Answer:
"nonmetal, nonmetal"
Explanation:
Oxygen is a non metal and Nitrogen is a non metal. It is 8th element of the periodic table. It is located in period 2 and group 16.
Nitrogen lies at the group 15 of the periodic table. Its atomic no is 7. Its valency is 2.
Hence, the correct option is (c) "nonmetal, nonmetal".
_______ is the ability of the body to fight infection via antibodies or specialized cells.
O immunity
O antibiotics
O pathogens
O breathing
Answer:
Immunity
Explanation:
how can we remove the turbidity from water?
Answer:
Settling and decanting is a method to reduce turbidity by letting the water sit for 2-24 hours so that the particulates settle to the bottom of the container. The clear water is then decanted off the top into a second container.
Explanation:
Settling and decanting is a method to reduce turbidity by letting the water sit for 2-24 hours so that the particulates settle to the bottom of the container. The clear water is then decanted off the top into a second container.
A sample of nitrogen gas is at a pressure of 1.20 atm, a volume of 30.0 liters, and a
temperature of
87.0 OC. How many moles of gas are in the sample? How many grams of gas are in the
sample?
Answer:
1. 1.21mol
2.8.5kg
Explanation:
the number of moles and grams of gas in the sample
A sample of oxalic acid is titrated with a standardized solution of KMNO4. A 25 mL sample of oxalic acid required 12.7 mL of 0.0206 M KMnO4 to achieve a pink colored solution. The balanced equation for this reaction is shown below:
6 H+ (aq) + 2 MnO4 - (aq) + 5 H2C2O4(aq) → 10 CO2(g) +8 H2O(l) + 2Mn2+(aq)
Required:
a. What does the pink color signify in this reaction?
b. What is the ratio of MnO4 - ions to H2C2O4 molecules in this reaction?
c. How many moles of MnO4 - ions reacted with the given amount of oxalic acid solution?
d. How many moles of H2C2O4 were present?
e. What was the molarity of the oxalic acid solution?
f. If the density of the oxalic acid solution was 1.00 g/mL, what was the percentage by mass of oxalic acid in the solution?
Answer:
Following are the solution to the given points:
Explanation:
Oxalic acid volume [tex]= 25.00 \ mL = 0.0250 \ litres[/tex]
KMnO4 volume [tex]= 12.70 \ ml = 0.0127 \ litres[/tex]
KMnO4 molarity [tex]= 0.0206\ M = 0.0206 \ \frac{mol}{l}[/tex]
In point a:
Its pink presence after full intake of oxalic acid with attachment to KMnO4 is suggested by the end-point of the process due to the small abundance of KMnO4, As just a self predictor, KMnO4 is used.
In point b:
[tex]H_2C_2O_4[/tex] molecules mole ratio to [tex]MnO_4^-[/tex] ions:
The equilibrium for both the oxalic acid and KMnO4 reaction is suggested:
[tex]6H+ (aq) + 2MnO_4- (aq) + 5H_2C_2O_4 (aq) \rightarrow 10CO_2 (g) + 8H_2O (l) + 2Mn_2+ (aq)[/tex]
The reaction of 5 mol of oxalic acid is 2 mol [tex]MnO_4^-[/tex] ions
[tex]H_2C_2O_4[/tex]: molecules mole proportion to [tex]MnO_4^-[/tex] ions:
[tex]5 H_2C_2O_4[/tex]: : [tex]2MnO_4^-[/tex]
In point c:
The Moles of [tex]MnO_4^-[/tex] ions reacted with the [tex]H_2C_2O_4[/tex]:
The molar mass of the solution is the number of solute moles in each volume of water
[tex]Molarity =\frac{moles}{Volume}\\\\Moles \ of\ KMnO_4 = Molarity \times volume[/tex]
Moles with ions reacted to mol with both the amount of : supplied.
In point d:
[tex]H_2C_2O_4[/tex] moles in the sample present:
[tex]H_2C_2O_4[/tex] moles = moles [tex]MnO_4^-[/tex] ions [tex]\times[/tex] mole ratio
[tex]H_2C_2O_4[/tex] moles in the sample = [tex]2.6162 \times 10^{-4}\ mol \times (\frac{5}{2})[/tex]
[tex]H_2C_2O_4[/tex] molecules = [tex]6,5405\times 10^{-4}[/tex] mol are present in the sample
In point e:
Oxalic acid molarity = [tex]\frac{mole}{volume}[/tex]
[tex]=\frac{ 6.54 \times 10^{-4} mol}{0.025\ L} \\\\ = 0.0260 \ M[/tex]
In point f:
Oxalic acid level by mass in the solution:
Oxalic acid mass calculation:
Oxalic acid molar weight = 90.0349 [tex]\frac{g}{mol}[/tex].
Oxalic acid mass per liter = oxalic acid moles per liter [tex]\times[/tex] molar mass
[tex]= 0.0260 \frac{mol}{L} \times 90.0349 \frac{g}{mol}\\\\= 2.3409 \frac{g}{L}\\\\ = 2.3409 \frac{g}{1000 \ mL}\\\\= 0.2409 \frac{g}{100 \ mL}[/tex]
When Oxalic acid solution density[tex]= 1.00 \ \frac{g}{mL}[/tex]
Mass oxalic acid percentage = [tex]0.2409 \%[/tex]
Oxalic acid mass proportion [tex]= 0.24\% \ \frac{W}{v} \ \ Mass[/tex]
3. Which of the following statements is correct?
X Х
1 doubling the pressure of a gas doubles its volume
2. 2.00 L of air at 227°C has twice the pressure of the same 2.00 L of air at -
23°C
3. 2.00 L of air at 100°C has twice the pressure of the same 2.00 L of air at
50°C
4. halving the pressure of a gas halves its volume
Answer:
3. 2.00 L of air at 100°C has twice the pressure of the same 2.00 L of air at 50°C
Explanation:
1) doubling the pressure of a gas doubles its volume
This is incorrect because by increasing the pressure volume is going to be decreased.
2) 2.00 L of air at 227°C has twice the pressure of the same 2.00 L of air at 23°C
This is also incorrect because 2 L air at 227 °C will have the pressure more than twice time as compared to the 2L air at 23°C.
3. 2.00 L of air at 100°C has twice the pressure of the same 2.00 L of air at 50°C
This is correct;
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
thus, by increasing the temperature pressure is also goes to increase in the same ratio.
4. halving the pressure of a gas halves its volume
This is incorrect because halving the pressure of gas increasing its volume.
Help needed within the next 10 minutes
16.2 g of Water are formed
I've been stuck on this problem for 23456789 minutes please help!!
Answer:
C₄H₆O₃ + H₂O ⇒ 2C₂H₄O₂
Explanation:
Given:
C₄H₆O₃ + H₂O ⇒ C₂H₄O₂
Find:
Balance equation
Computation:
C₄H₆O₃ + H₂O ⇒ C₂H₄O₂
C₄H₆O₃ + H₂O ⇒ 2C₂H₄O₂
Number of atom should be equal in LHS and RHS.
So,
We have to multiply 2 in RHS to get equal number of atom.
Consider the following equilibrium: 2SO^2(g) + O2(9) = 2 SO3^(g)
1. What is equal at equilibrium?
2. What would happen to the forward rate if some 0were removed from this equilibrium?
3. Explain why, in terms of collision theory.
4. Would the reaction still be at equilibrium at this point?
Answer:
At equilibrium, the forward and backward reaction rates are equal.
The forward reaction rate would decrease if [tex]\rm O_2[/tex] is removed from the mixture. The reason is that collisions between [tex]\rm SO_2[/tex] molecules and [tex]\rm O_2\![/tex] molecules would become less frequent.
The reaction would not be at equilibrium for a while after [tex]\rm O_2[/tex] was taken out of the mixture.
Explanation:
EquilibriumNeither the forward reaction nor the backward reaction would stop when this reversible reaction is at an equilibrium. Rather, the rate of these two reactions would become equal.
Whenever the forward reaction adds one mole of [tex]\rm SO_3\, (g)[/tex] to the system, the backward reaction would have broken down the same amount of [tex]\rm SO_3\, (g)\![/tex]. So is the case for [tex]\rm SO_2\, (g)[/tex] and [tex]\rm O_2\, (g)[/tex].
Therefore, the concentration of each species would stay the same. There would be no macroscopic change to the mixture when it is at an an equilibrium.
Collision TheoryIn the collision theory, an elementary reaction between two reactants particles takes place whenever two reactant particles collide with the correct orientation and a sufficient amount of energy.
Assume that [tex]\rm SO_2\, (g)[/tex] and [tex]\rm O_2\, (g)[/tex] molecules are the two particles that collide in the forward reaction. Because the collision has to be sufficiently energetic to yield [tex]\rm SO_3\, (g)[/tex], only a fraction of the reactions will be fruitful.
Assume that [tex]\rm O_2\, (g)[/tex] molecules were taken out while keeping the temperature of the mixture stays unchanged. The likelihood that a collision would be fruitful should stay mostly the same.
Because fewer [tex]\!\rm O_2\, (g)[/tex] molecules would be present in the mixture, there would be fewer collisions (fruitful or not) between [tex]\rm SO_2\, (g)[/tex] and [tex]\rm O_2\, (g)\![/tex] molecules in unit time. Even if the percentage of fruitful collisions stays the same, there would fewer fruitful collisions in unit time. It would thus appear that the forward reaction has become slower.
Equilibrium after ChangeThe backward reaction rate is likely going to stay the same right after [tex]\rm O_2\, (g)[/tex] was taken out of the mixture without changing the temperature or pressure.
The forward and backward reaction rates used to be the same. However, right after the change, the forward reaction would become slower while the backward reaction would proceed at the same rate. Thus, the forward reaction would become slower than the backward reaction in response to the change.
Therefore, this reaction would not be at equilibrium immediately after the change.
As more and more [tex]\rm SO_3\, (g)[/tex] gets converted to [tex]\rm SO_2\, (g)[/tex] and [tex]\rm O_2\, (g)[/tex], the backward reaction would slow down while the forward reaction would pick up speed. The mixture would once again achieve equilibrium when the two reaction rates become equal again.
which is the limiting reactant when 5.00g of H2 and 10.00g of O2 react and form water?
Explanation:
The reaction expression is given as:
2H₂ + O₂ → 2H₂O
The limiting reactant is the reactant in short short supply in the given reaction.
To find the limiting reactant we use the number of moles.
Mass of H₂ = 5g
Mass of O₂ = 10g
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of H₂ = 2(1) = 2g/mol
Molar mass of O₂ = 2(16) = 32g/mol
Number of moles H₂ = [tex]\frac{2}{5}[/tex] = 0.4mole
Number of moles O₂ = [tex]\frac{10}{32}[/tex] = 0.3mole
From the balanced reaction equation:
2 mole of H₂ reacts with 1 mole of O₂
0.4 mole of H₂ reacts with 0.2 mole of O₂
But we are given 0.3 moles of O₂, so the limiting reactant is H₂ because oxygen gas is in excess
The limiting reactant when 5.00g of H₂ and 10.00g of O₂ react is Oxygen (O₂)
StoichiometryFrom the question,
We are to determine the limiting reactant
First, we will write the balanced chemical equation for the reaction
The balanced chemical equation for the reaction is
2H₂ + O₂ → 2H₂O
This means 2 moles of H₂ reacts with 1 mole of O₂ to produce 2 moles of H₂O
Now, we will determine the number of moles of each reactant present
For H₂Mass = 5.00 g
Molar mass = 2.0 g/mol
Using the formula,
[tex]Number\ of \ moles = \frac{Mass}{Molar\ mass}[/tex]
Number of moles of H₂ = [tex]\frac{5.00}{2.0}[/tex]
Number of moles of H₂ = 2.50 moles
For O₂Mass = 10.00 g
Molar mass = 32.0 g/mol
Then,
Number of moles of O₂ = [tex]\frac{10.00}{32.0}[/tex]
Number of moles of O₂ = 0.3125 mole
Now,
Since 2 moles of H₂ reacts with 1 mole of O₂
Then,
0.625 moles of H₂ reacts with 0.3125 mole of O₂
This means part of the H₂ reacts with all of the O₂. Since all the O₂ reacted, then O₂ is the limiting reactant.
Hence, the limiting reactant when 5.00g of H₂ and 10.00g of O₂ react is Oxygen (O₂).
Learn more on Stoichiometry here: https://brainly.com/question/17199947
How much voltage does 4 oranges produce?
Answer:
For generating electricity, there must be a power source present and a total circuit. In order to generate electricity from citcrus fruit circuit, it is necessary to have materials like wire, a small bulb, lemon fruit, and two metal elements. The power source in this circuit is the lemon fruit. The metals that are taken here in this experiment are zinc and copper.
Explanation:
g Which of the following describe chemical properties of hydrogen gas (H2)? At room temperature its density is less than any other gas. It reacts vigorously with oxygen to form water. Liquefied H2 boils at a very low temperature (-253oC). Both b and c are chemical properties.
Answer: It reacts vigorously with oxygen to form water.
Explanation:
Physical property is defined as the property of a substance which becomes evident during physical changes.
Example: At room temperature its density is less than any other gas.
Liquefied [tex]H_2[/tex] boils at a very low temperature [tex](-253^oC)[/tex]
Chemical property is defined as the property of a substance which becomes evident during chemical changes. These properties are defined when a substance undergo changes in bonding of atoms.
Example: It reacts vigorously with oxygen to form water.
Which environmental factor might positively impact a plant's traits
Answer:
light, temperature, water, humidity, and nutrition.
how can you tell when a solid substace dissolves in water and does not react
Answer:
because it starts to fall apart and it eventually just disappears like for example putting a bleach tablet it water it will take day to desolve but it desolves any way though.
At what temperature does 1.00 atm of He gas have the same density as 1.00 atm?
Answer:
The answer is "[tex]2.73 \times 10^3 \ K[/tex] ".
Explanation:
Please find the complete question in the attachment.
The Formula for Ideal gas:
[tex]\to PV = nRT \\\\[/tex]
[tex]= ( \frac{m}{M})RT[/tex]
[tex]\to Density\ \rho = \frac{m}{V} = \frac{PM}{RT}[/tex]
[tex]\to P= pressure\\\\\to V = volume\\\\ \to n = moles\ of \ gas \\\\\to R = molar \ gas \ constant\\\\ \to T = temperature\\\\ \to m = mass \\\\ \to M = molar \ mass[/tex]
[tex]\to P(Ar) = P(He) = 1.00 atm\\\\\to T(Ar) = ?\\\\ T(He) = 273.2 \ K\\\\\to M(Ar) = 39.948 \ \frac{g}{mol}\\\\ \to M(He) = 4.0026 \ \frac{g}{mol}\\\\\to \rho(Ar) = \rho(He)\\\\\bold{Formula: } \\\\ \to \frac{P(Ar)M(Ar)}{RT(Ar)} = \frac{P(He)M(He)}{RT(He)}\\\\\to \frac{1.00 \times 39.948}{(0.08206 \times T(Ar))} = \frac{1.00 \times 4.0026}{(0.08206 \times 273.2)}\\\\ \to T(Ar) = 2.73 \times 10^3 \ K[/tex]
Calculate the temperature, in K, of 2.20 moles of gas occupying 4.10 L at 2.82 atm.
Answer:
64 k
Explanation:
To figure this out you need to start with the ideal gas equation:
P
⋅
V
=
n
⋅
R
⋅
T
You have P (3.30 atm), V (3.5 l), n (2.20 moles) and you can look up the gas constant, R (0.082057 (latm)/(molK)).
We simply rearrange the ideal gas equation to get T by itself:
T
=
P
⋅
V
n
⋅
R
Then simply plug in the values you were given, making sure that the units are in liters, atmospheres, and moles (which they are, in this case):
T
=
3.30
atm
⋅
3.5
l
2.20
moles
⋅
0.082057
(l*atm)/(mol*K)
=
63.9799
K
Since volume was only given to 2 significant figures, we can only report 2 significant figures for our answer:
64 K.
Which of the following configurations CANNOT be magnetic?
Answer:d8
Explanation:
Help needed urgently
Answer:
Empirical formula = CH3O
Molecular formula = C2H6O2
von Answe
2076 Set B Q.No. 23 Are all standard solutions, primary
standard solutions or not? Give reason. 1 g of a divalent metal
was dissolved in 25 mL of 2N H2SO4 (f = 1.01). The excess
acid required 15.1mL of 1N NaOH (f = 0.8) for complete
neutralization. Find the atomic weight of the metal
. [1 +4]
Ans: Atomic weight = 52.05 amu
go5 gram of a divalent metal
Answer:
i have no clue
Explanation:
i have no clue
How does the composition of the object to figure a differ from the objects shown in figure be name the object
Answer:
A is a Comet, B is an asteroid
Explanation:
:X
All matter basically looks the same. Is this statement true or false?
Answer
false
Explanation:
sorry I tbought i put false I hope I helped ....
The answer is false! All matters do not look the same, even if it had a visible look the answer would be false!
Why is the answer false?
There is lots of matters, Like liquids:
(Water, Juice, Milk, etc.)
All Water, Juice, & Milk looks different, Maybe SOME look the same, but the question is saying "All", Most of all questions is wrong.
Therefore the answer is false!
Learn more about matter on www.Bing/LearnMore/Subject="Matter%20Learning"/Search.com
Need more of my help? Put #AJQ in your questions and I will come fast!
The diagram below shows a food web in a woodland.
A food web diagram showing cornstalks with two arrows pointing away from it. One of the arrows points to the letter X and the other arrow points to a grasshopper. There are two arrows pointing away from the grasshopper. One is pointing to a baby sparrow and the other to the letter Y. There is an arrow pointing away from the baby sparrow to a snake and an arrow pointing away from the letter X to the snake.
If a certain organism is a secondary consumer, what best explains its position in the food web? (3 points)
a
X, because organism X feeds on producers
b
Y, because organism Y feeds on producers
c
X, because organism X feeds on a carnivore
d
Y, because organism Y feeds on a herbivore
Explanation:
Options A and B have wrong reasons because to feed on producers means that it is a primary consumer.
Option C is wrong because organism X only feeds on cornstalks.
Organism Y does feed on the grasshopper, which feeds on the cornstalks. It is a secondary consumer.
Hence Option D is correct.
Which of the following BEST describes a way in which water moves in the water cycle?
A. Water falls from the sky as rain. It stays where it falls until it evaporates
B. Water falls from the sky as snow. As the snow melts, the water runs up to Earth's mountains.
C. Water falls from the sky as rain. The water then flows downhill
D. Water falls from the sky as hail. The hail is eventually buried in the ground
Answer: Its A or D
wish i had an actual answer sorry..
The correct answer should be A
Which are ways to ensure that temperature readings are accurate? Check all that apply. -shaking the thermometer before use
-using the thermometer as a stirring rod
-making sure the liquid inside the thermometer is at eye level when taking the temperature
- making sure the bulb of the thermometer does not touch the bottom of the beaker or the ice when taking the temperature
-using the Celsius scale instead of the Fahrenheit scale when taking temperature readings
Answer: making sure the liquid inside the thermometer is at eye level when taking the temperature.
making sure the bulb of the thermometer does not touch the bottom of the beaker or the ice when taking the temperature
Explanation:
A thermometer is a device that's used to know the temperature of individuals. In order to ensure the accuracy of the readings in a thermometer, it is vital to making sure the liquid inside the thermometer is at eye level when taking the temperature.
Also, one should make sure the bulb of the thermometer does not touch the bottom of the beaker or the ice when taking the temperature.
The thermometer should not be used as a stirring rod. One should not shake it or play with it. Also, using either Celcius or Fahrenheit doesn't really matter.
Not every practice is accepted in temperature reading and these are the practices that apply are
Making sure the liquid inside the thermometer is at eye level when taking the temperature.Making sure the bulb of the thermometer does not touch the bottom of the beaker or the ice when taking the temperature.Option C and Option D are correct Ways to ensure that temperature readings are accurate while using a thermometerGenerally, The essential precautions that need to be taken when the using of thermometer encompass the following:
Do not use a thermometer as a stirring instrument,
Make positive that the liquid interior the thermometer is at eye stage when taking the temperature reading
Do not swing or shake down a thermometer reading
Therefore,the ways that apply are
Making sure the liquid inside the thermometer is at eye level when taking the temperature.
Making sure the bulb of the thermometer does not touch the bottom of the beaker or the ice when taking the temperature.
Option C and D are correct
For more information on Temperature
https://brainly.com/question/13439286
Which represents the ionization of a strong electrolyte?
Answer:
Explanation:
Strong electrolytes completely ionize when dissolved, and no neutral molecules are formed in solution. Since NaCl is an ionic solid (s), which consists of cations Na+ and anions Cl−, no molecules of NaCl are present in NaCl solid or NaCl solution. The ionization is said to be complete.
Answer:
K3PO4(s) ----- 3K+(aq) + PO43–(aq)
Explanation:
edge 2021
How do you know the number of valence electrons for those elements?
Answer:
For neutral atoms, the number of valence electrons is equal to the atom's main group number. The main group number for an element can be found from its column on the periodic table. For example, carbon is in group 4 and has 4 valence electrons. Oxygen is in group 6 and has 6 valence electrons.
Explanation:
hope this help
The force that gravity exerts on an object is
Question 7 options:
It's Acceleration
It's Weight
It's Mass
Constant
Answer:
gravity exerts on it's mass brother
How many milliliters of an aqueous solution of 0.193 M potassium carbonate is needed to
obtain 7.90 grams of the salt?
Answer:
295 mL
Explanation:
Given data:
Volume needed = ?
Molarity of solution = 0.193 M
Mass of salt = 7.90 g
Solution:
Molarity = number of moles of solute / volume in L
Number of moles of salt = mass/molar mass
Number of moles of salt = 7.90 g/ 138.205 g/mol
Number of moles = 0.057 mol
Volume needed:
Molarity = number of moles / volume in L
0.193 M = 0.057 mol / volume in L
Volume in L = 0.057 mol / 0.193 M
Volume in L = 0.295 L
L into mL
0.295 L × 1000 mL/1L
295 mL
The rate of consumption of B in the reaction A + 3 B → C + 2 D is 2.7 mol dm−3 s−1. State the reaction rate, and the rates of formation or consumption of A, C, and D.
Answer:
[tex]\frac{1}{-1} \frac{d[A]}{dt} =\frac{1}{-3} \frac{d[B]}{dt}=\frac{1}{1} \frac{d[C]}{dt}=\frac{1}{2} \frac{d[D]}{dt}[/tex]
[tex]\frac{d[A]}{dt} =-0.9\frac{mol}{dm^3*s} \\\\ \frac{d[C]}{dt} =0.9\frac{mol}{dm^3*s}\\\\ \frac{d[D]}{dt} =1.8\frac{mol}{dm^3*s}[/tex]
Explanation:
Hello!
In this case, since the reaction rate for all the species are written by considering how they change and the coefficients they have in the reaction, for A, B, C and D we can write:
[tex]\frac{1}{-1} \frac{d[A]}{dt} =\frac{1}{-3} \frac{d[B]}{dt}=\frac{1}{1} \frac{d[C]}{dt}=\frac{1}{2} \frac{d[D]}{dt}[/tex]
Whereas the numeric denominators stand for the coefficients balancing the reaction. In such a way, by using the rate of consumption of B, we can compute the rate of consumption of A and the rates of formation of both C and D as follows:
[tex]\frac{d[A]}{dt} =\frac{-1}{-3} \frac{d[B]}{dt}=\frac{1}{3}*-2.7\frac{mol}{dm^3*s} \\\\ \frac{d[A]}{dt} =-0.9\frac{mol}{dm^3*s} \\\\\\ \frac{d[C]}{dt} =\frac{1}{-3} \frac{d[B]}{dt}=\frac{1}{-3}*-2.7\frac{mol}{dm^3*s} \\\\ \frac{d[C]}{dt} =0.9\frac{mol}{dm^3*s}\\\\\\ \frac{d[D]}{dt} =\frac{2}{-3} \frac{d[B]}{dt}=\frac{2}{-3}*-2.7\frac{mol}{dm^3*s} \\\\ \frac{d[D]}{dt} =1.8\frac{mol}{dm^3*s}[/tex]
Whereas the rates of consumption are negative and the rates of formation positive.
Best regards!
12. Balance the following redox reaction by ion - electron method -
Cr07- (aq) + SO, (g) -- Crd+ (aq) + S0x2 (aq) (acidic medium)
(
hope this will help you mate! :)
shadow
water ------- is water--------
Answer:
Water is water.
Explanation:
Water is a colorless and odorless substance found all over Earth. Water is made up of billions of molecules. ... Water on our planet flows as liquid in rivers, streams, and oceans; is solid as ice at the North and South Poles; and is gas (vapor) in the atmosphere. Water is also underground and inside plants and animals