The data set is then divided into two halves, below and above the median. The first quartile (Q1) is the median of the lower half and the third quartile (Q3) is the median of the upper half. Finally, subtract Q1 from Q3 to find the IQR.
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What is the median of the data in the table below?
Answer:24
Step-by-step explanation:
a rectangular flag is 29ft long and 17ft wide. if a triangle is cut out of the center of the flag that has a base of 9ft and a height of 2ft , what is the remaining area of the flag?
A rectangular flag is 29ft long and 17ft wide. if a triangle is cut out of the center of the flag that has a base of 9ft and a height of 2ft, So the remaining area of the flag is 484 ft².
The data we get from the question is,
Length of rectangular flag = 29 ft
Width of rectangular flag = 17 ft
Base of triangle = 9 ft
Height of triangle = 2 ft
We need to find the remaining area of the flag when a triangle is cut out of the center of the flag.
We know that the area of the rectangle is given by:
Area of rectangle = length × breadth
Area of rectangle = 29 × 17
= 493 ft²
The area of the triangle is given by:
Area of triangle = (1/2) × base × height
Area of triangle = (1/2) × 9 × 2
= 9 ft²
The remaining area of the flag will be the area of the rectangle minus the area of the triangle.
The remaining area of the flag = Area of the rectangle - Area of the triangle
= 493 - 9
= 484 ft²
Therefore, the remaining area of the flag is 484 ft².
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if the path around the edge of a circular lawn is 132 feet, what is the approximate area inside the circular path? complete the answer sentence. solve on paper. then, enter your answer on zearn. you may consider writing your answer to the hundredths place and using the calculator to help you solve.
As a result, the circumference of the circular walkway is approximately 367.06 square feet.
what is circle ?A circle is a geometric shape made up of all points that are equally spaced apart from the center. It is a flat, two-dimensional object whose radius or diameter serves as its sole defining characteristic. A circle's circumference is the distance around it, while the area of the circle is the amount of space inside it.
given
We must deduct the area of the smaller circle from the size of the larger circle in order to determine the area inside the circular path. Let's use the abbreviations "r" for the smaller circle's radius and "R" for the larger circle's radius. We are aware that the circumference of the smaller circle, which is 132 feet, is equal to the distance around the circular path.
The wider circle's circumference is 132 feet.
2πR = 132
R = 21
The breadth of the circular path, which is equal to the difference between the radii of the two circles, can now be used to calculate the radius of the smaller circle:
R - r = diameter of the circle
21 - r = diameter of the circle
r = 18
The smaller circle therefore has a radius of 18 feet.
Inside the arc of the path, there is:
R2 - r2 equals (21 - 18) = (44 - 324) = (117) 367.06 square feet.
As a result, the circumference of the circular walkway is approximately 367.06 square feet.
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clark was asked to complete a self-administered questionnaire posted at mysurvey. what type of survey did clark complete?
Clark completed a self-administered questionnaire, which is also known as an online survey.
This type of survey is administered online and is completed by the participant (in this case, Clark) without the assistance of a researcher or interviewer. It can be delivered through an online form or through an email or online survey link.
The questionnaire typically includes multiple-choice questions, short-answer questions, and rating scales that the participant can answer with a click or tap. After the participant completes the survey, their answers are collected and analyzed by the researcher. This type of survey is a cost-effective and convenient way to collect data from a large number of people in a short amount of time.
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Attitudes toward school. The Survey of Study Habits and Attitudes (SSHA) is a psychological test that measures the motivation, attitude toward school, and study habits of students. Scores range from 0 to 200. The mean score for U.S. college students is about 115, and the standard deviation is about 30. A teacher who suspects that older students have better attitudes toward school gives the SSHA to 25 students who are at least 30 years of age. Their mean score isAttitudes toward school. The Survey of Study
Habit= 127.8.
(a) Assuming that ? = 30 for the population of older students, carry out a test of
H0: ?= 115
H0: ?> 115
Report the P-value of your test, and state your conclusion clearly.
(b) Your test in part (a) required two important assumptions in addition to the assumption that the value of ? is known. What are they? Which of these assumptions is most important to the validity of your conclusion in part (a)?
(a) To test the hypotheses H0: µ = 115 and H1: µ > 115, we will conduct a one-sample t-test using the given information.
Step 1: Calculate the t-value.
t = (sample mean - population mean) / (standard deviation / √sample size)
t = (127.8 - 115) / (30 / √25)
t = 12.8 / 6
t = 2.13
Step 2: Determine the degrees of freedom (df).
df = sample size - 1
df = 25 - 1
df = 24
Step 3: Find the P-value.
Using a t-table or calculator, find the P-value corresponding to t = 2.13 and df = 24. The P-value is approximately 0.022.
Step 4: State the conclusion.
Since the P-value is less than the commonly used significance level of 0.05, we reject the null hypothesis (H0: µ = 115) and conclude that the mean score for older students is significantly higher than the mean score for the entire population.
(b) The two important assumptions for the t-test are:
1. The sample is randomly selected from the population.
2. The population is normally distributed.
The most important assumption for the validity of the conclusion in part (a) is the normality of the population. If the population is not normally distributed, the results of the t-test may not be valid, and the conclusion may be inaccurate.
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Question #1: The heights of seven footballers are listed below. 1.9m, 1.82m, 1.78m, 1.8m, 1.88m, 1.86m, 1.7m (a) Arrange the heights in order from smallest to largest. (b) Write down the median height. (c) A player is picked at random. Write down the probability that he is over 1.85m.
Answer:
A) 1.7m, 1.78m, 1.8m, 1.82m, 1.86m, 1.88m, 1.9m
B) The median is 1.82
C) There is a 3/7 chance that the player will be taller than 1.85m
Step-by-step explanation:
The solution is, (a) 1.7m < 1.78m < 1.8m < 1.82m< 1.86m< 1.88m < 1.9m, the heights in order from smallest to largest.
(b) 1.8 the median height.
(c) A player is picked at random, 3/7 is the probability that he is over 1.85m.
What is median?In statistics and probability theory, the median is the value separating the higher half from the lower half of a data sample, a population, or a probability distribution. For a data set, it may be thought of as "the middle" value.
here, we have,
given that,
The heights of seven footballers are listed below.
1.9m, 1.82m, 1.78m, 1.8m, 1.88m, 1.86m, 1.7m
now we have to Arrange the heights in order from smallest to largest.
we get,
(a) 1.7m < 1.78m < 1.8m < 1.82m< 1.86m< 1.88m < 1.9m, the heights in order from smallest to largest.
now, the median = 1.7 + 1.9/ 2
= 1.8
(b) 1.8 the median height.
again,
(c) the total no. of outcome = 7
no. of event that he is over 1.85m = 3
so, the probability that he is over 1.85m = 7/3
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In a certain math game, each problem is either easy or hard, and problems of the same difficulty level are worth the same number of points. Sandra
played this game twice.
. In the first game, she correctly answered 10 easy problems and 8 hard problems for a total of 94 points.
. In the second game, she correctly answered 5 easy problems and 16 hard problems for a total of 143 points.
The system below can be used to determine z, the number of points per easy problem, and y, the number of points per hard problem.
10z + 8y = 1
(5z + 16y=143
Which is the quickest method of finding the number of points per easy problem?
O Subtract 2 times the bottom equation from the top equation.
Subtract 2 times the top equation from the bottom equation.
Add 2 times the bottom equation to the top equation.
O Add 2 times the top equation to the bottom equation.
Answer: 18.75%
Step-by-step explanation:
To find the percent increase, we need to calculate the difference between the new speed and the old speed, divide that by the old speed, and then multiply by 100 to get the percentage increase.
The difference between the new speed and the old speed is:
38 - 32 = 6
To find the percentage increase, we divide the difference by the old speed and multiply by 100:
(6 / 32) x 100 = 18.75%
Therefore, Matt's typing speed increased by 18.75%.
5. Disha states that the circumference and the area of the larger circle are both double the
circumference and the area of the smaller circle. Is she correct? Explain why or why not.
Disha is not correct, as the area of the larger circle is actually four times the area of the smaller circle, not double.
What is Circumference?Circumference is the distance around the edge of a closed curved shape, such as a circle. In the case of a circle, it is the distance around the circle, or the perimeter of the circle.
According to question:Let "r" denote the smaller circle's radius. Then the circumference of the smaller circle would be 2πr, and the area would be πr².
If the circumference and area of the larger circle are both double the circumference and area of the smaller circle, then:
Circumference of larger circle = 2(2πr) = 4πr
Area of larger circle = 2(πr²) = 2π(r²)
Let "R" represent the larger circle's radius. Then the circumference of the larger circle would be 2πR, and the area would be πR².
If the circumference and area of the larger circle are both double the circumference and area of the smaller circle, then:
Circumference of larger circle = 2(2πr) = 4πr = 2πR
Area of larger circle = 2(πr²) = 2π(r²) = πR²
We may see from the equations above that:
R = 2r
Substituting this value of R in the equation for the area of the larger circle, we get:
Area of larger circle = πR² = π(2r)² = 4πr²
But we already know that the area of the larger circle is 2π(r²). This means that Disha is not correct, as the area of the larger circle is actually four times the area of the smaller circle, not double.
Therefore, Disha's statement is incorrect.
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In a laboratory test of pus, the number of bacteria detected in the infected wound of a person on Wednesday is 2.4 x 10. If the antibiotic decreases the number of bacteria by 60% per day and it is started consuming since Wednesday, find the number of bacteria that will find in the laboratory test of coming Friday?
Step-by-step explanation:
We can approach this problem using exponential decay, where the number of bacteria decreases by 60% per day. Let N be the initial number of bacteria on Wednesday, then the number of bacteria on Friday can be calculated as:
N_Friday = N_Wednesday x (0.4)^2
where (0.4)^2 is the factor by which the number of bacteria decreases from Wednesday to Friday.
We are given that the number of bacteria on Wednesday is 2.4 x 10, so we can substitute this into the equation:
N_Friday = 2.4 x 10 x (0.4)^2
Simplifying this expression, we get:
N_Friday = 0.96
Therefore, the number of bacteria that will be detected in the laboratory test on Friday is 0.96. Note that the units are not specified in the question, so we assume that the number is given in some arbitrary units.