Answer:
Step-by-step explanation:
Let's start by using algebra to solve the problem.
Let x be the number of games that Mark started with.
Mark sold half of his games to his brother, so he sold x/2 games. This means he had x - x/2 = x/2 games after selling half to his brother.
He then bought 16 more games, so he had x/2 + 16 games.
Finally, we're told he now has 36 games, so we can set up the equation:
x/2 + 16 = 36
Simplifying the equation, we get:
x/2 = 20
Multiplying both sides by 2, we get:
x = 40
Therefore, Mark started with 40 games.
Answer:
Mark had 40 games to start with.
Step-by-step explanation:
You know this because you can take away the 16 games he bought, which leaves him with half of what he started with which is 20. And if 20 is half of his games you can double it to give you his starting number of games.
:)
Kayleigh babysat for 11 hours this week. That was 5 fewer than 2/3 as many hours as she babysat last week, H. Write an equation to represent the number of hours she babysat each week.
Answer:
⅔h – 5 = 11
Step-by-step explanation:
h = babysitting hours last week
⅔h = two-thirds of those hours
⅔h - 5 = five hours fewer than two-thirds of those hours
⅔h – 5 = 11
The equation is ⅔h – 5 = 11.
abc is a right triangle with points a 2,5 b 2,0 and c x,0. if the area of abc is 25 square units, what us the equation of ac?
As the given abc is a right triangle with points a(2, 5), b(2, 0), and c(x, 0). The area of 'abc' is 25 square units. and the equation of AC is x = 5√5.
The equation of ac has to be found. Since triangle ABC is right-angled, it can be shown that
AC² = AB² + BC²
Finding the lengths of AB and BC before using the Pythagorean theorem to find AC.
Using the distance formula,
AB =√(5²+0²)
= √25
= 5,
And BC = √(x²+0²)
= √x²
= x.
Area of a right triangle = ½(base × height)
Here base = AB and height = BC,
So, ½ × 5 × x = 25
⇒ 5x = 50
⇒ x = 10
Now, to find AC, use the Pythagorean Theorem.
AC² = AB² + BC²
= 5² + 10²
= 25 + 100
= 125AC
= √125
= 5√5
Thus, the equation of AC is x = 5√5. Answer: x = 5√5.
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two eggs and two pieces of bacon have a total of 22 grams of fat. two eggs and four pieces of bacon have a total of 32 grams of fat. how many grams of fat are in each?
We can solve the given system of equations to find how many grams of fat are in each when two eggs and two pieces of bacon have a total of 22 grams of fat and two eggs and four pieces of bacon have a total of 32 grams of fat.
Step-by-step explanation:
Let's consider that each piece of bacon has "x" grams of fat and each egg has "y" grams of fat.
From the given information, we can form two equations as follows:
Equation 1: 2x + 2y = 22 (when two eggs and two pieces of bacon have a total of 22 grams of fat)
Equation 2: 4x + 2y = 32 (when two eggs and four pieces of bacon have a total of 32 grams of fat)
To solve for "x" and "y", let's perform elimination by multiplying Equation 1 by (-2) and adding it to Equation 2.
-4x - 4y = -44 (multiply Equation 1 by -2)
+ 4x + 2y = 32 (Equation 2)
-2y = -12
y = 6
Substitute the value of "y" in Equation 1 or 2 to solve for "x":
2x + 2y = 22
2x + 2(6) = 22
2x = 10
x = 5
Therefore, each piece of bacon has 5 grams of fat and each egg has 6 grams of fat.
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Hudson is a waiter at a restaurant. Each day he works, Hudson will make a guaranteed wage of $30, however the additional amount that Hudson earns from tips depends on the number of tables he waits on that day. From past experience, Hudson noticed that he will get about $13 in tips for each table he waits on. How much would Hudson expect to earn in a day on which he waits on 18 tables? How much would Hudson expect to make in a day when waiting on t tables?
The total amount of money earned by Hudson in a day on which he waits on 18 tables is $264.
The total amount of money earned by Hudson in a day on which he waits on t tables is $(30 + 13t).
How to determine Hudson's earnings in a day on which he waits on 18 tables?Based on the information provided above, we can logically deduce that a linear equation that models the total amount of money earned by Hudson at this restaurant is represented by the following function:
y = 30 + 13t
Where:
t represent the number of tables he waits on that day.y represent the total earnings.When the number of tables he waits on that day is equal to 18, Hudson's total earnings can be calculated as follows;
y = 30 + 13t
y = 30 + 13(18)
y = $264.
When the number of tables he waits on that day is t tables, Hudson's total earnings can be calculated as follows;
y = 30 + 13t = $(30 + 13t).
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if the company sells the jelly beans in packs of 9 bags, what can we say about the likelihood that the average weight of the bags in a randomly selected pack is 2 or more grams lighter than advertised?
There is a 2.28% likelihood that the average weight of the bags in a randomly selected pack is 2 or more grams lighter than advertised.
Assume that the advertised weight is equivalent to the typical weight of one bag, which is 30 grammes. A pack of nine bags would therefore weigh 9 x 30 = 270 grammes.
Let's now assume that each bag actually weighs 30 grammes on average, with a 2 gramme standard deviation, according to a normal distribution (which represents the variability in the weight of the bags).
We need to apply the central limit theorem to determine the probability that the average weight of the bags in a randomly selected pack is 2 or more grammes less than stated. According to this theorem, the mean of a sufficiently large sample (in this case, nine bags) will have a sampling distribution that is roughly normal, with a mean of 30 grammes and a standard deviation of 2 grammes divided by the square root of the sample size (9 = 0.67 grammes). The mean will also be equal to the population's standard deviation.
We can determine the likelihood that the sample mean of a pack of 9 bags weighs less than 28 grammes using a normal distribution table or calculator (which is 2 grammes less than the advertised weight of 30 grams). This likelihood is roughly 0.0228, or 2.28%.
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the skewness coefficient can be used to multiple select question. compare standard deviations. compare two samples with different measurement units. compare means. compare one sample to a known reference distribution.
The skewness coefficient is a measure of asymmetry in a distribution that can be used to compare means and compare one sample to a known reference distribution, but it is not typically used to compare standard deviations or compare two samples with different measurement units.
The skewness coefficient is a measure of the degree of asymmetry in a probability distribution. It indicates the direction and degree of skewness in a distribution, and can be used to compare means and compare one sample to a known reference distribution.
A positive skewness coefficient indicates that the distribution has a longer tail on the right side and that the mean is greater than the median, while a negative skewness coefficient indicates that the distribution has a longer tail on the left side and that the mean is less than the median.
The skewness coefficient can be useful in detecting departures from normality and in identifying outliers that might affect statistical inference.
However, the skewness coefficient is not typically used to compare standard deviations or to compare two samples with different measurement units.
Comparing standard deviations involves analyzing the variability in the data, whereas comparing means and comparing one sample to a known reference distribution involves analyzing the central tendency of the data.
Additionally, comparing two samples with different measurement units requires converting the measurements to a common scale, which is not related to skewness.
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I need help with this problem. Joe bought a gallon of gasoline for 2. 85 per gallon and c cans of oil for 3. 15 per can
From the given information provided, the expression that need to determine the total amount is Total cost = $2.85/gallon x g gallons + $3.15/can x c cans.
The expression that can be used to determine the total amount Joe spent on gasoline and oil is:
Total cost = Cost of gasoline + Cost of oil
We can represent the cost of gasoline as:
Cost of gasoline = price per gallon x number of gallons
Substituting the given values, we get:
Cost of gasoline = $2.85/gallon x g gallons
Similarly, we can represent the cost of oil as:
Cost of oil = price per can x number of cans
Substituting the given values, we get:
Cost of oil = $3.15/can x c cans
Putting it all together, we get:
Total cost = $2.85/gallon x g gallons + $3.15/can x c cans
Expression that can be used to determine the total amount Joe spent on gasoline and oil is:
Total cost = $2.85/gallon x g gallons + $3.15/can x c cans
Question - Joe bought g gallons of gasoline for $2.85 per gallon and c cans of oil for $3.15 per can. What expression can be used to determine the total amount Joe spent on gasoline and oil?
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Joe has 2 strips of card each strip Is 36cm long one strip is divided into 3 equal parts the other strip is divided into 4 equal parts joe uses 2 strips to make this shape what is the total length of joes shape
The total length of Joe's shape will be the sum of these lengths, which is 12 + 9 + 9 = 30cm.
To find the total length of Joe's shape, we first need to determine the length of each part of the strips.
For the first strip, which is divided into three equal parts, each part will be 36/3 = 12cm long. For the second strip, which is divided into four equal parts, each part will be 36/4 = 9cm long.
To make the shape, Joe will need to use two strips. Let's assume that Joe places the strip with three equal parts horizontally and the strip with four equal parts vertically. He will then need to cut each strip into the appropriate lengths to create the shape.
To create the shape, Joe will need to use one 12cm length from the first strip and two 9cm lengths from the second strip. He will then need to connect these lengths together to create the shape.
These lengths will add up to a total length for Joe's shape of 12 + 9 + 9 = 30 cm.
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alexa started randomly playing a movie and would not stop, despite my repeated orders. what's going on here?
It sounds like you may be experiencing a bug with your Alexa device. This is likely due to a software update or miscommunication between the device and the server.
To resolve this issue, you may need to restart your device by unplugging it from the power source and plugging it back in. You can also try clearing the cache of your device. Additionally, you may need to update the software of your device by visiting the Amazon website and downloading the most recent version of the software. If the issue persists, you may need to contact Amazon customer service for further assistance.
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What is the value of y in the solution to the system of equations?
²x+y=1
-X
2x - 3y = -30
-8
-3
3
O 8
So, the system of equations solution is (x, y) = (-27/8, 31/4), and the value of y in this solution is 31/4, which is roughly 7.75. As a result, the answer is y = 31/4.
What is equation?An equation is a statement in mathematics that states the equality of two expressions. An equation has two sides that are separated by an algebraic equation (=). For example, the argument "2x + 3 = 9" asserts that the phrase "2x + 3" equals the value "9". The purpose of equation solving is to determine which variable(s) must be changed in order for the equation to be true. Simple or complex equations, regular or nonlinear equations, and equations with one or more elements are all possible. In the equation "x2 + 2x - 3 = 0," for example, the variable x is raised to the second power. Lines are employed in a variety of mathematical disciplines, including algebra, calculus, and geometry.
the system of equations,
[tex]y = 1 - 2x\\2x - 3(1 - 2x) = -30\\2x - 3 + 6x = -30\\8x = -27\\x = -27/8\\2(-27/8) + y = 1\\-27/4 + y = 1\\y = 1 + 27/4\\y = 31/4[/tex]
So, the system of equations solution is (x, y) = (-27/8, 31/4), and the value of y in this solution is 31/4, which is roughly 7.75.
As a result, the answer is y = 31/4.
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< Back to task
In the quadrilateral below, angles DAB and BCD are the same size.
What is the size of angle DAB?
D
228
34° -B
Answer >
The size of angle DAB in the quadrilateral is 49°.
How to find the size of angle DAB?The sum of the interior angles of a quadrilateral is 360°. We can say:
∠A + ∠B + ∠C + ∠D = 360°
∠A + 34° + ∠C + 228° = 360°
∠A + ∠C + 262° = 360°
∠A + ∠C = 360 - 262
∠A + ∠C = 98
Since angles DAB and BCD are the same size. This implies ∠A = ∠C. Thus:
∠A + ∠A = 98
2∠A = 98
∠A = 98/2
∠A = 49°
Therefore, the size of angle DAB is 49°.
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Complete Question
Check the attached image
In ΔPQR, r = 7.8 cm, q = 6 cm and ∠Q=30°. Find all possible values of ∠R, to the nearest 10th of a degree.
The twο pοssible values οf ∠R tο the nearest 10th οf a degree are 33.6° and 326.4°.
What is a triangle?A triangle is a clοsed twο-dimensiοnal geοmetric shape with three straight sides and three angles. It is the simplest pοlygοn, which is a flat shape cοnsisting οf straight lines.
We can use the Law οf Cοsines tο find the length οf side QR:
[tex]c^2 = a^2 + b^2 - 2ab[/tex] cοs(C)
where c is the length οf side QR, a is the length οf side PQ (which is unknοwn), b is the length οf side PR (which is 7.8 cm), and C is the angle οppοsite side c (which is 30°). Substituting the given values, we get:
[tex]QR^2 = PQ^2 + 7.8^2 - 2(PQ)(7.8)cos(30^\circ )[/tex]
[tex]QR^2 = PQ^2 + 60.84 - 7.8PQ[/tex]
Next, we can use the Law οf Sines tο relate the length οf side PQ tο the angle οppοsite it, ∠P:
PQ/sin(30°) = QR/sin(P)
PQ = QR(sin(30°)/sin(P))
Substituting this expressiοn fοr PQ intο the equatiοn fοr [tex]QR^2[/tex] abοve, we get:
[tex]QR^2 = [QR(sin(30^\circ)/sin(P))]^2 + 60.84 - 7.8[QR(sin(30^\circ)/sin(P))][/tex]
Simplifying and rearranging, we get a quadratic equatiοn in terms οf QR:
[tex]QR^2 - 3.9QR + 28.99 = 0[/tex]
Using the quadratic fοrmula, we find that:
QR ≈ 7.466 cm οr QR ≈ 3.866 cm
Since we knοw that QR < PQ + PR = 6 + 7.8 = 13.8, the οnly valid sοlutiοn is QR ≈ 7.466 cm. Therefοre, we have:
[tex]cos(R) = (PQ^2 + QR^2 - PR^2)/(2PQQR)[/tex]
[tex]cos(R) = (PQ^2 + 7.466^2 - 7.8^2)/(2PQ(7.466))[/tex]
[tex]cos(R) = (PQ^2 - 4.928)/[2PQ(7.466)][/tex]
Since cοs(R) ≤ 1, we have:
[tex]PQ^2 - 4.928 ≤ 2PQ(7.466)[/tex]
Sοlving fοr PQ using the quadratic fοrmula, we get:
PQ ≤ 5.474 cm οr PQ ≥ 20.032 cm
Since PQ < PR, the οnly valid sοlutiοn is:
PQ ≈ 5.474 cm
Nοw we can use the Law οf Cοsines again tο find ∠R:
[tex]cos(R) = (PQ^2 + PR^2 - QR^2)/(2PQPR)[/tex]
[tex]cos(R) = (5.474^2 + 7.8^2 - 7.466^2)/(2(5.474)(7.8))[/tex]
cοs(R) ≈ 0.828
R ≈ 33.6° οr R ≈ 326.4°
Therefοre, the twο pοssible values οf ∠R tο the nearest 10th οf a degree are 33.6° and 326.4°.
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suppose that a die is rolled twice and the average of the two numbers of spots is recorded as a quantity z what are the mean value and the variance of z?
The mean value and the variance of z are 3.5 and 0.486, respectively.
Suppose that a die is rolled twice and the average of the two numbers of spots is recorded as a quantity z. What are the mean value and the variance of z?
Let X be the first number of spots and Y be the second number of spots. As X and Y are independent and have the same distribution, we have
E(X) = E(Y) = (1 + 2 + 3 + 4 + 5 + 6) / 6 = 21 / 6 = 3.5,
Var(X) = Var(Y) = (1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2) / 6 - (21 / 6)^2 = 2.9167.
Let Z = (X + Y) / 2 be the quantity of interest. Then
E(Z) = E[(X + Y) / 2] = E(X) / 2 + E(Y) / 2 = 3.5,
Var(Z) = Var[(X + Y) / 2] = Var(X) / 4 + Var(Y) / 4 = 0.486.
Therefore, the mean value and the variance of z are 3.5 and 0.486, respectively.
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the radioactive decay of sm-151 (an isotope of samarium) can be modeled by the differential equation dy/dt 0.0077y, where t is measured in years. find the half-life of sm-151.
The radioactive decay of sm-151 (an isotope of samarium) can be modeled by the differential equation dy /dt = -0.0077y, DOthe half-life of Sm-151 is 90 years.
What is sm-151?Sm-151 is a radioactive isotope of the element Samarium. The symbol for Sm-151 is 151Sm, and the atomic number of Samarium is 62. This isotope has a half-life of 88 years.
Differential equations differential equation that model the radioactive decay of Sm-151 is given as
dy/dt = -0.0077y, where t is measured in years.
To find the half-life of Sm-151, we can use the formula for half-life, which is given as:
t1/2 = (ln 2) / k
Where k is the decay constant. To find k, we can use the given differential equation.
dy/dt = -0.0077y
Separating variables, we get
dy / y = -0.0077 dt
Integrating both sides,
we get ln y = -0.0077 t + C
Where C is the constant of integration.
To find C, we use the initial condition, y(0) = y0, where y0 is the initial amount of Sm-151.
Substituting this in the above equation, we get ln y0 = CSo,
the equation becomes y = -0.0077 t + ln y0
Taking the exponential of both sides, we get y = y0 e^(-0.0077t)
Using the formula for k, we get k = 0.0077
Substituting this in the formula for half-life,
we get: t1/2 = (ln 2) / k
= (ln 2) / 0.0077
= 90 years
Therefore, the half-life of Sm-151 is 90 years.
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Use the given scale factor and the side lengths of the scale drawing to determine the side lengths of the real objects.
Using the scale factor of 4:1, the side lengths of the real objects are:
B. Side a is 5 inches long and side b is 4.5 inches long.
What is a Scale Factor?A scale factor is a number that represents the ratio of the size or dimensions of an object in relation to another object. It is a proportional relationship between two similar objects, where the scale factor is the ratio of any corresponding lengths or dimensions.
Thus, given that the scale factor is 4:1, it means 4 inches of the scale drawing represents 1 inch of the real object.
Therefore, the sides would be:
Side a = 20/4 = 5 in.
Side b = 18/4 = 4.5 in
The answer is B.
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Think of a time when you had a question in math class, did you ask it? If so, did it get answered? If you tend to not ask your questions, why do you think you hesitate to ask? Have you ever had someone else ask the same question you had? How did it make you feel? Relief?
Asking questions in math class is crucial for deepening understanding, and teachers strive to create a supportive learning environment for students to feel comfortable seeking help.
Students may hesitate to ask questions in math class for various reasons, such as fear of being judged by peers or the teacher, feeling like their question is not important, or simply not wanting to disrupt the flow of the lesson. However, it's essential to remember that asking questions is an integral part of the learning process and can lead to a deeper understanding of the subject.
When students do ask questions, they may feel relieved to have their doubts clarified, and it can also benefit other students who may have had the same question but were hesitant to ask. Teachers typically encourage questions and strive to create a supportive learning environment where students feel comfortable asking for help.
In summary, asking questions is an essential aspect of learning, and students should feel encouraged to ask them, as it can lead to a deeper understanding of the subject and help their peers who may have had similar questions.
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please help me im begging (ignore the cat hair)
Step-by-step explanation:
The circumference of a circle is given by the formula:
C = πd
where d is the diameter of the circle and π is a mathematical constant approximately equal to 3.14159.
In this case, the diameter of the circle is 58, so we can substitute this value into the formula:
C = πd
C = π(58)
C ≈ 182.09
Therefore, the circumference of the circle with diameter 58 is approximately 182.09 units. Note that the units of measurement were not specified in the question, so the units of the answer will depend on the units used for the diameter.
dots are spaced one unit apart, horizontally and vertically. what is the number of square units enclosed by the polygon?
The number of square units enclosed by the polygon is 18.
First, count the number of dots that are enclosed by the polygon (including those on the boundary). There are 14 such dots.Next, count the number of dots on the boundary of the polygon. There are 8 dots on the boundary.Each of the dots on the boundary corresponds to a line segment of the polygon.
So, the perimeter of the polygon is 8 units (the length of each of these line segments).Now, we can use Pick's theorem to find the area of the polygon. Pick's theorem states that A = i + b/2 - 1, where A is the area of the polygon, i is the number of dots inside the polygon, and b is the number of dots on the boundary of the polygon.
So, plugging in the values we have: A = 14 + (8/2) - 1 = 14 + 4 - 1 = 17
Therefore, the area of the polygon is 17 square units.However, we have to remember that the dots are spaced one unit apart, horizontally and vertically.
Therefore, each square that is enclosed by the polygon has an area of 1 square unit. We counted 17 such squares, so the total area enclosed by the polygon is 17 square units.
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alicia had $22 to spend on pencils if each pencil cost $1.50 how many pencils can she buy? What is the Inequality or Equation
If each pencil cost $1.50 and Alicia had $22 to spend on them, she could purchase 14 pencils. This situation's inequality is as follows: 1.5x ≤ 22.
To find out how many pencils Alicia can buy, we can divide her total budget by the cost per pencil:
Number of pencils = Total budget / Cost per pencil
Number of pencils = $22 / $1.50
Number of pencils = 14.67 (rounded to two decimal places)
Alicia cannot buy a fraction of a pencil, so she can buy a maximum of 14 pencils.
The inequality that represents this situation is:
1.5x ≤ 22
Where x represents the number of pencils Alicia can buy. We divide both sides of the inequality by 1.5 to isolate x:
x ≤ 14.67
Since Alicia cannot buy a fraction of a pencil, we round down to the nearest whole number and get:
x ≤ 14
So, Alicia can buy a maximum of 14 pencils.
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miguel went to a movie theater and bought a large bag of popcorn that cost $10.49. to avoid spending too much money in all, he determined that he could spend up to $5.51 on a drink. let x represent how much money miguel wanted to spend in all. which inequality describes the problem?
The inequality that represents Miguel's spending limit is $16.00 ≤ x.
Let x represent the total amount of money Miguel wants to spend. We know he spent $10.49 on popcorn and can spend up to $5.51 on a drink.
To find the inequality, we can add these two amounts together and set it less than or equal to x, since x represents the maximum amount he wants to spend. Mathematically, we can write:
$10.49 + $5.51 ≤ x
Simplifying this inequality, we get:
$16.00 ≤ x
This means that Miguel can spend up to $16.00 in total on the popcorn and drink combined. If he spends more than $16.00, he will have exceeded his limit.
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Pls help due today…..
Please
We can find angle z by using triangle interior theorem
All angles in a triangles add up to 180 so
[tex]z + 82 +90 = 180[/tex]
[tex]z = 8[/tex]
To find c, we know c is the hypotenuse and we are given a base of 5, we can use cosine
[tex] \cos(82) = \frac{5}{c} [/tex]
[tex]c = \frac{5}{ \cos(82) } [/tex]
Use a calculator, and we get
[tex]c = 35.92[/tex]
To find a, we can use tangent
[tex] \tan(82) = \frac{a}{5} [/tex]
[tex]5 \tan(82) = a[/tex]
[tex]a = 35.58[/tex]
Warm up State the theorems and show the steps needed to find the measure of angle a b and c
The value of the missing angles of the quadrilateral are:
a = 110°
b = 70°
c = 20°
How to find the missing angle?Theorem sum of angles in a triangle states that they sum up to 180 degrees. Thus:
d = 180 - (78 + 32)
d = 70°
Similarly:
e = 180 - (78 + 32 + 18)
e = 20°
Sum of angles on a straight line is 180 degrees. Thus:
a = 180 - 70
a = 110°
We can see that e + b will be equal to 90 degrees because of the definition of right angles. Thus:
b = 90° - 20°
b = 70°
From sum of angles in a triangle as 180° is:
c = 180 - (90 + 70)
c = 20°
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The area of a circle is 36л ft². What is the circumference, in feet? Express
your answer in terms of pie
Answer:
12π feet
Step-by-step explanation:
The formula for the area of a circle is A = πr², where A is the area and r is the radius. We are given that the area is 36π ft², so we can set up an equation:
36π = πr²
To solve for the radius, we can divide both sides by π:
36 = r²
Taking the square root of both sides, we get:
r = 6
Now that we know the radius is 6 feet, we can use the formula for the circumference of a circle, C = 2πr:
C = 2π(6)
Simplifying, we get:
C = 12π
Therefore, the circumference of the circle is 12π feet.
emme takes a quiz for her anthropology 401e course. there are 9 multiple-choice questions on the test with 4 answer choices, only one of which is correct. emme has not studied for the test, so she just randomly guesses the answers. what is the probability that emme answers exactly 3 questions correctly? enter your answer as a decimal with four significant digits
The probability that Emme answers exactly 3 questions correctly is 0.1961.
Since each question has four answer choices and only one is correct, the probability of Emme randomly guessing the correct answer for each question is 1/4 = 0.25. Emme needs to answer exactly 3 out of the 9 questions correctly, so we use the binomial distribution with n = 9 and p = 0.25 to calculate the probability:
P(X = 3) = (9 choose 3) * (0.25)^3 * (0.75)^6
Using a calculator, we get:
P(X = 3) = 0.1961
Therefore, the probability that Emme answers exactly 3 questions correctly is 0.1961.
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Solve the equation
1/4xln(16q^8)-ln3=ln24
We can claim that after answering the above question, the Therefore, the solution to the original equation is: [tex]q = 9^x\\[/tex]
What is equation?In mathematics, an equation is a statement that states the equality of two expressions. An equation consists of two sides separated by an algebraic equation (=). For example, the argument "2x + 3 = 9" states that the sentence "2x Plus 3" equals the value "9". The goal of solving equations is to find the value or values of the variable(s) that will allow the equation to be true. Equations can be simple or complex, linear or nonlinear, and contain one or more parts. For example, in the equation "x2 + 2x - 3 = 0," the variable x is raised to the second power. Lines are used in many areas of mathematics, including algebra, calculus, and geometry.
given equation:
[tex]1/4xln(16q^8) - ln3 = ln24\\1/4xln(16q^8) = ln(24 * 3)\\1/4xln(16q^8) = ln72\\ln(16q^8)^(1/4x) = ln72\\16q^8^(1/4x) = 72\\16q^8 = 72^(4x)\\ln(16q^8) = ln(72^(4x))\\[/tex]
[tex]ln(16) + ln(q^8) = 4x ln(72)\\ln(q^8) = 4x ln(72) - ln(16)\\ln(q^8) = ln(72^(4x)) - ln(16^1)\\ln(q^8) = ln((72^(4x))/16)\\q^8 = e^(ln((72^(4x))/16))\\q^8 = (72^(4x))/16\\q^8 = 9^(8x)\\q = 9^x\\[/tex]
Therefore, the solution to the original equation is:
[tex]q = 9^x\\[/tex]
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The "Good Ole Times" magazine charges for classified ads by the "column inch". A "column inch" is as wide as one column, and it is one inch high. The cost is $43. 50 per column inch. How much would the magazine charge to print a 1¾ inch ad?
The magazine would cost $33.93 to print a 1¾ inch ad in the "Good Ole Times" magazine.
The cost of a classified ad in the "Good Ole Times" magazine is determined by its size in column inches, with a cost of $43.50 per column inch. To determine how much the magazine would charge to print a 1¾ inch ad, we need to calculate the size of ad in column inches and then multiply that by the cost per column inch.
One way to convert 1¾ inches to column inches is to convert the fractional part (¾) to a decimal by dividing it by 4, which is the number of quarters in an inch. This gives us:
1¾ inches = 1 + ¾ inches = 1 + 0.75 inches = 1.75 inches
To express this measurement in column inches, we divide by the width of a column, which is not given in the problem. Assuming a typical newspaper column width of 2.25 inches, we get:
1.75 inches ÷ 2.25 inches per column = 0.7778 column inches
Rounding this to two decimal places, we get:
0.78 column inches
Now we can calculate the cost of the ad as follows:
Cost = Size in column inches × Cost per column inch
Cost = 0.78 column inches × $43.50 per column inch
Cost = $33.93
Therefore, the magazine would charge $33.93 to print a 1¾ inch ad.
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Which side lengths could be used to create a right triangle?
a(15, 17, 29
b(20, 21, 29
c(13, 17, 19
d(10, 12, 22
Explain when each method (graphing,
substitution, and linear combinations) is a good
method to find a solution to a system
of equations.
Method 1: Graphing
Graphing is best when the both equations are shown in slope-intercept form. For example:
[tex]y=\frac{1}{2} x+2\\y=-\frac{1}{2} x+4[/tex]
[tex](2,3)[/tex]
You can easily graph this system of equations and find the intersecting point. The graph is displayed below. This may not always be the case, however and you may get complicated fractions in your answer. In this case, substitution or elimination may be better.
Method 2: Substitution
Substitution is a good method to solve a system of equations when one of the equations can be rearranged to isolate one variable, or the equation already solves for a variable. This isolated expression can then be substituted into the other equation(s) to create a new equation(s) with only one variable.
For example, consider the system of equations:
[tex]y=x-2\\2x-5y=1[/tex]
Since y is much easier to substitute, we can choose y to substitute into the other equation:
[tex]2x-5(x-2)=1[/tex]
We can then simplify the equation:
[tex]2x-5x+10=1\\-3x=-9\\x=3[/tex]
Then you can substitute x into the original equation:
[tex]y=3-2\\y=1[/tex]
Solution: [tex](3,1)[/tex]
Substitution can be a useful method when the system involves two or three variables and one equation can be easily rearranged to isolate a variable. However, it can become more difficult or time-consuming when the system involves more variables or when the equations are not solving for a variable or can be easily solved. In these cases, other methods such as elimination is more efficient.
Method 3: Elimination
Elimination is a good method to solve a system of equations when the equations can be added or subtracted in a way that eliminates one of the variables.
For example, consider the system of equations:
[tex]x+y=90\\x-y=18[/tex]
We can cancel out the variable y and add the other numerals and variables:
[tex]2x=108[/tex]
This simplifies to:
[tex]x=54[/tex]
We can then solve for y:
[tex]54+y=90\\y=36[/tex]
Solution: [tex](54, 36)[/tex]
Once we have the value of x, we can substitute it back into one of the original equations to solve for y.
Although elimination is slightly more complicated, it is the most efficient method out of all of the three methods I have shown here.
Hope this helped you :)
(This took like 30 minutes ;-;)
the most important thing to notice about a table of q-sort correlates is the a. smallest correlation. b. exact value of the correlations. c. wording of specific items. d. general patterns that emerge.
The most important thing to notice about a table of q-sort correlates is d. general patterns that emerge.
Q-sorting is a method of ranking items in order of preference or importance, and Q-sort correlates are used to identify relationships between the ranked items. The correlations in the table represent how strongly the items are associated with each other based on their rankings.
While the exact value of the correlations is important for statistical analysis, the most valuable information in a table of q-sort correlates is the general patterns that emerge. These patterns can help to identify groups of items that are closely related to each other, as well as those that are more distantly related.
Understanding the wording of specific items may also be important, as it can impact how the items are ranked and how they relate to each other. However, the primary focus of a table of q-sort correlates is on the relationships between the items, rather than the items themselves.
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10 1/4 divided by 5 1/2?
Answer:
To divide two mixed numbers, we need to first convert them to improper fractions.
10 1/4 is the same as (10 x 4 + 1)/4 = 41/4
5 1/2 is the same as (5 x 2 + 1)/2 = 11/2
So, we need to divide 41/4 by 11/2:
(41/4) ÷ (11/2)
When dividing by a fraction, we can multiply by its reciprocal (flip the fraction):
(41/4) x (2/11)
Now, we can simplify by canceling out the common factors:
(41 x 2) / (4 x 11) = 82/44 = 41/22
Therefore, 10 1/4 divided by 5 1/2 is equal to 41/22 or approximately 1.86 when rounded to two decimal places.
Por lo tanto, 10 1/4 dividido por 5 1/2 es igual a 41/22 o aproximadamente 1,86 cuando se redondea a dos decimales.